NT Unit V Part II - Network Functions PDF
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Sri Chandrasekharendra Saraswathi Viswa Mahavidyalaya
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Summary
This document includes solved questions and answers on network functions, including driving point functions, transfer functions, voltage gain, current gain, poles, and zeroes. It also covers topics like driving point impedance and transfer admittance, along with sample problems and diagrams.
Full Transcript
## SOLVED QUESTION BANK **Q. 5.1.** Explain the following terms: * Driving point function * Transfer function * Voltage gain * Current gain * Poles & zeroes of Network function **Ans:** * **Driving point function:** In a two-port network (see figure below), a driving point function relat...
## SOLVED QUESTION BANK **Q. 5.1.** Explain the following terms: * Driving point function * Transfer function * Voltage gain * Current gain * Poles & zeroes of Network function **Ans:** * **Driving point function:** In a two-port network (see figure below), a driving point function relates the voltages and currents at the same port. For example, $Z_{11} = \frac{V_1}{I_1}$ is the driving point impedance at port 1. * $Z_{22} = \frac{V_2}{I_2}$ is the driving point impedance at port 2 * $Y_{11} = \frac{I_1}{V_1}$ is the driving point admittance at port 1 * $Y_{22} = \frac{I_2}{V_2}$ is the driving point admittance at port 2 * **Transfer Function:** The transfer function is the ratio of the Laplace transform of the output voltage to the Laplace transform of the input voltage. For a two-port network, the transfer function is: > $T(S) = \frac{V_2(S)}{V_1(S)}$ * **Voltage Gain:** The voltage gain is the ratio of the output voltage to the input voltage. For a two-port network, the voltage gain is: > $\frac{V_2}{V_1}$ * **Current Gain:** The current gain is the ratio of the output current to the input current. For a two-port network, the current gain is: > $\frac{I_2}{I_1}$ * **Poles & Zeroes of Network Function:** If a network function or transfer function is given as: > $N(S) = T(S) = K \frac{(S+Z_1)(S+Z_2)---(S+Z_n)}{(S+P_1)(S+P_2)---(S+P_n)}$ where K is constant. * **Poles:** The values of 'S' at which the transfer function T(S) becomes infinite are called as poles of T(S). > $S=-P_1, S=-P_2, ... , S=-P_n$ * **Zeroes:** Values of 'S' at which the transfer function T(S) becomes zero are called as zeroes of T(S). > $S=-Z_1, S=-Z_2, ... , S=-Z_n$ **Figure:** Two-port network ``` ____ ____ | | | | _ | 1 |______| 2 | _ | |___|______|___| | _ | 1' |______| 2' | _ | | | | |____|______|____| V1 V2 ``` ## Network Functions **Q. 5.2.** Define the following with respect to Network functions: * Poles * Zeroes * Driving point impedance * Transfer admittance **Ans:** * **Driving Point Impedance:** The ratio of transform voltage to current. > $Z_{11}=\frac{V_1}{I_1}$ and $Z_{22}=\frac{V_2}{I_2}$ * **Transfer Admittance:** The ratio of transform current at the output port to the transform voltage at the input port. > $Y_{12} = \frac{I_2}{V_1}$ and $Y_{21} = \frac{I_1}{V_2}$ **Q. 5.3.