BIOL 362 Cellular Dynamics: Cytoskeletal Dynamics II PDF
Document Details

Uploaded by SuccessfulTaiga
UBC
2025
Tags
Summary
These are lecture slides for BIOL 362 Cellular Dynamics from January 14, 2025. The slides cover cytoskeletal dynamics module 1-2, in particular actin and microtubule dynamics. The slides have practice questions to help students learn about cell dynamics.
Full Transcript
BIOL 362 Cellular Dynamics January 14, 2025 Module 1-2: Cytoskeletal Dynamics II Mouse fibroblast cells...
BIOL 362 Cellular Dynamics January 14, 2025 Module 1-2: Cytoskeletal Dynamics II Mouse fibroblast cells Actin Microtubules Slides for people on the waitlist Wittm an n T. Niko n Small Wo rld https://www.nikonsmallworld.com/galleries/2003-photomicrography-competition/filamentous-actin-and-microtubules-structural-proteins-in-mouse-fibroblasts Lecture Outline 1. What is the cytoskeleton? 2. Common properties of F-actin and microtubule dynamics 3. Actin filament dynamics in vitro: treadmilling (review) 4. Microtubule dynamics in vitro: dynamic instability 5. Accessory proteins that control filament dynamics in vivo (next lecture) 6. Drugs that inhibit cytoskeletal dynamics (next lecture) Relevant chapters in MBoC (7th edition): Chapter 16 2 Learning Goals 1. To understand how to employ a simple equation to predict cytoskeletal dynamics. 2. To understand the concept of dynamic instability during microtubule assembly. 3 1. Actin filament dynamics (review) 4 Actin polymerization follows a sigmoidal curve Steady state t=3 t=2 t=0 5 Addition of actin oligomers accelerates the polymerization Growth curve without lag phase 6 Concept: Elongation rate can be defined by the simple equation rate constant Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š 7 Four key points to note when using this equation Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š 1. What does ānā stand for in real life? 2. Why does the incorporation rate depend on [free subunit]? 3. What is the difference between elongation rate and polymerization rate? 4. Can we apply this equation for nucleation step? Clicker Q: What does ānā stand for in real life? Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š Original definition of n n in real life? A. Filament length B. Filament number C. Filament mass Clicker Q: What does ānā stand for in real life? Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š Original definition of n n in real life? A. Filament length B. Filament number C. Filament mass (length x number) Clicker Q: Why does the incorporation rate depend on [free subunit]? Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š Because [free subunit] determinesā¦ A. kon B. The frequency of interactions between filament-ends and free subunits. C. The speed of free subunit movement. Clicker Q: Why does the incorporation rate depend on [free subunit]? Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š Because [free subunit] determinesā¦ A. kon B. The frequency of interactions between filament-ends and free subunits. C. The speed of free subunit movement. What is the difference between elongation rate and polymerization rate? Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š Select the correct statement: A. Elongation rate can be negative. B. Polymerization rate can be negative. C. Dissociation rate can be negative. What is the difference between elongation rate and polymerization rate? Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š Select the correct statement: A. Elongation rate can be negative. B. Polymerization rate can be negative. C. Dissociation rate can be negative. Incorporation rate = polymerization rate. Dissociation rate = depolymerization rate Concept: Critical concentration is the subunit concentration at steady-state Slope of š š At steady-stateā¦ = ššš ššššššš ā šššš this curve š š š š =š š š kon [subunit] = koff šššš n ššššššš = ššš Cc : Critical concentration Net Incorporation and dissociation 15 are balanced Discuss with your neighbor: Can we apply this equation for nucleation step? Incorporation Dissociation Elongation š š Rate: = ššš šššš ššššššš ā šššš š š koff koff kon kon kon kon koff koff Clicker Q: Critical concentration Letās