MTS 102 +++.pdf

NOT FOR SALE MTS 102 ELEMENTARY MATHEMATICS II REVISION QUESTIONS BY COMR. AJELE IFEKITAN FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE Question 1 : Evaluate the limitlimx→−∞x2−5t−92×4+3×3 A. 4 B. 0 C. 2 D....

NOT FOR SALE MTS 102 ELEMENTARY MATHEMATICS II REVISION QUESTIONS BY COMR. AJELE IFEKITAN FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE Question 1 : Evaluate the limitlimx→−∞x2−5t−92×4+3×3 A. 4 B. 0 C. 2 D. 1 Answer to question 1 is A. 4 Question 2 : Evaluate the limitlimx→∞6e4x−e−2x8e4x−e2x+3e−x A.35 B.14 C.34 D.12 Answer to question 2 is C. 3/4 Question 3 : Evaluate the limitlimh→02(−3+h)2−18h A. 6 B. 14 C. 12 D. 8 Answer to question 3 is C. 12 Question 4 : Find the derivative f(x)=2×2−16x+35 by using first principle A.x+16 B.2x−8 C.3x−5 D.4x−16 Answer to question 4 is D.4x−16 Question 5 : Find the derivative f(x)=2×2−16x+35 by using first principle A.3x−5 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE B.4x−16 C.x+16 D.2x−8 Answer to question 5 is B.4x−16 Question 6 : Evaluate the limitlimt→4t−√(3+4)4−t A.−58 B.−38 C.34 D.−18 Answer to question 6 is B. -3/8 Question 7 : Differentiate y=3√(x2)(2x−x2) with respect to x A.y=5×233+4×533 B.y=5×233−4×533 C.y=10×233−8×533 D.y=10×233+8×533 Answer to question 5 is B.y=5×233−4×533 Question 8 : Evaluate the limitlimt→4t−√(3+4)4−t A.34 B.−18 C.−38 D.−58 Answer to question 8 is C. -3/8 Question 9 : Given y(x)=x4−4×3+3×2−5x, evaluated4ydx4 A. 22 B. 42 C. 30 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE D. 24 Answer to question 9 is D. 24 Question 10 : Differentiate with respect to x:f(x)=(ax3+bx) A.ax2+b B.3a−b C.3ax2+b D.3×2+1 Answer to question 10 is C.3ax2+b Question 11 : Evaluate the limitlimx→∞2×4−x2+8x−5×4+7 A.13 B.34 C.12 D.23 Answer to question 10 is C. 1/2 Question 12 : Differentiate y=3√(x2)(2x−x2) with respect to x A.y=5×233−4×533 B.y=5×233+4×533 C.y=10×233−8×533 D.y=10×233+8×533 Answer to question 12 is B.y=5×233+4×533 Question 13 : Given2x5+x2−5t2, find dydx by using the first principle A.6t2+10t−3 B. c−t−2+8t−3 C.t2+5t−3 D.6t+7t−3 Answer to question 12 is A.6t2+10t−3 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE Question 14 : Evaluate the limitlimh→02(−3+h)2−18h A. 8 B. 14 C. 12 D. 6 Answer to question 12 is C. 12 Question 15 : Evaluate the limitlimx→∞6e4x−e−2x8e4x−e2x+3e−x A.35 B.34 C.12 D.14 Answer to question 15 is C. 1/2 Question 16 : Giveny(x)=x4−4×3+3×2−5x, evaluated4ydx4 A. 24 B. 22 C. 42 D. 30 Answer to question 16 is A. 24 Question 17 : Given2x5+x2−5t22x5+x2−5t2, finddydx by using the first principle A.6t+7t−3 B.6t2+10t−3 C.t2+5t−3 D. c−t−2+8t−3 Answer to question 17 is B.6t2+10t−3 Question 18 : Differentiate with respect to x:f(x)=(ax3+bx) A.ax2+b FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE B.3×2+1 C.3ax2+b D.3a−b Answer to question 18 C.3ax2+b Question 19 : Evaluate the limitlimx→∞2×4−x2+8x−5×4+7 A.34 B.23 C.13 D.12 Answer to question 18 D. 1/2 Question 20 : Evaluate the limitlimx→−∞x2−5t−92×4+3×3 A. 4 B. 0 C. 1 D. 2 Answer to question 20 A. 4 IFEKITAN CARES...Information is light, I chose to carry it FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE Question 1 : Integrate ∫(x3+3×2+2x+4) A.x42−x3+x2+4x+c B.6×4−3×2+c C.x44+x3+x2+4x+c D.3×44+2×3+x+c Question 2 : Given f(x) =(7×4−5×3) , evaluate df(x)dx A.28×3−15×2 B.2×3−15×2 C.28×2−15×2 D.7×4−5×3 Answer to question 2 is A. A.28×3−15×2 Question 3 : Evaluate ∫e4xdx A.ex+c B.13ex+c C.14e4x+c D.3ex3+c Answer to question 3. Is A. ex+c Question 4 : Find ∫sec3xtanxdx A.cos3x2+c B.sin2x+c C.cos2x+c D.sec3x3+c Answer to question 4. Is A. ex Question 5 : Find the volume of a sphere generated by a semicircley=√(r2−x2) FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE revolving around the x-axis A.4πr32 B.4πr33 C.