** For the network in the figure (see below), find the transfer admittance $Y_{12}(S) = \frac{I_2(S)}{V_1(S)}$ and plot the poles and zeroes of $Y_{12}(S)$. **Ans:** <start_of_image> схемы в области S: **Figure:** Two-port network for Q. 5.3 ``` ____ ____ | | | | _ | 1 |______| 2 | _ | |___|______|___| | _ | 1' |______| 2' | _ | | | | |____|______|____| V1 V2 ``` **Figure:** Two-port network in S-domain ``` ____ ____ | | | | _ | 1 |______| 2 | _ | |___|______|___| | _ | 1' |______| 2' | _ | | | | |____|______|____| I1(s) I2(s) V1(s) V2(s) ``` **Q. 5.4.** For a given network function $I(S)$, draw the pole-zero diagram and hence obtain the time domain response. Verify the result analytically. > $I(S) = \frac{3S}{(S+1)(S+3)}$ **Ans:** **Pole-zero diagram:** **Q. 5.5.** Find the voltage ratio and transfer admittance function of the ladder network shown (see below). **Figure:** Ladder Network ``` + 1H | | ------- | | | | 1F | | | | | +---- | |-----+ | | | | 1F | | 1F | | | | +----- | |-----+ | | | | 1H | | + V1 V2 ``` **Figure:** Ladder Network in S-domain ``` + 1/S | | ------- | | | | 1/S | | | | | +---- | |-----+ | | | | 1/S | | 1/S | | | | +----- | |-----+ | | | | 1/S | | + I1(s) I4(s) V1(s) V4(s) ``` **Ans:** **Q. 5.6.** Explain how a time response can be obtained from a pole-zero plot. Consider a transform of current: > $I(S) = K \frac{(S+Z_1)(S+Z_2)---(S+Z_n)}{(S+P_1)(S+P_2)---(S+P_n)}$ **Ans:** **Q. 5.7.** Find the time domain response of the current transform, given by $I(s) = \frac{3S}{(S+2)(S^2+2S+2)} $ by locating the poles and zeroes in the S-plane. **Ans:** **Q. 5.8.** * Let $f_1(t) = 2u(t)$ and $f_2(t) = e^{-3t}u(t)$. Determine the convolution between $f_1(t)$ and $f_2(t)$. * A function in the Laplace domain is given by $F(S) = \frac{2(S+4)}{(S+3)(S+8)}$. Find the initial and the final value theorem and verify the same by finding $f(t)$. **Ans:** **Q. 5.9.** Obtain the current transfer ratio $\frac{I_2(S)}{I_1(S)}$ for the network in the figure (see below): **Figure:** Network for Q. 5.9 ``` + | | ------- | | | C_1 | | | +---- | |-----+ | | | | R | | ------- | | | C_2 | | | +---- |----|-----+ | | + I1 I2 ``` **Ans:** **Q. 5.10.** The driving point admittance of a network is given by: > $Y(S) = \frac{10S}{s^2 + 10S + 250}$ If a unit impulse voltage is applied to the network, find the current $i(t)$ entering the network using a pole-zero diagram, or the pole-zero plot. **Ans:** **Q. 5.11.** Plot the pole and zeroes in the S-plane for the following network function $F(S) = \frac{S^2+4S+3}{S^2+2S}$. Also, find $f(t)$. **Ans:** **Q. 5.12.** The network in the figure (see below) is terminated at port 2 by a resistance of 1 Ω. Find the transform admittance $Y_{12} = \frac{I_2(S)}{V_1(S)}$ for this terminated network. **Figure:** Two-port network for Q. 5.12 ``` + | | ------- | | | 2H | | | +---- | |-----+ | | | | 1Ω | | | ------- | | | 1H | | | +---- |----|-----+ | | + I1 V1 I2 V2 ``` **Ans:** **Q. 5.13.** Find the transform impedance of the network shown (see below) **Figure:** Network for Q. 5.13 ``` + | | ------- |-----+ | | | 2 Ω | | | | | +------ | |-----+ | | | | | | ------- |-----+ | | | 1/S | | | +------- | |------+ | | | | | | ------- |-----+ | | | 1 Ω | | | | | +------- | |------+ | | | | | + Z ``` **Ans:** **Q. 5.14.