Motion in a Straight Line PDF

? Motion in a Straight Line Distance and Displacement 7. Displacement is not zero; then distance must not be zero...

? Motion in a Straight Line Distance and Displacement 7. Displacement is not zero; then distance must not be zero (a) True (b) False 1. Find displacement between A & B 8. Distance is not equal to zero; then displacement may equal to zero B 2m C (a) True (b) False (i) 7m 9. Statement-1: Distance and displacement is different physical (ii) quantity. Statement-2: Distance and displacement have same unit and 4m 4m dimension. 7m (a) Both statement false A (b) Both statement true B A D 3m 5m (c) Statement-I is false and Statement-II is true B (d) Statement-I is true and Statement-II is false 7m 1m 10. Statement-I : Rest & Motion are absolute terms. 8m 3m Statement-II : Distance can’t be decrease with time while 8m 4m displacement can Be. 2m 2m A 2m 6m 4m (iv) 1m (a) Both statement false (iii) 8m (b) Both statement true 5m 2m (c) Statement-I is false and Statement-II is true A (d) Statement-I is true and Statement-II is false 8m B 11. Which of the following option is correct for motion in 1-D, 2. Correct statement among the following is. without change in direction. (a) When displacement is zero, distance traveled is not zero. (a) Distance = |displacement | (b) Distance > |displacement | (b) When displacement is zero, distance traveled is also zero. (c) Distance ≥ |displacement | (d) Distance < |displacement | (c) When distance is zero, displacement is not zero. 12. Which of the following option is correct for motion in 1-D, with (d) Distance traveled and displacement are always equal change in direction. (e) None of the above statement is correct (a) Distance = |displacement | (b) Distance > |displacement | 3. Fill in the blanks : (may/must/must not/may not) (c) Distance ≥ |displacement | (d) Distance < |displacement | (a) Distance traveled by object is zero, the displacement........... 13. Which of the following option is never correct for a moving be non-zero. object? (b) Distance traveled by object is not zero then displacement........... be zero. (a) Distance = |displacement | (b) Distance > |displacement | (c) Displacement moved is zero then distance...........or........... (c) Distance ≥ |displacement | (d) Distance < |displacement | zero 14. (d) If displacement is not equal to zero, then distance........... (i) Object is moving in Distance ≤ (A) equal to zero straight line displacement 4. Particle is moving on straight line, distance is equal to displacement (ii) Object is moving on Distance > (B) straight line Without displacement (a) True (b) False change in direction 5. Displacement independent of choice of frame of reference (iii) Object is Projected Distance = (C) (a) True (b) False upward from ground displacement 6. For a particle moving on parabolic path distance always grater (iv) Moving on circular Distance ≥ (D) than displacement Path displacement (a) True (b) False 15. The numerical ratio of displacement to distance is.. Motion Displacement distance (a) always less than 1 1. A→B a.ℓ i.3ℓ (b) always greater than 1 2. A→C b. ℓ ii.4ℓ (c) always equal to 1 3. A→D c. 0 iii.ℓ (d) may be less than 1 or equal to 1 4. A→A iv.2ℓ d. 2 16. If x denotes the ratio of displacement to distance, the possible value of x is : 22. An object is moving along the sides of a regular hexagonal path with side length ℓ. For each motion: (a) 3 (b) 6/7 E l D (c) 1 (d) Both (B) and (C) l l 17. If initial position of object (2, 6, 9) and final position (8,–2, 19) then find displacement and distance F C 18. Object moves from A(2, 3, –4) to B(3,4,1) to C(5,7,1). Find l l distance and displacement from A to C. A l B 19. A car moving along in a straight highway from point P to point Q Match the corresponding displacement travelled by the object to point R and to point S, then back to point Q and finally to the point R as shown in the figure below. Motion Displacement (a) Find the distance travelled by car. 1. A → B a. 2ℓ (b) Find the displacement of the car. 2. A → C b. 0 7km 3. A → D c. 5km 3 3km 4. A → E d. ℓ P Q R S 5. A → F e. 3ℓ 20. Object moves on a circular path by angle 60o then find ratio of 6. A → A distance to displacement. 23. Match the corresponding distance travelled by the object: B Motion Distance 1. A → B a. 5ℓ π 270o R 2. A → C b. 2ℓ 60o = rad A 3 3. A → D c. 6ℓ R A 4. A → E d. 4ℓ 5. A → F e. 3ℓ B (i) (ii) 6. A → A f. ℓ 24. Kallua is moving on a circular path and completes one full round in 40 seconds. After moving for 3 minutes and 20 seconds , what B will be Kallua's displacement? 120o 25. The position of an object is given by the equation: x = (t2 + 2t + 3) R A m Find the position of the object at t = 2 seconds and displacement O in 2 sec. 26. A student moves as follows: 10 meters towards the east, then 20 meters towards the south, and then 20√2 meters in the northwest direction. Find the displacement of the student from the starting (iii) point. 