−π−r32 D.πr34 Question 6 : Find the integral with respect to x ∫cosxsinxdx A.cos2x2+c B.sinx C.sin2x2+c D.sin2x+c Question 7 : Find the ∫tan3xsec3xdx A.sec2x+1 B.cot2x+1 C.sec2x D.tan2x+1 Question 8 : Integrate with respect to x : ∫3−1x√7+x2dx A.4−2√2 B.2√2 C.√2 D.4√2 Question 9 : Evaluate ∫3ex+5cos(x)−10sec2(x)dx A.2ex−x−10tanx+c B.3e2+5sinx−10tanx+c C.3ex+cosx−10tanx+c D.3ex+5sinx−10secx+c Question 10 : Evaluate∫x2e3xdx FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE A.e3x3(x2−2×3+29)+c B.ex3(x2+2×3−25)+c C.e2x3(x3−x4+29)+c D.−e3x3(x2+2×3−29)+c Question 11 : Evaluate∫x+1×2−3x+2dx A.3ln(x−2)−2ln(x−1)+c B.3ln(x−2)+2ln(x+1)+c C.3ln(x+2)−2ln(x+1)+c D.−3ln(x−2)−2ln(x−1)+c Question 12 : Integrate with respect to x : ∫2−1×2(x3+4)2dx A. 6 B.12 C. 12 D.512 Question 13 : Evaluate∫2−1y2+y−2dy A.716 B.316 C.516 D.1716 Question 14 : Evaluate∫(3x−2)6dx A.(3x+2)72+c B.(3x−2)721+c C.(3x+2)721+c D.3(3x−2)72+c Question 15 : Evalute ∫x2(3−10×3)dx A.115(3−20×3)5)+c FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE B.110(1−10×2)5)+c C.1150(3−10×3)5)+c D.1100(3−2×3)5)+c Question 16 : Find∫xcosax2dx with respect to x A.12asinax2+c B.sec2x+1 C.sin2x+c D.cos3x+c Question 17 : Determine∫x2+1(x+2)3 A.ln(x+2)+4x+2−52(x+3)2+c B.ln(x−2)+4x−2−52(x+3)2+c C.ln(x+2)−4x+2−52(x+3)2+c D.−ln(x+2)−4x+2−52(x+3)2+c Question 18 : Integrate with respect to x : ∫41x+1√xdx A. -20 B.203 C.320 D. 20 Question 19 : Evaluate∫cos(6x+4)dx A.sin(6x+4)6+c B.tan(6x+4)6+c C.cos(6x+4)6+c D.sec(6x+4)6+c Question 20 : Evaluate∫xe6xdx A.x6e6x−1136e6x+c B.x3e6x+116e6x+c FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE C.x6e6x+1136e6x+c D.−x6e6x+1136e6x+c IFEKITAN CARES...Information is light, I chose to carry it FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE Question 1 : Evaluate the limitlimx→−∞x2−5t−92×4+3×3 A. 4 B. 0 C. 2 D. 1 Answer to question 1 is A. 4 Question 2 : Evaluate the limitlimx→∞6e4x−e−2x8e4x−e2x+3e−x A.35 B.14 C.34 D.12 Answer to question 2 is C. 3/4 Question 3 : Evaluate the limitlimh→02(−3+h)2−18h A. 6 B. 14 C. 12 D. 8 Answer to question 3 is C. 12 Question 4 : Find the derivative f(x)=2×2−16x+35 by using first principle A.x+16 B.2x−8 C.3x−5 D.4x−16 Answer to question 4 is D.4x−16 Question 5 : Find the derivative f(x)=2×2−16x+35 by using first principle A.3x−5 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE B.4x−16 C.x+16 D.2x−8 Answer to question 5 is B.4x−16 Question 6 : Evaluate the limitlimt→4t−√(3+4)4−t A.−58 B.−38 C.34 D.−18 Answer to question 6 is B. -3/8 Question 7 : Differentiate y=3√(x2)(2x−x2) with respect to x A.y=5×233+4×533 B.y=5×233−4×533 C.y=10×233−8×533 D.y=10×233+8×533 Answer to question 5 is B.y=5×233−4×533 Question 8 : Evaluate the limitlimt→4t−√(3+4)4−t A.34 B.−18 C.−38 D.