** A network function N(S) has the following data: * Zero at origin * A simple pole at -1 * Pairs of complex conjugate zero at -4+j1 & poles at -1+j1 * N(S) = 20 at infinite frequency. Determine network function N(S) **Ans:** **Q. 5.15.** For the given network function, plot poles and zeroes in the S-plane and, hence, obtain the time domain response. > $I(S) = \frac{3S}{(S+1)(S+4)}$ **Ans:** **Q. 5.16.** Show that the voltage transfer function of the following network (see below) has imaginary zeroes given by $S = \pm \frac{j}{CR}$. **Figure:** Network for Q. 5.16 ``` + | | ------- |-----+ | | | R | | | | | +------ | |-----+ | | | | | | ------- |-----+ | | | C | | | | | +------- | |------+ | | | | | | ------- |-----+ | | | R | | | | | +------- | |------+ | | | | | | ------- |-----+ | | | C | | | | | +------- | |------+ | | | | | + V1 V2 ``` **Ans:** **Q. 5.17.** Draw the pole-zero diagram for the given network function and, hence, obtain $V(t)$. > $V(S) = \frac{4(S+2)}{(S+1)(S+3)}$ **Ans:** **Q. 5.18.** For the ladder network shown in the figure (see below), find the: * Driving point input impedance $Z_{11}$ * Transfer impedance $Z_{12}$ * Voltage-ratio transfer function $G_{12}$ Assume $I_2 = 0$ **Figure:** Network for Q. 5.18 ``` + | | ------- | | | 1H | | | +---- | |-----+ | | | | 1F | | | ------- | | | 1H | | | +---- |----|-----+ | | + I1 V1 I2 = 0 V2 ``` **Ans:** **Q. 5.19.** Draw the pole-zero diagram for the given network function $I(S)$ and, hence, obtain i(t) using the pole-zero diagram. > $I(S) = \frac{20S}{(S+5)(S+2)}$ **Ans:** **Q. 5.20.** Obtain the pole-zero diagram of the given function. > $I(S) = \frac{2S}{(S+1)(S^2+2S+4)}$ **Ans:** **Q. 5.21.** Find the time domain response of the current transform, given by $I(s) = \frac{5S}{(S+1)(s^2+2S+2)} $ by locating the poles and zeroes in the S-plane. **Ans:** **Q. 5.22.** The given network is terminated at port 2 by a resistance of 1 Ω. Find the transform admittance $Y_{12} = \frac{I_2(S)}{V_1(S)}$ for this terminated network. **Figure:** Network for Q. 5.22 ``` + | | ------- | | | | 2 Ω | | | | | +---- | |-----+ | | | | 1F | | 1 Ω | | | | +----- | |-----+ | | | | 1 | | + I1(s) I2(s) V1(s) V2(s) ``` **Ans:** **Q. 5.23.** State the necessary condition for driving point functions and transfer functions. **Ans:** **Q. 5.24.** Find the voltage transfer function $G_{12}(S)$ for the network shown (see below). **Figure:** Network for Q. 5.24 ``` + | | ------- | | | | 2 Ω | | | | | +---- | |-----+ | | | | 1 Ω | | 1 Ω | | | | +----- | |-----+ | | | | 1 | | + V1 V2 ``` **Ans:** **Q. 5.25.** For a network function given as > $I(S) = \frac{10(S+1)}{(S+5)S^2+6S+ 13}$ Place the poles and zeroes in the S-plane and hence find i(t). **Ans:** **Q. 5.26.** Show that the transfer function of the following function (see below) is: > $F(S) = \frac{1}{S^2+1}coth(\frac{πS}{2})$ **Figure:** Function For Q. 5.26 ``` 1 | | 1 | | | | | | | | +------+ | | | | | | | +------+ 0 P t ``` **Ans:** **Q. 5.27.** For the network shown (see below) find the voltage transfer function $G_{12} = \frac{V_2(S)}{V_1(S)}$. **Figure:** Network for Q. 5.27 ``` + | | ------- | | | | 1 Ω | | | | | +---- | |-----+ | | | | 1F | | 2 Ω | | | | +----- | |-----+ | | | | 2F | | + V1 V2 ``` **Ans:** **Q. 5.28.