21. An object is moving along the sides of a square park with a side 27. Ramlal Moves 10 m North then 10 m east, then 10 m climb upward length of ℓ. The motions of the object between points A, B, C, then find his displacement. and D are listed in the given figure. For each motion, match the 28. A person moves 20 m North then 30 m towards East and finally following: 40 2 m South-West then his displacement. D C (a) 10 2tan −1 ( 2 ) South of west 2l ) −1 (b) 10 5tan ( 2 ) South of west ( l −1 (c) 10 5tan (1 / 2 ) West of South (d) Both (a) and (b) 29. A butterfly start flying from a corner of the cubical room of side l and reaches to the opposite corner of the room. Find its A l B displacement. MR PHYSICS for questions practice 2 Class Question Bank  30. An ant start moving from a corner of the solid cubical room and Position want to reach opposite of body diagonal) find (minimum distance (Metres) 20 moved by ant. 15 31. A carom board (4 ft × 4 ft) square) has the queen at the centre. The 10 queen, hit by the striker moves to the front edge, rebounds and 5 goes in the hole behind the striking line. Find the magnitude of displacement of the queen 0 3 6 9 12 15 18 21 24 27 30 Time –5 (Seconds) (i) from the centre to the front edge –10 (ii) from the front edge to the hole and –15 (iii) from the centre of the hole. –20 32. Position-time graph for two man are moving along x-axis as shown; then find correct relation between 36. A drunkard is walking along a straight road. He takes 5 steps x (Position) forward and 3 steps backward and so on. Each step is 1 m long and takes 1 s. There is a pit on the road 11 m away from the starting x point. The drunkard will fall into the pit after: (a) 21 s (b) 29 s (c) 31 s (d) 37 s 37. Magnitude of initial position vector is 3 m and its makes 15° angle from x-axis and magnitude of final position vector is 4 m and its Time makes 75° angle from x-axis. Find out displacement of particle. t1 t2 38. A particle can move only along x-axis. Three pairs of initial and (a) Displacement = distance (b) Displacement > distance final positions of particle at two successive times are given (c) Displacement < distance (d) None of these Pair Initial Position Final Position 33. For given between position and time graph. 1 –3m +5m (i) Calculate the total distance traveled by the object from point 2 –3m –7m A to D. 3 +7m –3m (ii) Calculate the displacement of the object from point A to D. Find the sum of magnitudes of displacement in the pairs which give negative displacement in m. x (a) 14 (b) 12 10 m B C (c) 20 (d) 22 D t A 2s 4s 6s Speed and Velocity 34. An object moves along a path according to the position-time graph is shown. 39. Object is moving in straight line without change in direction, moves x1 distance in time t1 and then x2 distance in time t2 then (i) Calculate the distance traveled by the object from A to B. find average speed. (ii) Determine the displacement of the object from A to B. 40. Object is at position x1 at time t1 and at position x2 at time t2 then 30 m find average speed & average velocity if is it moving with a B change in direction. 20 m 41. Instantaneous velocity of a particle- (A) depends on instantaneous position A 10 m (B) depends on instantaneous speed 45 85 125 t (C) independent of instantaneous position 35. The position-time graph for an elevator travels up and down is (D) independent of instantaneous speed given below. Find the distance and displacement of the elevator (a) Both (A) & (B) are correct (b) Both (C) & (D) are correct between 6 seconds and 21 seconds. (c) Both (A) & (D) are correct (d) Both (B) & (C) are correct MR PHYSICS for questions practice 2024 - Question Bank 3  42. Consider the motion of the tip of the minute hand of a clock for 54. A person travels along a straight road for the first t/3 time with a one hour motion which of the following is/are correct. speed V1 and for next 2t / 3 time with a speed v2. Then the mean (A) The displacement is zero speed v is given by (B) The distance covered is zero (C) The average speed is zero v1 + 2v2 1 1 2 (a) v = (b) = + (D) The average velocity is zero/ 3 v 3v1 3v2 Option (a) (A) & (D) (b) (B) & (C) 1 3v2 (c) 3 = 2v1v2 (d) v = 3 2v1 (c) (A) & (C) (d) (B) & (D) 43. An object moves with speed v1, v2 and v3 along a line segment 55. Object is moving with constant speed (v) on square track then Fill AB, BC and CD respectively as shown in figure. Where in the blank for average speed and average velocity. AB = BC and AD = 3AB, then average speed of the object will be: D C v1v2v3 v1 + v2 + v3 (a) (b) 3 ( v1v2 + v2v3 + v3v1 ) 3 V v1 + v2 + v3 3v1v2v3 (c) (d) 3v1v2v3 v1v2 + v2v3 + v3v1 A V B 44. A Train has speed 60 km/hr for one -hr and 40km/hr for next half-hr, then average speed in km/hr. Motion Avg. Speed Avg. Velocity (a) 50 (b) 53.33 A→B (c) 48 (d) 70 A→C 45. Object Moves for 10 s with speed 20 m/s and then it Moves with A→D speed 30 m/s for 10 sec then find average speed for Complete A→A Journey. 56. If Instantaneous speed is constant, then what about average speed 46. Object moves 10 m with speed 20 m/s and then it Moves with 57. A particle is moving such that its position coordinates (x,y) are speed 30 m/s for 10 sec. then find Avg. speed for Complete Journey. (2m, 3m) at time t = 0, (6m,7m) at time t = 2s and (13m, 14 m) at  47. Object moves 20 m with speed 20 m/s and then it moves with time t = 5s. The average velocity vector vavg from t = 0 to t = 5 s speed 30 m/s for 20 m then find Avg. speed for Complete Journey. 2 (a) 1 13iˆ + 14 ˆj ( ) (b) 7 iˆ + ˆj ( ) 48. If object moves th distance of journey with speed 10 m/s and 5 3 5 remaining with 30 m/s then average speed will be : 11 ˆ ˆ 49. A car travels from Kota to Jaipur with speed 30 km/h, and it returns ( (c) 32 iˆ + ˆj ) (d) 5 (i+ j ) along the same path with speed 60 km/h. Calculate average speed 58. Position x = t2–2t + 4 then find, velocity at t = 2sec of the car and Avg. velocity ? 59. 50. A body covers first one-third of the distance with velocity 10ms–1 in same direction, the second one – third with a velocity 20ms–1 Velocity A............. B............. If veloc- It velocity is and last one-third with a velocity of 30 ms–1. The average velocity ity is variable then what of body is constant about speed then what (a) 17.8 ms–1 (b) 16.4 ms–1 about (c) 18.3 ms–1 (d) 20.2 ms–1 speed. Speed It speed is If speed is C............. D............. 2t constant variable 51. Object Moves with V1 for t/3 and with V2 for then find Avg. 3 then what then what speed about ve- about 52. A truck moves a distance of 50 km. It covers first half to the loctiy ?? velocity distance at speed of 200 m /s and second half at speed v. If average 60. Position of object x = 10 t –2t2. Find time when object comes to at speed of truck is100 m/s then value of v is rest. 53. A bus travels its half distance of journey with speed 5 m/s. It covers remaining distance in two equal time intervals with speed 61. If object is moving with speed v = 3t2; then find average speed in 15m/s Calculate average speed of the bus for the whole journey. 