assume we have a test tube containing steady-state actin filaments after an in vitro polymerization assay. After which of the following manipulations will the critical concentration change? A: Adding more free subunits to the test tube. B: Addition of proteins that facilitate subunit incorporation. C: Removing filaments from the test tube. 17 Clicker Q: Critical concentration Letās assume we have a test tube containing steady-state actin filaments after an in vitro polymerization assay. After which of the following manipulations will the critical concentration change? A: Adding more free subunits to the test tube. B: Addition of proteins that facilitate subunit incorporation. C: Removing filaments from the test tube. B: some accessory proteins can modify kon or koff 18 We can intuitively predict polymer dynamics when Cc is known š š = ššš ššššššš ā šššš š š When [subunit] = Cc : equilibrium [subunit] > Cc : polymer n will grow [subunit] < Cc : polymer will shrink 19 More intuitive mathematical explanation š š = ššš ššššššš ā šššš š = šš ā š š š linear equation y Cc Cc 0 x -b (-koff) [subunit] 20 Critical concentration can be defined for each end to understand polymer dynamics in detail ATP cap k+on k-on k-off k+off Elongation rate Elongation rate at the minus end at the plus end š šā š š+ + ššššššš ā š+ ā ššššššš ā šā = šon = šon off š š off š š At equilibrium At equilibrium - + -šššš + šššš šŖš = - šŖš = + ššš ššš 21 Difference in Cc between plus/minus ends creates a new state: treadmilling Note: Elongation rate indicates net growth or shrink. This is not same as the polymerization rate. When š š+ [G-actin] < Cc+ š š Both ends shrink š š š šā [G-actin] > Cc- š š š š Cc + Both ends grow Cc - Cc+ < [G-actin] < Cc- Plus ends grow [G-actin] Minus ends shrink 22 Movie: Actin Treadmilling https://www.youtube.com/watch?v=VVgXDW_8O4U 23 Clicker Q: Steady-state in this graph? Note: Elongation rate indicates net growth or shrink. This is not same as the polymerization rate. š š+ Which of the following š š [G-actin] concentrations achieves steady-state? š š š šā š š š š Cc + p q r A. p B. q Cc - C. r [G-actin] 24 Clicker Q: Steady-state in this graph? Note: Elongation rate indicates net growth or shrink. This is not same as the polymerization rate. š š+ Which of the following š š [G-actin] concentrations achieves steady-state? š š š šā š š š š Cc + p q r A. p B. q Cc - C. r At q, growth at the plus-end and [G-actin] shrinkage at the minus-end 25 cancel out (= zero net growth). Discuss with your neighbor: Which is the correct graph? In vitro polymerization assay Time = 0 Steady state A Filament mass (n) There will be no assembly when at steady state initial [G-actin] is less than or equal to Cc. B When [G-actin] > Cc, polymers will be formed. (higher amount of steady state polymers when you add more monomers) 0 Cc Initially added [G-actin] at t = 0 26 Clicker Q: Which is correct? In vitro polymerization assay Time = 0 Steady state A at steady state [G-actin] C B 0 Cc Initially added [G-actin] at t = 0 27 Answer: B In vitro polymerization assay Time = 0 Steady state When initial [G-actin] < Cc, no net growth (no polymer formation). Thus, all subunits remain to be free. at steady state [G-actin] When initial [G-actin] > Cc, remaining free subunit concentration is B equal to Cc. Cc 0 Cc Initially added [G-actin] at t = 0 28 2. Microtubule dynamics 29 Discovery of microtubules Discovery of nucleus (1831) A microtubule inhibitor colchicine was used to Invention of Discovery of Discovery of cell treat gout in ancient microscope āCellā division (1837) Discovery of Egypt. (1550 BCE) (16th century) (17th century) microtubules (late 19th century) Limitation of naked eye Technology development Identification of Colchicine binding protein: tubulin (1967) 30 Discovery of microtubules Walther Flemming Theodor &ofMarcella Boveri Discovery (1843-1905) (1862-1915; nucleus (1831) 1863-1950) A microtubule inhibitor colchicine was used to Invention of Discovery of Discovery of cell treat gout in ancient microscope āCellā division (1837) Discovery of Egypt. (1550 BCE) (16th century) (17th century) microtubules (late 19th century) Paweletz N. Nature (2001); Flemming W. Advancements in Maderspacher F. Curr. Biol. (2008); Boveri T. (1899) Die Entwickelung von Limitation of naked eye Zellsubstanz, Kern und Zelltheilung (1882). Ascaris megalocephala mit besonderer RĆ¼cksicht auf die KernverhƤltnisse technology Identification of Colchicine binding protein: tubulin (1967) 31 Microtubule dynamics in vitro is also predictable when Cc is known When Filament dynamics [free subunit] = Cc : no net growth Cc [free subunit] > Cc : polymers will grow [free subunit] < Cc : polymers will shrink [free subunit] 32 What we have learned so far are theories to predict bulk assembly Biochemical analysis (info of population of cytoskeletons) What people were able to infer was 100 bulk assembly of filaments. (mass = number x length) Filament mass (n) Critical concentration Steady state Visualization by microscopy Nucleation elongation Individual microtubules exhibited unexpected behaviors time 33 3. Individual microtubule dynamics 34 MT dilution assay by Mitchison and Kirschner Number of MTs Experiments by Mitchison and Kirschner (1984) Microtubule density (108 /ml) Tubulin Elongation Reaction mix was 50 ĀµM step diluted: Condition 1 Condition1: [free tubulin] ~ 15 ĀµM Condition 2: [free tubulin] ~ 7.5 ĀµM Condition 2 Time after dilution (min) Cc ~ 14 ĀµM 35 Mitchison and Kirschner Nature (1984) Surprisingly, some microtubules kept growing after the subunit dilution below Cc Experiments by Mitchison and Kirschner (1984) Before Frequencies of microtubules dilution Tubulin Elongation Dilution 50 ĀµM step Condition1: [free tubulin] ~ 15 ĀµM Condition 2: Condition 2 [free tubulin] ~ 7.5 ĀµM Electron Condition 1 microscopy Microtubule length (Āµm) Mitchison and Kirschner Nature (1984) Cc ~ 14 ĀµM 36 What does this information tell about filament mass? Number of MTs Microtubule density (108 /ml) Frequencies of microtubules Before dilution Condition 1: Net increase in Condition 1 mass. Condition 2: Net decrease in Condition 2 mass. Both are consistent with Condition 2 Condition 1 biochemical theories. Microtubule length (Āµm) Time after dilution (min) Mitchison and Kirschner Nature (1984) 37 A ground-breaking theory of microtubule dynamics proposed in 1984 Some microtubules kept Individual MT is at either growing even when growing or shrinking phases [free tubulin] < Cc Hypothesis: A microtubule keeps growing until randomly transitions into the shrinking phase. Mitchison and Kirschner Nature (1984) 38 Visualization of individual MT dynamics at steady state Time-lapse imaging (steady-state) Tubulin/end binding protein Shrinking Growing Shrinking Time Growing Shrinking Horio and Hotani Nature (1986) Roostalu et al., eLife (2020) 39 GTP hydrolysis serves as a switch between growing and shrinking phases Tubulin/end binding protein WT tubulin GTPase mutant tubulin Roostalu et al., eLife (2020) 40 Concept: Dynamic instability Loss of GTP cap Regain of GTP cap Mitchison and Kirschner Nature (1984) 41 Concept: Catastrophe is triggered by the conformational change of microtubule lattice Growing Shrinking Plus-end Igaev and Grubmuller Plos Comp. Biol. (2020) 42 Summary of filament dynamics in vitro Elongation/steady state Shrinking Nucleation kon, koff: constant High koff Low kon GDP Rescue GDP Catastrophe GDP High koff kon, koff: constant Low kon 43 Summary Understanding of bulk assembly and individual filament assembly are both important to fully understand mechanisms of filament dynamics. Microtubule repeats two different steps: growth and shrinkage. Transition between these states are called catastrophe and rescue, respectively. Catastrophe is induced by the GTP hydrolysis-dependent conformational change of tubulin oligomers. 