** Select the function which represents the driving point impedance of a passive network, and justify. > i). $\frac{S^3+5S^2+S+5}{S(S^2+1)} $ > ii). $\frac{15(S^3+2S^2+3S+5)}{4(S^2+6S^3+8S^2+5)}$ **Ans:** **Q. 5.29.** Determine the driving point impedance of the given ladder network. **Figure:** Network for Q. 5.29 ``` + | | ------- | | | | 5F | | | | | +---- | |-----+ | | | | 5F | | 5H | | | | +----- | |-----+ | | | | 5H | | + V1 V2 ``` **Ans:** **Q. 5.30.** For the network shown (see below), find the current transfer ratio $o_{12} = \frac{I_2}{I_1}$. **Figure:** Network for Q. 5.30 ``` + | | ------- | | | 1 Ω | | | +------- | |--------+ | | | | 2 Ω | | | | | +------- | |--------+ | | | | 21 b | | | | | +------- | |--------+ | | | | 2 Ω | | | | | +------- | |--------+ | | | | 1 Ω | | | | | ------- | | | + I1 I2 V1 V2 ``` **Ans:** **Q. 5.31.** Find the voltage transfer function $G_{12}(S) = \frac{V_2(S)}{V_1(S)}$ for the network (see below) **Figure:** Network for Q. 5.31 ``` + | | ------- | | | | 1F | | | | | +---- | |-----+ | | | | 1 Ω | | 1F | | | | +----- | |-----+ | | | | 1 Ω | | + V1 V2 ``` **Ans:** **Q. 5.32.** Find the time domain response by locating the poles and zeroes in the S-plane for the following function: > $I(S) = \frac{3S}{S^2+2S+2}$ **Ans:** **Q. 5.33.** Explain the concept of complex frequency. **Ans:** **Q. 5.34** Find the voltage transfer function $G_{12}(S)$ for the network shown in the figure (see below). **Figure:** Network for Q. 5.34 ``` + | | ------- | | | | 2 Ω | | | | | +---- | |-----+ | | | | 1 Ω | | 1 Ω | | | | +----- | |-----+ | | | | 1 | | + V1 V2 ``` **Ans:** **Q. 5.35.** Draw the pole-zero diagram for the given network function and hence obtain $V(t)$. > $V(S) = \frac{4(S+2)}{(S+1)(S+3)}$ **Ans:** **Q. 5.36.** For the ladder network shown in the figure (see below), find the: * Driving point input impedance $Z_{11}$ * Transfer impedance $Z_{12}$ * Voltage-ratio transfer function $G_{12}$ Assume $I_2 = 0$. **Figure:** Network for Q. 5.36 ``` + | | ------- | | | 1H | | | +---- | |-----+ | | | | 1F | | | ------- | | | 1H | | | +---- |----|-----+ | | + I1 V1 I2 = 0 V2 ``` **Ans:** **Q. 5.37.** Find the voltage transfer ratio $G_{12}(S) = \frac{V_2(S)}{V_1(S)}$ for the network shown (see below). **Figure:** Network for Q. 5.37 ``` + | | ------- | | | | 1F | | | | | +---- | |-----+ | | | | 1 Ω | | 1F | | | | +----- | |-----+ | | | | 1 Ω | | + V1 V2 ``` **Ans:** **Q. 5.38.** Obtain the pole-zero diagram of the given function. > $I(S) = \frac{2S}{(S+1)(S^2+2S+4)}$ **Ans:** **Q. 5.39.** Find the time domain response of the current transform, given by $I(s) = \frac{5S}{(S+1)(s^2+2S+2)} $ by locating the poles and zeroes in the S-plane. **Ans:** **Q. 5.40.** Find the voltage transfer function $G_{12}(S)$ for the network shown in the figure (see below). **Figure:** Network for Q. 5.40 ``` + | | ------- | | | | 2 Ω | | | | | +---- | |-----+ | | | | 1 Ω | | 1 Ω | | | | +----- | |-----+ | | | | 1 | | + V1 V2 ``` **Ans:** **Q. 5.41.** Find the voltage transfer ratio $G_{12}(S) = \frac{V_2(S)}{V_1(S)}$ for the network shown (see below). **Figure:** Network for Q. 5.41 ``` + | | ------- | | | | 1F | | | | | +---- | |-----+ | | | | 1 Ω | | 1F | | | | +----- | |-----+ | | | | 1 Ω | | + V1 V2 ``` **Ans:** **Q. 5.42.