2-sec. MR PHYSICS for questions practice 4 Class Question Bank  62. A man is moving on circular path as shown then find avg. speed in 69. Average velocity in a time interval zero then in same time one rotation. interval average speed is: B (a) Must be zero (b) May be zero V1 = 5 m/s (c) Must be non-zero (d) may be-ve V2 = 10 m/s π 70. Assertion : The average velocity of the object over an interval of 90o = red time is either Smaller than or equal to the average speed of the 2 object over the same interval. 20 o A Reason : Velocity is a vector quantity and speed is a scalar R 3 =1 quantity. 2π 5π (a) If both Assertion & Reason are True & the Reason is a correct 150o = 6 explanation of the Assertion. V3 = 15 m/s (b) If both Assertion & Reason are True but Reason is not a C correct explanation of the Assertion. 63. Object is moving on circular path with constant speed then find (c) If Assertion is True but the Reason is False. Average Velocity when it completed half revolution. (d) If both Assertion & Reason are false. 64. A car runs at a constant speed on a circular track of radius 100 m 71. Object is moving with constant speed then velocity of object: , taking 62.8 seconds for every circular lap. The average speed for half circular lop is (a) may be variable (b) must be constant (c) must be variable (d) may be zero (a) 10 m/s (b) zero 72. Find ratio of velocity of A to B (c) 20 m/s (d) 30 m/s X (Position) 65. Object is moving on circular path with speed v then find avg. velocity when it moves an angle θ. A B B o V 15 30o θ A R Acceleration 66. A particle is executing a circular motion of radius R with a uniform 73. Which of the following is possible: speed v. After completing half the circle, the change in velocity, and in speed will be respectively   (a) v = cost n a = cost n (a) zero, zero (b) 2v, zero (b) V↑ a = costn (c) 2v, 2v (d) zero, 2v (c) V↑ a=0 67. Assertion (A) : Object is moving on circular path with constant (d) V↑ a↓ speed then the change in velocity will be zero when it will (e) V↓ a↑ complete it’s half revolution as it is moving with same speed. n (f) V = cos t a↑ Reason (R) : Velocity is vector quantity. (g) V = cos tn a = cos tn (a) A is false but R is true 74. Which of the following option is correct: (b) B Both A and R are true but R is NOT the correct explanation of A (a) Velocity of object increasing and acceleration may decreasing (c) A is true but R is false (b) Velocity of object decreasing and acceleration may increasing (d) Both A and R are true and R is the correct explanation of A (c) Acceleration may be non-zero when velocity of object is zero. 68. Assertion : The average and instantaneous velocities have same value in a uniform motion. (d) All of these. Reason : In uniform motion, the velocity of an object increases 75. Statement-I : If acceleration of particle is increasing, it’s uniformly. velocity must increases. Statement-II : The rate of change of speed with respect to time (a) If both Assertion & Reason are True & the Reason is a correct will provide us Net acceleration. explanation of the Assertion. (b) If both Assertion & Reason are True but Reason is not a (a) Both statements false correct explanation of the Assertion. (b) Both statements true (c) If Assertion is True but the Reason is False. (c) Statement-I is false and Statement-II is true (d) If both Assertion & Reason are false. (d) Statement-I is true and Statement-II is false MR PHYSICS for questions practice 2024 - Question Bank 5 76. Object is moving such that its velocity and acceleration is in 85. In a car race on straight road, car A takes a time 't less than car B opposite direction then at the finish and passes finishing point with a speed 'V' more than that of car B. Both the cars start from rest and travel with constant (a) Speed may constant. acceleration a1 and a2 respectively. Then 'v' is equal to (b) Speed may increasing. 2a1a1 (c) Speed must be decreasing. t 2a1a2 t (a) a1 + a2 (b) (d) Speed may be increasing or decreasing: a1 + a2 77. An object is moving with constant velocity then which of the (c) a1a2 t (d) t 2 following option is correct 86. The position-time graphs for two students A and B returning from (a) Acceleration may be increasing. the school to their homes are shown in figure: (b) Acceleration is zero. x B (c) Acceleration is decreasing. (d) (Acceleration is non-zero. A 78. Which of the following is wrong (a) Velocity increasing and acceleration decreasing.   (b) v ↓ and a ↑   O (c) v ↑ and a = 0 t (d) None of these. (A) A lives closer to the school 79. Object is moving with acceleration 2 m/s² its velocity at t = 0 is (B) B lives closer to the school 10m/s then find its velocity at t = 4s (C) A takes lesser time to reach home 80. Velocity at t = 0 sec is 10 m/s its velocity becomes 40 m/s after 6 (D) A travels faster than B sec then find acceleration. (E) B travels faster than A 81. Velocity at t = 2sec is 20 m/s. At t = 5sec, it becomes 32 m/s. Then Choose the correct answer from the options given below: velocity at t = 7sec will be: (a) (A) and (E) only (b) (B) and (E) only Sol. 40 m/s. (c) (A), (C) and (E) only (d) (A), (C) and (D) only 82. An object may have 87. Ramlal is moving with velocity 3iˆ + 4 ˆj at t = 0 after 5 sec its (A) varying speed without having varying velocity velocity becomes 4iˆ + 3 ˆj then find average acceleration. (B) varying velocity without having varying speed 88. Kallu