CHEM271 Fall 2024 Lecture Notes PDF

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OutstandingTruth5588

Uploaded by OutstandingTruth5588

University of Maryland

2024

Efrain E. Rodriguez

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chemical kinetics reaction mechanisms catalysis chemistry

Summary

These lecture notes cover chemical kinetics, focusing on rate limiting steps, reaction mechanisms, and catalysis. The document includes examples like hydroxylamine decomposition, and calculations using the Arrhenius equation. It is part of a chemistry course, likely at the undergraduate level.

Full Transcript

Midterm I Average 69 % - 3/60 ↳ 41. pts CHEM271 Fall 2024 Lecture 13 Rate limiting steps, mechanisms, and catalysis Efrain E. Rodriguez University of Maryland Aurhenius k= exp() b frequen...

Midterm I Average 69 % - 3/60 ↳ 41. pts CHEM271 Fall 2024 Lecture 13 Rate limiting steps, mechanisms, and catalysis Efrain E. Rodriguez University of Maryland Aurhenius k= exp() b frequency EA = factor activation energy · E. E. Rodriguez, UMD, CHEM271 2 The two-point Arrhenius equation In k = (A E ⑰ - (nh-Ink E - ln k - = , 1 ⑨ 1/T (K-1) 10/16/2024 3 Example: Hydroxylamine decomposes to its products with a rate constant of 0.237 x10-4 L mol-1 s-1 at 0 °C. At 25 °C, its constant increases to 2.64 x10-4 L mol-1s-1. A. What is the order of the reaction? B. What is the activation energy for hydroxylamine decomposition? C. What is the frequency factor? NH2OHig + Ong) > - products & (6 mol"s" or M".s"( [NH - H023 # rate = k 2nd order 10/16/2024 4 Is In =C 7 Use R 8 314 Tz = 25 %, 298 15k. =. J no" K. T = 0 %, 273 15K. Ea = 6 52 X10"J. - mol " # = 65 2. 15 : molt 10/16/2024 5 for A factor ( solve (frequency + herelease InA = Ink In A = In (0 237x10"). + 6. 52x10 "T not -mot (27 In A = 18. 08 In A = 18 08. 18 08 A. = 2 =. x10 MT s. Reaction mechanisms from kinetics ↳ of reactants Sequence steps by which > - products Overall: NO2 (g) + CO (g) NO (g) + CO2 (g) Elementary steps: 1) NO2 (g) + NO2 (g) NO3 (g) + NO (g) 2) NO3 (g) + CO (g) NO2 (g) + CO2 (g) ↳) Write a rate for each elementary step. rate (step 1) k [N02]2(rate(step2) k[N0](0) = = 6 The molecularity of the rate laws Unimolecular Acg) products Most 3 > - probable Bimolecular A + A + molecularities. B + A - products B + B > - Termolecular A + A + B > - products 3 have 7 The rate-determining step (also Dr. Rodriguez’s commute on University Boulevard) ↳ The slowest elementary step is the rate-determing Step LD. The observed rate corresponds law to the rate-determining step. 10/16/2024 8 1) - 2 (log) (((g) 2) CH( > H((g) + ((z(g) - + * Cz(g) x() x(y + = , S) Find overall reaction intermediates Identify reaction of each step Determine molecularity. 1.) unimolec. C(y() > - 2x() ia Reaction & and Jy (g) : intermediates Short-lived and not in overall uxn Example: 2NO2 (g) + F2 (g) 2NO2F (g) 1) NO2 (g) + F2 (g) NO2F (g) +slow F (g) Elementary steps: 2) - F (g) + NO2 (g) NO2F (g) fast rate = k[NO2][F] bimdecular Fig) is ran intermediate. 9 10 1) NO2 (g) + NO2 (g) NO3 (g) + NO (g) 2) NO3 (g) + CO (g) NO2 (g) + CO2 (g) 11 Multi-steps involving an equilibrium k1 A (g) + B(g) C (g) + D (g) k-1 12 Example: I-(aq) + OCl- (aq) Cl- (aq) + OI- (aq) Elementary 1) OCl- (aq) + H2O (l) HOCl (aq) + OH- (aq) steps: 2) I- (aq) + HOCl (aq) HOI (aq) + Cl- (aq) 3) OH- (aq) + HOI (aq) HOI (aq) + Cl- (aq) 13 1) OCl- (aq) + H2O (l) HOCl (aq) + OH- (aq) 2) I- (aq) + HOCl (aq) HOI (aq) + Cl- (aq) 3) OH- (aq) + HOI (aq) HOI (aq) + Cl- (aq) a) Identify the reaction intermediates b) Identify the rate limiting step c) Propose a rate law for this based on answer b) 10/16/2024 14 1) OCl- (aq) + H2O (l) HOCl (aq) + OH- (aq) 2) I- (aq) + HOCl (aq) HOI (aq) + Cl- (aq) 3) OH- (aq) + HOI (aq) HOI (aq) + Cl- (aq) a) Identify the reaction intermediates b) Identify the rate limiting step c) Propose a rate law for this based on answer b) 10/16/2024 15

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