** The given network is terminated at port 2 by a resistance of 1 Ω. Find the transform admittance $Y_{12} = \frac{I_2(S)}{V_1(S)}$ for this terminated network. **Figure:** Network for Q. 5.42 ``` + | | ------- | | | | 2 Ω | | | | | +---- | |-----+ | | | | 1F | | 1 Ω | | | | +----- | |-----+ | | | | 1 | | + I1(s) I2(s) V1(s) V2(s) ``` **Ans:** **Q. 5.43.** Explain the concept of complex frequency. **Ans:** **Q. 5.44** Find the voltage transfer function $G_{12}(S)$ for the network shown (see below). **Figure:** Network for Q. 5.44 ``` + | | ------- | | | | 2 Ω | | | | | +---- | |-----+ | | | | 1 Ω | | 1 Ω | | | | +----- | |-----+ | | | | 1 | | + V1 V2 ``` **Ans:** **Q. 5.45** For a network function given as > $I(S) = \frac{10(S+1)}{(S+5)S^2+6S+13}$ Place the poles and zeroes in the S-plane and hence find $i(t)$. **Ans:** **Q. 5.46.** Show that the transfer function of the following function (see below) is: > $F(S) = \frac{1}{S^2+1}coth(\frac{πS}{2})$ **Figure:** Function For Q 5.46 ``` 1 | | 1 | | | | | | | | +------+ | | | | | | | +------+ 0 P t ``` **Ans:** **Q. 5.47.** For the network shown in the figure (see below), find the voltage transfer function $G_{12} = \frac{V_2(S)}{V_1(S)}$. **Figure:** Network for Q. 5.47 ``` + | | ------- | | | | 1 Ω | | | | | +---- | |-----+ | | | | 1F | | 2 Ω | | | | +----- | |-----+ | | | | 2F | | + V1 V2 ``` **Ans:** **Q. 5.48.** Select the function which represents the driving point impedance of a passive network, and justify. > i). $\frac{S^3+5S^2+S+5}{S(S^2+1)} $ > ii). $\frac{15(S^3+2S^2+3S+5)}{4(S^2+6S^3+8S^2+5)}$ **Ans:** **Q. 5.49.** Determine the driving point impedance of the given ladder network. **Figure:** Network for Q 5.49 ``` + | | ------- | | | | 5F | | | | | +---- | |-----+ | | | | 5F | | 5H | | | | +----- | |-----+ | | | | 5H | | + V1 V2 ``` **Ans:** **Q. 5.50.** For the network shown (see below), find the current transfer ratio $o_{12} = \frac{I_2}{I_1}$. **Figure:** Network for Q. 5.50 ``` + | | ------- | | | 2H | | | +---- | |-----+ | | | | 1Ω | | | ------- | | | 1H | | | +---- |----|-----+ | | + I1 V1 I2 V2 ``` **Ans:** **Q. 5.51.** Find the voltage transfer ratio $G_{12}(S) = \frac{V_2(S)}{V_1(S)}$ for the network shown (see below). **Figure:** Network for Q. 5.51 ``` + | | ------- | | | | 1F | | | | | +---- | |-----+ | | | | 1 Ω | | 1F | | | | +----- | |-----+ | | | | 1 Ω | | + V1 V2 ``` **Ans:** **Q. 5.52.** The given network is terminated at port 2 by a resistance of 1 Ω. Find the transform admittance $Y_{12} = \frac{I_2(S)}{V_1(S)}$ for this terminated network. **Figure:** Network for Q. 5.52 ``` + | | ------- | | | | 2 Ω | | | | | +---- | |-----+ | | | | 1F | | 1 Ω | | | | +----- | |-----+ | | | | 1 | | + I1(s) I2(s) V1(s) V2(s) ``` **Ans:** **Q. 5.53.** Find the voltage transfer ratio $G_{12}(S) = \frac{V_2(S)}{V_1(S)}$ for the network shown (see below). **Figure:** Network for Q. 5.53 ``` + | | ------- | | | | 1F | | | | | +---- | |-----+ | | | | 1 Ω | | 1F | | | | +----- | |-----+ | | | | 1 Ω | | + V1 V2 ``` **Ans:** **Q. 5.54.** Find the time domain response by locating the poles and zeroes in the S-plane for the following function: > $I(S) = \frac{3S}{S^2+2S+2}$ **Ans:**