44 5. Practice question set 45 Question 1 Indicate if each of the following structures is based on actin filaments (A), microtubules (M), or intermediate filaments (I). Your answer would be a four-letter string composed of letters A, M, and I only; e.g. AAMI. ( ) The cell cortex ( ) The mitotic spindle ( ) The nuclear lamina ( ) Thin filaments A: AAIM B: AMMI C: AMIA D: MMIA 46 Answer: C Cell cortex Mitotic spindle Nuclear lamina Thin filament 47 Question 2 Indicate true (T) and false (F) statements below regarding the cell cytoskeleton. Your answer would be a four-letter string composed of letters T and F only; e.g. TTFF. ( ) The three major building blocks of cytoskeletal filaments can bind to and hydrolyze nucleotides. ( ) The building blocks of actin filaments and microtubules are globular proteins, whereas those of intermediate filaments are themselves filamentous proteins. ( ) Intermediate filaments provide mechanical support to the cell. ( ) Plant cells lack microtubules. A: TTFF B: FTTF C: TFTF D: FFTT 48 Answer: B Polymer: Actin filament (F-actin) Microtubule Intermediate filament Keratin/Vimentin Subunit: actin (G-actin) Ī±-tubulin/Ī²-tubulin Neurofilament protein Desmin/etc. Globular proteins 49 Question 3 Which of the following event corresponds to the ālag phaseā of the filament growth curve during in vitro polymerization? A. Nucleation B. Reaching steady state C. ATP or GTP hydrolysis D. Treadmilling 50 Answer: A Actin dimer and trimer are unstable # of contacts 1 3 6 8 (hydrophobic interaction) Also true for microtubules 51 Question 4 The time courses of seeded actin polymerization under two different conditions are compared in the following graph. If the overall kon for polymerization is known to be the same under both of these conditions, which curveā(1) or (2)ācorresponds to the condition with a higher koff rate constant? Which one corresponds to a higher Cc for polymerization? (1) subunits in filaments Percentage of actin (2) Time after salt addition A. Curve (1); curve (1) B. Curve (1); curve (2) C. Curve (2); curve (1) D. Curve (2); curve (2) E. Curve (2); both curves have the same Cc. 52 Answer: D The time courses of seeded actin polymerization under two different conditions are compared in the following graph. If the overall kon for polymerization is known to be the same under both of these conditions, which curveā(1) or (2)ācorresponds to the condition with a higher koff rate constant? Which one corresponds to a higher Cc for polymerization? 100% Cc (1) When koff is high, subunits in filaments Percentage of actin Cc (2) Cc is high because Cc = koff/kon Cc is the unused free subunit concentration at the steady state (shown by arrows). Time after salt addition A. Curve (1); curve (1) B. Curve (1); curve (2) C. Curve (2); curve (1) D. Curve (2); curve (2) E. Curve (2); both curves have the same Cc. D is correct 53 Question 5 If the concentration of free subunits is C, under which condition does the growth of a cytoskeletal filament proceed spontaneously? A. C > 1/kon B. C < 1/koff C. C > kon/koff D. C > koff/kon E. C > CcĆkon/koff 54 Answer: D If the concentration of free subunits is C, under which condition does the growth of a cytoskeletal filament proceed spontaneously? A. C > 1/kon B. C < 1/koff D is correct C. C > kon/koff D. C > koff/kon koff/kon is Cc E. C > CcĆkon/koff 55 Question 6 In the following graph of actin elongation rates under different subunit concentrations, which of the following corresponds to the slope of the line? grow A. kon Elongation rate B. koff C. kon/koff D. koff/kon 0 E. kon ā koff shrink Subunit concentration 56 Answer 6 In the following graph of actin elongation rates under different subunit concentrations, which of the following corresponds to the slope of the line? grow A is correct. A. kon Elongation rate B. koff dn/dt C. kon/koff D. koff/kon 0 E. kon ā koff shrink Subunit concentration This is a linear equation like š š y = ax-b = ššš ššššššš ā šššš š š Then āaā is the slope 57 Question 7 According to the following graph, which shows the elongation rate at the plus and minus ends of actin filaments as a function of actin subunit concentration, at what concentration (A to E) does the total length of the filament remain more or less constant with time? grow Elongation rate 0 shrink A BC DE Subunit concentration 58 Answer 7 According to the following graph, which shows the elongation rate at the plus and minus ends of actin filaments as a function of actin subunit concentration, at what concentration (A to E) does the total length of the filament remain more or less constant with time? grow Elongation rate B is correct. 0 shrink A BC DE Subunit concentration 59