is moving with speed 40 m/s in north after 10 sec he is (C) non-zero acceleration without having varying velocity moving with 40 m/s in east then find. (D) non-zero acceleration without having varying speed (i) Magnitude of rate of change in velocity.) (a) Only B is correct (b) Only D is correct (ii) Rate of change in (magnitude of velocity.) (c) Both B and D are correct (d) All are correct 89. Find acceleration in each case. 83. The velocity of a particle is zero at t = 0 then (i) x = 4t + 6, (ii) x = 3t2 + 4t + 6, (iii) x = 2t3 + 5t, (iv) x = t4 + 4t, (v) V = 3t2 + 4, (vi) V=3t + 4, (vii) V = t3 + 4, (viii) V = 2x + 4 (A) the acceleration at t = 0 must be zero 4 (B) the acceleration at t = 0 may be zero 90. If x = then find acceleration t2 (C) if the acceleration is zero from t = 0 to t = 10s, speed is also zero in this interval 91. In which case acceleration is non zero constant. (D) if the speed is zero from t = 0 t = 10 sec, the acceleration is (i) x = t2 + 2t also zero in the interval. (ii) x = 1/t2 (a) A), (C) and (D) are correct (b) (B), (C) and (D) are correct (iii) x = et (c) (A) and (D) are correct (d) (B) and (C) are correct (iv) x = t3 84. For a body moving on a straight line if x is position coordinate and (v) x = sin(t) t is time then acceleration of body is constant when - (vi) xt2 = cos tn (A) x and velocity is linear (vii)= x 3t + 5 (B) x and(square of velocity is linear (viii) V = t2 (C) t and velocity is linear (ix) V = kt (D) t and square of velocity is linear (x) V = sin(t) (a) Both (A) & (B) are correct (xi) V = kx2 (b) Both (C) & (D) are correct (xii) V = k x (c) Both (A) & (D) are correct 1 (d) Both (B) & (C) are correct (xiii) V = x MR PHYSICS for questions practice 6 Class Question Bank  92. Object is moving such that its position given as a function of time 108. The position of a particle moving along the x-axis at certain times is given below : x = α t 2 + β t + γ then find initial velocity, initial acceleration and initial position. t (s) 0 1 2 3 93. Object is moving with velocity V = 4t2 +2t + 4 then find velocity x (m) -2 0 6 16 and acceleration at t = 1 sec. Which of the following describes the motion correctly? 94. If V = kx the find acceleration at x = 2m. (a) Uniform: accelerated 95. Velocity of object V = 3t2 then find acceleration in 2 sec and (b) Uniform, decelerated acceleration at 2 sec. (c) Non-uniform, accelerated 96. If position x = t2 + 5t3 + 6 then find (d) There is not enough data for generalization. (i) Initial acceleration. 109. A particle moves along a straight line such that its displacement (ii) Initial velocity. at any time t is given by s = (t3 –6t2 – 3t + 4) meters. The velocity (iii) Acceleration at t = 2sec. when the acceleration is zero is 97. If position x = at2-bt3 find time when the acceleration is zero. (a) 3 m/s (b) 42 m/s 98. If position of object x = t2 –4t+5 then find instant when velocity (c) -9 m/s (d) -15 m/s becomes zero and displacement when object comes to at rest. 110. Position of object x = t3 – 6t2 + 10 find time when acceleration of 99. If velocity of object V = 3t2 then find distance in 2 sec. object will be zero. 100. The position of a particle moving along X -axis in given by x = 10t 111. Position of object x = 2t3 – 4t2 + 4 then find, velocity acceleration -2t2. Then the time (t) at which it will momentarly come to rest is and position at t = 2sec (a) 0 (b) 2.5 s 112. Position x = t3 –9t2 + 4 Find velocity when acceleration is zero. (c) 55 (d) 10 s 113. Position of object x = 2t3 –24t + 4 find acceleration, when velocity 101. If the displacement of a particle varies with time as x= t + 7 , of object is zero. then 114. A particle moving along x-axis has acceleration f, at time t, given (a) Velocity of the particle is inversely proportional t  t = f f 0 1 −  , where f0 and T are constants. The particle at t = 0 (b) Velocity of the particle is proportional to t2  T has zero velocity. At the instant (t = T) the particle's velocity is (c) Velocity of the particle is proportional to t (d) The particle moves with constant acceleration 1 102. The position x of particle moving along x-axis varies with time (a) f 0T (b) f0T 2 t as x = A sin (wt) where A and w are positive constants. The acceleration a of particle varies with its position (x) as 1 (c) f 0T 2 (d) f0T2 (a) a = Ax (b) a = –w2x 2 115. A body is moving with variable acceleration (a) along a straight (c) a = A w x (d) a = w2xA line. The average acceleration of body in time interval t1 to t2 is 103. The initial velocity of a particle is u (at t = 0) and the acceleration a is given by at3/2. Which of the following relations is valid? a [t2 + t1 ] a [t2 − t1 ] (a) (b) 2 2 3α t 3 (a) v = u + at3/2 (b) v= u + t2 t2 2 2 v= u + α t 5/2 ∫ t1 adt ∫ t1 adt (c) 5 (d) v = u + at5/2 (c) t2 + t1 (d) (t − t ) 2 1 104. A particle of unit mass undergoes one-dimensional motion such 116. A particle moves in a straight line and its position x at time t is that its velocity varies according to v(x) = bx–2n, where b and n are given by x2 = 2 + t. Its acceleration is given by constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by −2 1 (a) –2nb2e –4n+1 (b) –2nb2x –2n-1 (a) 3 (b) − x 4x3 (c) –2nb2x –4n–1 (d) –2b2x –2n+1 1 1 105. If velocity V = k x then find acceleration. (c) − (d) 4x 2 x2 106. If velocity v ∝ x then which of the following function is correct 117. A particle moves a distance x in time t according to equation for position time relation. x = (t + 5)–1 The acceleration of particle is proportional to (a) x ∝ t (b) x ∝ t2 (a) (Velocity) 3/2 (b) (Distance)2 (c) x ∝ t (d) x ∝ t3/2 (c) (Distance) –2 (d) (Velocity)2/3 107. The velocity of a body depends on time according to the equation 118. If acceleration of object a = 2x3/2 then find velocity at x where v = (t + 6)2 The body is undergoing. initial x = 0 is 4 m/s (a) Uniform motion 119. In which option object is moving in one-dimension without (b) Non-uniform motion with uniform acceleration. change in direction. ?? (c) Non-uniform motion with non-uniform acceleration. (a) x = t2 + 6t + 4 (b) x = –t2 – 4t + 4 (d) None of the above. (c) x = 4t – t2 + 5 (d) Both 1 and 2 MR PHYSICS for questions practice 2024 - Question Bank 7 120. Position x = t2 + 6t + 4 then find distance and displacement in 134. Object starts his motion from rest and constr acceleration ‘a ‘ then t = 4 sec. find ration of displacement in 1sec, 2sec, 2sec, 4 sec, 121. If position x = t2 – 6t + 2 then find distance and displacement in 135. If object starts his motion from rest and constant acceleration a 4 sec. then its displacement and distance will be same? 122. If position of object t2– 4t + 3 then find avg. speed (total distance) (a) True (b) False and avg. velocity (total distance) in 4 sec. 136. If u = 0 (initial velocity) and constant acceleration then find ratio 123. If one – dimensional motion, instantaneous speed v satisfies of distance in 4-sec and 8-sec. 0 ≤ v < v0. 137. Object starts his motion from rest and constant acceleration then (a) The displacement in time T must always take non - negative find ration displacement in of 5sec and in next 5sec values 138. Object starts from rest and constant acceleration it moves 80 m in (b) The displacement x in time T satisfies with variable 6-sec then find displacement in 12-sec –v0T < x < v0T 139. Object starts his motion from rest and constant acceleration then (c) The acceleration is always a non-negative number find ratio of displacement in 1st s: 2nd s: 3rd s (d) The motion has no turning points 140. If velocity of object is given as = V 25 − 8 x , then find displacement of particle in 1st second of it’s motion. 141. A particle experiences a constant acceleration for 20 sec after Motion in Straight Line with Constant starting from rest. If it travels a distance S1 in the first 10 sec and a distance S2 in the next 10 sec, then: Acceleration (a) S1 = S2 (b) S1 = S2/3 (c) S1 = S2/2 (d) S1 = S2/4 124. If a car at rest accelerates uniformly to a speed of 144 km/h in 20 142. A body starts from rest. What is the ratio of the distance travelled s, it covers a distance of by the body during the 4th and 3rd second. (a) 1440 cm (b) 2980 cm 143. Object starts his motion from rest and constant acceleration and (c) 20 m (d) 400 m moves 100 m in 1st 5-sec then find displacement in next 5-sec. 125. The velocity of the bullet becomes one third after it percentages 144. An object accelerates from rest to a velocity 27.5 m/s in 10 sec 4 cm in a wooden block. Assuming that bullet is facing a constant then find distance covered by object in next 10 sec. resistance during its motion in the block. The bullet stops (a) 550 m (b) 137.5 m completely after travelling of (4 + x) cm inside the block. The value of x is: (c) 412.5 m (d) 275 m 145. Object starts his motion from u and constant acceleration then find (a) 2 (b) 1 velocity at mid point if velocity at end point is v. (c) 0.5 (d) 1.5 146. Object starts his motion with u and constant acceleration a then 126. Object starts from rest and constant acceleration moves 80 m in 7 find its velocity V0 at one 3rd displacement of complete journey if sec. then find displacement in next 7 sec. final velocity is V. 127. A particle moves in a straight line with a constant acceleration. It 147. A car is moving along a straight road with a uniform acceleration. changes its velocity from 10 m/s to 20 m/s while passing through It passes through two points P and Q separated by a distance with a distance 135 m in t second. The value of t is velocity 30 km/h and 40 km/h respectively. The velocity of the car (a) 9 (b) 10/9 midway between P and Q is (c) 10 (d) 90 (a) 33.3 km /h (b) 20 2 km / h 128. The velocity of a body moving with a uniform acceleration of 2 m/ sec² is 10 m/sec. Its velocity after an interval of 4 sec is (c) 25 2 km / h (d) 35 km /h (a) 12 m /sec (b) 14 m /sec 148. A car moving with a speed of 50 km/h can be stopped by applying (c) 16 m /sec (d) 18 m /sec brakes after at least 6 m. If the same car is moving with a speed of 100 km/h, what is the minimum stopping distance? 129. A body of mass 10 kg is moving with a constant velocity of 10 m/s. When a constant force acts for 4 seconds on it, it moves with (a) 6 m (b) 12 m a velocity 2 m/sec in the opposite direction. The acceleration (c) 18 m (d) 24 m produced in it is: 149. A car moving with a speed of 40 km/h can be stopped by applying (a) 3 m /sec2 (b) –3 m /sec2 brakes after at least 2 m. If the same car is moving with a speed of 20 km/h, what is the minimum stopping distance? (c) 0.3 m /sec2 (d) –3 m /sec2 (a) 4 m (b) 6 m 130. Object starts his motion with velocity 10 m/sec after 8 sec its velocity becomes 24 m/sec then find total displacement in this (c) 8 m (d) 0.5 m interval. (a = constant) 150. A particle start moving from rest and constant acceleration. It travels a distance x in first 2s, and y in 4s then correction relation 131. Object starts his motion with velocity 10 m/sec and uniform is acceleration 2m/s2 then find velocity and displacement in 5 sec. (a) y = 3x (b) y = 4x 132. Object starts his motion from rest and acceleration = 5 m/s2 then find displacement in 4 sec and in 4th sec. (c) y = x (d) x = 4y 151. A particle starts from rest and constant acceleration it moves 40 m 133. Object starts his motion from rest and constant acceleration then in 3 sec then find distance in next 3sec[or] 3 sec to 6 sec. find ratio of displacement in 6th-sec and 6-sec MR PHYSICS for questions practice 8 Class Question Bank 152. Object starts his velocity 10 m/s/and acceleration 3 m/s² then find 164. An engine of a train, moving with uniform acceleration passes the displacement