−58 Answer to question 8 is C. -3/8 Question 9 : Given y(x)=x4−4×3+3×2−5x, evaluated4ydx4 A. 22 B. 42 C. 30 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE D. 24 Answer to question 9 is D. 24 Question 10 : Differentiate with respect to x:f(x)=(ax3+bx) A.ax2+b B.3a−b C.3ax2+b D.3×2+1 Answer to question 10 is C.3ax2+b Question 11 : Evaluate the limitlimx→∞2×4−x2+8x−5×4+7 A.13 B.34 C.12 D.23 Answer to question 10 is C. 1/2 Question 12 : Differentiate y=3√(x2)(2x−x2) with respect to x A.y=5×233−4×533 B.y=5×233+4×533 C.y=10×233−8×533 D.y=10×233+8×533 Answer to question 12 is B.y=5×233+4×533 Question 13 : Given2x5+x2−5t2, find dydx by using the first principle A.6t2+10t−3 B. c−t−2+8t−3 C.t2+5t−3 D.6t+7t−3 Answer to question 12 is A.6t2+10t−3 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE Question 14 : Evaluate the limitlimh→02(−3+h)2−18h A. 8 B. 14 C. 12 D. 6 Answer to question 12 is C. 12 Question 15 : Evaluate the limitlimx→∞6e4x−e−2x8e4x−e2x+3e−x A.35 B.34 C.12 D.14 Answer to question 15 is C. 1/2 Question 16 : Giveny(x)=x4−4×3+3×2−5x, evaluated4ydx4 A. 24 B. 22 C. 42 D. 30 Answer to question 16 is A. 24 Question 17 : Given2x5+x2−5t22x5+x2−5t2, finddydx by using the first principle A.6t+7t−3 B.6t2+10t−3 C.t2+5t−3 D. c−t−2+8t−3 Answer to question 17 is B.6t2+10t−3 Question 18 : Differentiate with respect to x:f(x)=(ax3+bx) A.ax2+b FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE B.3×2+1 C.3ax2+b D.3a−b Answer to question 18 C.3ax2+b Question 19 : Evaluate the limitlimx→∞2×4−x2+8x−5×4+7 A.34 B.23 C.13 D.12 Answer to question 18 D. 1/2 Question 20 : Evaluate the limitlimx→−∞x2−5t−92×4+3×3 A. 4 B. 0 C. 1 D. 2 Answer to question 20 A. 4 IFEKITAN CARES...Information is light, I chose to carry it FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE Question 1 : Given 2×5+x2−5t2 , finddydxby using the first principle A.6t2+10t−3 B.t2+5t−3 C. c−t−2+8t−3 D.6t+7t−3 Answer to question 1 is A.6t2+10t−3 Question 2 : Find the derivative f(x)=2×2−16x+35 by using first principle A.x+16 B.3x−5 C.2x−8 D.4x−16 Answer to question 2 is D.4x−16 Question 3 : Given y(x)=x4−4×3+3×2−5x , evaluated4ydx4 A. 30 B. 22 C. 42 D. 24 Answer to question 3 is D. 24 Question 4 : Evaluate the limit limx→∞6e4x−e−2x8e4x−e2x+3e−x A.34 B.14 C.12 D.35 Answer to question 4 is A. 3/4 Question 5 : Differentiate y=3√(x2)(2x−x2) with respect to x A.y=5×233−4×533 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE B.y=10×233+8×533 C.y=5×233+4×533 D.y=10×233−8×533 Answer to question 5 is C.y=5×233+4×533 Question 6 : Evaluate the limit limh→02(−3+h)2−18h A. 12 B. 6 C. 14 D. 8 Answer to question 6 is A. 12 Question 7 : Evaluate the limit limt→4t−√(3+4)4−t A.−18 B.−58 C.−38 D.34 Answer to question 7 is B. -5/8 Question 8 : Differentiate with respect to x: f(x)=(ax3+bx) A.3a−b B.ax2+b C.3ax2+b D.3×2+1 Answer to question 8 is C.3ax2+b Question 9 : Evaluate the limit limx→−∞x2−5t−92×4+3×3 A. 4 B. 1 C. 2 FOR REVISION PURPOSE ONLY, IFEKITAN CARES  NOT FOR SALE D. 0 Answer to question 9 is A. 4 Question 10 : Evaluate the limit limx→∞2×4−x2+8x−5×4+7 B.13 C.12 D.34 Answer to question 10 is C. 12 IFEKITAN CARES...Information is light, I chose to carry it IFEKITAN CARES...Information is light, I chose to carry it IFEKITAN CARES...Information is light, I chose to carry it IFEKITAN CARES...Information is light, I chose to carry it FOR REVISION PURPOSE ONLY, IFEKITAN CARES