Lecture 7, 8 & 9 Biophysics I - Radiation Physics PDF
Document Details
Uploaded by LowCostLeaningTowerOfPisa5680
Tags
Summary
This document provides lecture notes on biophysics, focusing on radiation physics, specifically X-rays. It details X-ray production, components of X-ray tubes, and attenuation. The information within is comprehensive and suitable for an undergraduate-level course.
Full Transcript
Lecture 7,8 &9 biophysics I Radiation Physics Production of X–Rays x-rays emitted from x-ray tube. Components of the X-ray tube cathode : contain a heated metal filament to supply electrons by thermionic emission The material of the filament is tungsten which is chosen becaus...
Lecture 7,8 &9 biophysics I Radiation Physics Production of X–Rays x-rays emitted from x-ray tube. Components of the X-ray tube cathode : contain a heated metal filament to supply electrons by thermionic emission The material of the filament is tungsten which is chosen because of its high melting point Components of the X-ray tube The cathode contain negatively charged focusing cup. The function of the cathode cup is to direct the electrons toward the anode so that they strike the target in a well- defined area, the focal spot. Components of the X-ray tube An evacuated chamber across which a potential difference can be applied This high potential to accelerate the negative electrons from cathode to anode Components of the X-ray tube Anode (the target): a metal with a high efficiency for conversion of electron energy into X-ray photons Components of the X-ray tube The material chosen for the anode should satisfy a number of requirements (1) High conversion efficiency for electrons energy to X-rays. High atomic numbers(Z) are favored since the X-ray intensity is directly proportional to Z. lead (Z = 82) converts 1% of the energy into X- rays but aluminium (Z = 13) converts only 0.1%. (2) A high melting point so that the large amount of heat released causes minimal damage to the anode Physics of X–ray production the energy of most of the electrons striking the target is dissipated in the form of heat, the remaining produce useful X-rays There are two mechanisms by which X-rays are produced. One gives rise to Bremsstrahlung or (braking radiation) and the other characteristic X- rays. Physics of X–ray production Bremsstrahlung : The process of bremsstrahlung (braking radiation) is the result of collision (interaction) between a high- speed electron and a nucleus. The electrons while passing near a nucleus may be deflected from its path by the action of uncles attraction and lose energy as bremsstrahlung x-ray. (predicted by Maxwell) Physics of X–ray production As the electron passes in the vicinity of a nucleus it suffers a sudden deflection and deceleration As a result, a part electron energy convert to X-ray photons. Physics of X–ray production The amount of bremsstrahlung produced depends upon two factors: (1) The atomic (Z) no. of the target (i.e. the more protons in the nucleus, the greater the deceleration of the electrons). (2) Potential difference on the tube. high potential lead to faster the electrons (the more likely they will penetrate into the region of the nucleus) and Higher amount of X-ray produced. Physics of X–ray production Characteristic X-rays: An electron strikes a K-electron in a target atom and knocks it out of its orbit. The vacancy in the K shell is filled almost immediately when an electron from an outer shell of the atom falls into it. Physics of X–ray production An X-ray photon emitted when an electron falls from the L level to the K-level is called a K characteristic X-ray, and that emitted when an electron falls from the M shell to the K shell is called a K X-ray Video explain x-ray production https://www.youtube.com/watch?v=Bc0eOjWkxpU How X – Rays Are Absorbed X-rays are not absorbed equally by all materials; if they were, they would not be very useful in diagnosis. Heavy elements such as calcium (bones) are much better absorbers of X-rays than light elements such as carbon, oxygen, and hydrogen (soft tissues ), and as a result, structures containing heavy elements, like the bones, stand out clearly. The soft tissues (fat, muscles, and tumors) all absorb X- ray equally and are thus it is difficult to distinguish from each other on an X-ray image. Of course, air is poor absorber of X-rays. X-ray beam attenuation The attenuation (absorption) of an X-ray beam is its reduction due to the absorption of some of the photons out of the beam. To measure the attenuation of an X-ray beam: consider a narrow beam of X-rays is produced and an X-ray detector measures the beam intensity after passing through a certain (material)absorber. X-ray beam attenuation The un-attenuated (initial) beam intensity is (Io). When sheets of absorber are introduced into the beam; the intensity of the beam decreases to (I) transmitted intensity. Initial intensity I0 Transmitted intensity I Thickness(X) X-ray beam attenuation The intensity of X-ray beam (I) decreases exponentially with the thickness of the absorber material (X). X-ray beam attenuation The exponential equation describing the attenuation curve for a mono-energetic X-ray beam is: x I Ioe where e = 2.718 (x) is the thickness of the attenuator () is the linear attenuation (absorption) coefficient of the absorber material. X-ray beam attenuation The linear attenuation coefficient is depending on: The energy of the X-ray photons. As the energy increase the absorption decrease for the same material. Type of material. heavy material (bone) has more attenuation coefficient than light material(soft tissue). X-ray beam attenuation Application of the absorption law: Calculate the transmitted intensity of the X- ray beam after passing through tissue of thickness 12 mm, knowing that the initial beam intensity was 1000 photon/cm2 and the µ=0.69 cm-1. X-ray beam attenuation The half-value layer (HVL) for an X-ray beam: is the thickness of a given material that will reduce the beam intensity by one-half X-ray beam attenuation The half-value layer for the X-ray beam in is 2.5 mm Al. The half-value layer is related to the linear attenuation coefficient by: 0.693 HVL μ