between 4 sec to 8 sec. signal post with velocity u and last compartment with velocity v. 153. A body starts from rest travelled a distance 120 m in the 8th sec The velocity with which middle point of train passes signal post is: then acceleration is: (a) 10 (b) 8 u+v v−u (a) (b) (c) 16 (d) 4 2 2 154. A body starts from rest with constant acceleration, it moves S1, S2 and S3 distance in 1st, 2nd and 3rd sec of its journey then correct v2 − u 2 v2 + u 2 (c) (d) relation is: 2 2 (a) S1 = S2 = S3 (b) 5S1 = 3S2 = S3 Rest to Rest Motion 1 1 1 1 (c) = S1 = S2 S3 (d)= S1 = S2 S3 3 5 5 3 165. Object starts his motion from rest and constant acceleration a for 155. Object loose its half velocity after travelling a distance 3 m with some time t1; then after retards with β and comes to at rest in time constance retardation, then find further distance after which it will t2 then find total distance travelled and Vmax stop. 166. A body starts from rest with acceleration 2 m/s² till it attains the (a) 3 m (b) 1 m maximum velocity then retards to rest with 3 m/s². If total time is (c) 2 m (d) 4 m 10 sec then maximum speed. 156. A body is moving with uniform acceleration describes (40 m in the 167. The engine of a motor cycle can produce maximum acceleration first 5 sec and (65 m in next 5 sec) Its initial velocity will be 5 m/s² It can produce maximum retardation 10 m/s² what is then minimum time in which he will cover a distance of 1.5 km (a) 4 m/s (b) 2.5 m/s (a) 5 sec (b) 15 sec (c) 5.5 m/s (d) 11 m/s (c) 10 sec (d) 30 sec 157. A particle moving with constant acceleration travels 24 m and 64 168. A particle starts from rest, accelerates at 2 m/s² for 10s and then m in the first two consecutive interval of 4 sec its initial velocity goes with constant speed for 30s and then decelerates at 4 m/s² till is: it stops. What is the distance travelled by it 158. Find distance travelled in 7 sec if its motion is given (a) 750 m (b) 800 m a = 2 m/s2 (c) 700 m (d) 850 m 169. A car starts from rest and moves with uniform acceleration a u = 10 m/s on a straight road from time t = 0 to t = T. After that, a constant deceleration brings it to rest. In this process the average speed of the car is aT (a) aT (b) 159. The initial velocity of particle is 20 m/s and retardation 2 m/s then 4 find distance and displacement in 12. sec. 3aT aT (c) (d) 2 2 160. The initial velocity of particle is 20 m/s and retardation 2 m/s2 then 170. A car accelerates from rest at a constant rate a for some time after find distance and displacement in 10th sec. which it decelerates at constant rate β and comes to rest. If total 161. The initial velocity is 21 m/s and retardation 2 m/s² then distance time elapsed is t. After how much time particle has attained it's and displacement in 11th sec. maximum velocity? (a) 0,0 (b) 0.5.0 t αt (a) (b) (c) 0,0.5 (d) 0.5 m 0.5 m 2 α +β βt 162. Object starts his motion from rest and constant acceleration takes (c) α + β (d) t time T for s displacement then find time taken for 1st half and 2nd 171. A particle of mass m moves on the x-axis as follows: It starts from half displacement rest at t = 0 from the point x = 0 and comes to rest at t = 1 at the 163. Two balls A and B are placed at the top of 180 m tall tower. Ball point x = 1 No other information is available about its motion A is released from the top at t = 0 s. Ball B is thrown vertically at intermediate time [0 < t < 1] If a denotes the instantaneous down with an initial velocity v at t = 2s After a certain time, acceleration of particle, then both balls met 100 m above the ground. Find value of V in ms-1. (a) |α| cannot exceed 2 at any point in its path. (use g = 10m/s2 (b) |α|must be > 4 at some point or points in its path (a) 10 (b) 15 (c) |α|cannot remain positive for all t in the interval 0 ≤ t ≤ 1 (c) 20 (d) 30 (d) |α|= 2 at any point in its path. MR PHYSICS for questions practice 2024 - Question Bank 9  Motion under Gravity 192. Water drops falls at regular interval from a tap which is 5m above the ground. The 3rd leaving the tap at the instant the 1st drop touches the ground. How far above the ground is the second drop 172. Object is dropped & moved 75 m in last sec of it's Journey then at that instant. find total time of journey 193. Ball is dropped from Height H then find ratio of time in 1st half and 173. Object is dropped and moves 135 m in last 1 sec of its Journey 2nd half distance. then find time of flight. 194. Object is dropped then it moves 2nd half distance in last 1 sec of 174. Object is dropped and moves 185 m in last 1 sec of its Journey motion then find time of flight. then find time of Flight & height from it is droid. 195. Object is projected with 40 m/s and 60 m/s respectively then find ratio of distance in last-sec of upward Journey 175. Object is dropped and moves 55 m in last 1 sec of its journey then find time of flight. 196. Ball is dropped from height H and takes T time to reach ground find Position of ball from ground after T/3 time. 176. Motion under gravity is an example of 197. Ball is Projected with speed u as shown in fig. then find distance (a) on-uniform acceleration, uniform motion between A & B (b) Non-uniform motion, Non-uniform acceleration (c) Non-uniform motion, uniform acceleration u/3 (d) Uniform motion, uniform acceleration B h u/2 177. Ball is dropped and move 85 m in n th sec then find that time interval. A 178. Ball is Projected with 50 m/s then find displacement in 3-sec and u 3rd sec. 179. Ball is dropped from 125 m then distance moved in last 2 sec of 198. A NCC parade is going at a uniform speed of 9 km/h under a Journey. mango tree on which a monkey is sitting at a height of 19.6 m. 180. Ball is dropped then find ratio of distance in 3rd sec and 7th sec At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is: 181. water drops are falling from a nozzle of shower onto the floor, (Given = g = 9.8 m/s²) from a height of 9.8 m. The drops fall at regular interval of time. (a) 5 m (b) 10 m When the first drops strikes the floor, at that instant, the third drop (c) 19.8 m (d) 24.5 m begins to fall. Locate the position of second drop from floor when first drop strikes the floor 199. Object is dropped then it moves 2nd half distance in last 1 sec of motion then find time of flight. (a) 4.18 m (b) 2.94 m 200. If a ball is thrown vertically upwards with speed u, the distance (c) 2.45 m (d) 7.35 m covered during the last t seconds of its ascent is 182. If velocity of object is given as = V 25 − 8 x , then find 1 2 displacement of particle in 1st second of it’s motion. (a) ut (b) 2 gt 183. Object is dropped from Height 180 m from ground find its 1 2 (c) ut − gt (d) (u + gt)t velocity at ground. and total time of flight: 2 184. Ball is dropped and touches the ground in 4 -sec. then find height 201. Rocket starts his motion in upward direction with acceleration (10 of towers from it dropped, velocity at ground, and distance m/s² upward. After 5 sec engine off then find maximum height traveled in last-sec of its journey. from ground. 185. A ball is dropped then find distance in 5th sec of journey 202. From the top of a building, 16 m high water drops are falling at equal intervals of time such that when the first drop reaches the 186. A Ball is dropped from a tower of Height 20m. then find velocity ground, the fifth drop just starts. Find the distance between the at ground. successive drops at that instant 187. Object is dropped and distance in last 1 sec is equal to 1st 3 sec 203. An elevator in which a man is standing is moving upwards with a then find height from ground from where ball is dropped. constant acceleration of 1m / s2 At some instant when speed is 10 188. A particle is dropped under gravity from rest from a height h and m/sec. If the man drops a coin a from a height 2m, it reaches the floor of the elevator after a time (g = 10m / s2)  9h  it travels a distance   in the last second the height h is 2  25  (a) 2 sec (b) 11 sec 7H 4 189. Ball is dropped from Height H and it travels in last sec of sec 16 (c) 11 (d) 1sec Journey then find 'H' 204. Ball is dropped from height 125 m after 3 sec it stopped and 190. A Ball is dropped at t = 0 sec after 1 sec, 2nd Ball is dropped after released at same instant find Total time of flight. 2 sec, 3rd Ball is dropped, after 3 sec 4th Ball is dropped. then Find distance b/w 2nd and 3nd Ball when 4nd Ball is about to fall. 205. Ball is Projected up with 80 m/s then find distance travelled in last sec of Journey. 1st 191. Water drop is falling in a regular intervals when drop is reaches to ground then 4th drop is about to release, then find distance (a) 35 m (b) 45 m between 2nd drop and 3rd drop height of water top is 9 m (c) 80 m (d) 75 m MR PHYSICS for questions practice 10 Class Question Bank  206. Ball is projected with speed 40 m/s then find Motion under Gravity Height to Ground (i) Hmax (ii) Tf 225. A ball is dropped from a high rise platform at t = 0 starting from (iii) Tupword rest. After 6 seconds another ball is thrown downwards from the (iv) Speed after t = 5sec, 6 sec same platform with a speed v. The two balls meet at t = 18 s. What (v) Distance in 6 sec is the value of v? (Take g = 10m / (s2) (vi) Displacement in 6 sec. (a) 75 m /s (b) 55 m /s (vii) Avg speed in 7 sec (c) 40 m /s (d) 60 m /s (viii) Avg velocity in 5 sec 226. Ball is Projected up with speed 4 m/s from a bridge The Ball (ix) Distance moved in 8th sec strikes the water surface after 4 s The Height of Bridge above the 207. Ball is projected upward with velocity 50 m/s then find : water surface (i) Time of flight (a) 80 m (b) 100 m (ii) Maximum height (c) 60 m (d) 40 m (iii) displacement in 6 sec 227. Find time of t light of ball (iv) Height at 7 sec u= 12 m/s (v) Average velocity in 8 sec (vi) Average speed in 8 sec 208. Object is Projected with 80 m/s then find average speed velocity in 8-sec. H=81 m 209. A Ball is thrown upward with speed 40 m/s then Find Avg. Velocity of upward Journey and speed at half of the maximum Height. 210. A Ball is thrown upward with uo if its velocity at half of maximum Height is 20 m/s then find it velocity u0 Ground 211. A ball is thrown vertically upward with an initial velocity of 150 (a) 2.7 sec (b) 5.4 sec x +1 m/s. The ratio of velocity after 3s and 5s is. The value of x (c) 4.8 sec (d) 6.9 sec is x (take g = 10 m/s2) x 228. Ball is projected up with speed "u" from height H. Then time of (a) –5 (b) 10 fight T1. With same speed "u" it is projected downward then time (c) 5 (d) 6 of fight is T2. find time of fight "T" when object is dropped from 212. Ball is Projected up with 50 m/s then Find distance moved in 8 -sec same height. 213. Ball is Projected up with 70m/s then find displacement in 10th sec 229. A ball is projected up with speed 20 m/s from a building height and 10 sec. 25 m. Then, find total time to reach the ball on ground. 214. Ball is Project up with 45 m/s then find distance moved in 5th sec. 230. Ball is projected from height of 75 m in upward direction with 215. Ball is projected up its position at t = 7s and t = 11s is same then, speed 10 m/s then find find velocity of projection and maxm height (i) Total time of flight. 216. Object is Projected up with u, its height at 3 sec and 13 sec is (ii) Velocity at ground. same, then find u and that Height, (iii) Maximum height from ground. 217. Ball is projected up its distance traveled in 3rd sec and 8th sec is same then find maximum height 231. Ball is projected up from height H with speed u and collide with 3u at ground then find H and time of flight 218. Bal is projected up with 55m/s then find distance in 6th sec. 232. A ball is projected up with speed u from height H and it takes 9s 219. Object is projected with 40 m/s then find average speed and to reach ground another same ball projected downward with same velocity in 6 sec. speed it takes 4s to reach ground if another ball is dropped from 220. Object is projected in upward with velocity 75 m/s. Find distance same height. Then, it will take to reach ground. in last 2 sec of upward journey. 233. A person standing on the floor of an elevator drops a coin. Coin 221. Ball is projected with speed u it crosses the height h in time t1 and reaches the floor in time t1 if the elevator is moving uniformly and t2 then find that height. time t2 if elevator is stationary. Then : 222. Ball is projected with speed 50 m/s. Then, find displacement in last 3 sec of journey. (a) t1 < t2 or t1 > t2 depending upon whether lift is going up or down. (a) 45 m (b) 35 m (c) 105 m (d) 80 m (b) t1 < t2 223. Ball is projected with speed u1 if air friction is not ignored then (c) t1 > t2 speed of collision u2 and t1 and t2 are time of upward and downward (d) t1 = t2 time, then 234. A lift is moving with uniform speed 20 m/s. Ball is released from (a) t1 = t2, u1 > u2 (b) t1 < t2, u1 > u2 lift when lift is at height 60 m from ground. Find total time of (c) t1 < t2, u1 < u2 (d) t1 > t2, u1 > u2 flight 224. If constant air friction is acting on object is a0 then find ratio of 235. A balloon starts raising up from ground with 1.25 m/s² after 8 sec time of flight of upward and downward Journey. a small particle is dropped then find time of flight of particle MR PHYSICS for questions practice 2024 - Question Bank 11 236. A balloon was moving upwards with uniform velocity of 10 m/s. x x An object of finite mass is dropped from the balloon when it was at a height of 75 m from ground level. The height of balloon from (i) (ii) ground when object strikes the ground was around (a) 300 m (b) 125 m t t (c) 200 m (d) 250 m x x Juggler Problem (iii) (iv) t t 237. A Juggler wants to Keep n Ball in air, if he is throwing Ball with speed u then what shout be time interval x 238. A Juggler maintain 4 Ball in air with throwing speed 20 m/s then find time interval, and Position of Balls when one ball Just about (v) to Project. t 239. A juggler maintains four balls in the air with air with throwing 245. Acceleration for given position-time graph is speed 20 m/s upwards in regular time intervals. When one ball is about to leave his hand the height of balls in air from the ground x will be: (a) 60 m, 80 m, 60 m, 0 m (b) 30 m, 40 m, 30 m, 0 m (c) 15 m, 20 m, 15 m, 0 m (d) 10 m, 20 m, 10 m, 0 m 240. Juggler wants to keep 5 Ball in air he project each ball with a time interval of 2 sec. Then find velocity of projectile. 241. A juggler maintains 10 balls in motion, making each of them rise at t a height of 80 m from his hands. Find the time interval maintained by the juggler to keep the proper distance between them (a) -ve (b) +ve (a) 0.6 s (b) 0.8 s (c) zero (d) increasing (c) 1.0 s (d) 1.2 s 246. In which time interval acceleration & velocity is parallel x Graph based Questions 242. Which of the following graph is correct for distance-time d t1 t2 t3 t d (a) t1 to t2 (b) t1 to t3 (a) (b) (c) t2 to t3 (d) None of this 247. The displacement-time graph for two particles A and B is follows. t t The ratio VA/VB is d d Y B (c) (d) displacement t t 15o A 243. The position-time graphs for two students A and B returning from 15o the school to their homes are shown in figure. (i) A lives closer to the school (ii) B lives closer to the school 45o X (iii) A takes lesser time to reach home t (iv) A travels faster than B (a) 1 : 2 (b) 13 : 1 (v) B travels faster than A. x (c) 1: 3 (d) 1 : 3 B 248. In which graph acceleration is non - zero constant? A X X (a) (b) t t o t X (a) (i), (iii), (iv) only (b) (i), (v) only (c) (i), (iii) and (v) only (d) (ii) and (v) only 244. Comment nature of motion for given graph? (c) (d) None of these t MR PHYSICS for questions practice 12 Class Question Bank 249. Figures (i) and (ii) below show the displacement-time graphs of 254. The position (x) of a particle moving along x-axis varies with time two particles moving along the x-axis. We can say that (t) as shown in figure. The average acceleration of particle in time X X interval t = 0 to t = 8 s is x (m) t t (i) (ii) 40 (a) Both the particles are having a uniformly accelerated motion (b) Both the particles are having a uniformly retarded motion (c) Particle (i) is having a uniformly accelerated motion while t (s) particle (ii) is having a uniformly retarded motion 0 2 4 6 8 (d) Particle (i) is having a uniformly retarded motion while (a) 3 m/s2 (b) –5 m/s2 particle (ii) is having a uniformly accelerated motion (c) –4 m/s2 (d) 2.5 m/s2 250. Which one of the following graph for a body moving along a straight line is possible? 255. Object starts motion from origin (0,0 as shown in the figure) Speed Speed V (a) (b) t t t5 O O t1 t2 t3 t4 t6 Time t=0 Speed (i) Then its position/ displacement is maximum at: (c) (d) (ii) Then its velocity is maximum at: t O Position O 256. A particle is moving in a straight line. Its v-t graph in different 251. Statement-I: Area under velocity-time graph gives distance cases are as shown below. Find the displacement and distance in travelled by body in given time. time interval t = 0 to t = 10s for the following cases: Statement-II: Area under acceleration-time graph is equal to 10 change in velocity in given time. (a) Both statements false 10 (b) Both statements true v v (c) Statement-I is false and Statement-II is true/ 10 (i) (m/s) (ii) (m/s) O 5 (d) Statement-l is true and Statement-II is false 252. Figure shows the position of a particle moving on the x-axis as a O 5 10 function of time t (s) t(s) –6 (m) X 10 20 10 v 10 5 (iii) (m/s) O 2 4 t (s) 0 2 4 6 8