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Polytechnic University of the Philippines Manila

2024

Kenneth James Nuguid

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abstract algebra algebra mathematical proof mathematics

Summary

This document is lecture notes from Abstract Algebra 2. It covers topics such as integral domains, fields, and polynomials. The material focuses on the concept of irreducible polynomials, with details on different criteria and relevant theorems.

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Abstract Algebra 2 Date: Every integral domain can be embedded in a field. We can find the smallest field that contains an integral domain. This is called its field of quotients or field of fractions. Let F...

Abstract Algebra 2 Date: Every integral domain can be embedded in a field. We can find the smallest field that contains an integral domain. This is called its field of quotients or field of fractions. Let F = Frac(R) be the field of quotients of R. Then F = { ab≠1 | a, b œ R, b ”= 0 }. Q = Frac(Z) and Y - Z - ]f (x) -- ^ Frac(F [x]) = F (x) = f, g œ F [x], g = ” 0 [ g(x) -- \ called the field of rational functions. Every field F has a unique, smallest subfield that is a subfield contained in every subfield of F. This is called its prime subfield. Let R be a ring with unity. If char R = 0, then R has a subring isomorphic to Z. If char R = n > 0, then R has a subring isomorphic to Zn. Let F be a field with unity. If char F = 0, then F has a subfield isomorphic to Q. If char F = p > 0, then F has a subfield isomorphic to Zp. Let R be a commutative ring with unity. Let M be a proper ideal of R. M is maximal … for an ideal I in R, M ™ I ™ R ∆ M = I or M = R. M is maximal … R M is a field. Let P be a proper ideal of R. P is prime … for a, b œ R, a œ P or b œ P whenever ab œ P. P is prime … R P is an integral domain in R, every maximal ideal is prime. A polynomial f is reducible in F [x] (or over F ) if it factors nontrivial into polynomials of smaller degrees. f œ F [x] is irreducible in F [x] (or over F ) if only factors into a nonzero constant and a polynomial of same degree. f is reducible over F f is irreducible over F nonzero constant f = g·h f = c·g deg f > deg g, deg h deg f = deg g © 2024, Kenneth James Nuguid, DMS, PUP Manila 3 Abstract Algebra 2 Date: If f is a nonzero constant (unit) then f is reducible (not irreducible). If deg f = 1, then f is irreducible. If deg f Ø 2 and f has a root c then f has a factor x ≠ c If deg f = 2 or deg f = 3 and f has no roots in F , then f is irreducible. If f factors into polynomials of smaller degree, then f is reducible. If f factors only as a product of a nonzero constant and a polynomial of same degree, then f is irreducible. If f œ Z[x], then rs œ Q (in lowest form) is a root, then r is a divisor of the constant term while s is a divisor of the leading coefficient. C(f ) or content of f is the gcd of its coefficients. f is said to be primitive iff C(f ) is a unit in R Gauss’s lemma states that the product of primitive polynomials is primitive. To obtain a polynomial in Z[x] we can multiply f by the lcd of the coefficients. f is irreducible in Z[x] ∆ f is irreducible in Q[x]. The converse is true only if f is primitve. 2x + 2 = 2(x + 1) which is not primitive is irreducible in Q[x] but not in Z[x] Let p be a prime. Mod p Test: If f reduces to an irreducible polynomial in Zp [x] then f is irreducible in Q[x]. Converse is not necessarily true. f = x3 ≠ x + 1 is irreducible over Z2. Thus, f = x3 ≠ 2x2 + x + 1 reduces to fp = x3 + x + 1 in Z2 [x]. Then f is irreducible over Q. In fact, any polynomial in Z[x] that reduces to x3 + x + 1 is irreducible over Q. Eisenstein’s Criterion: Let f = an xn + · · · + a1 x + a0 œ Z[x]. ÷ p (prime) s.t. p | a0 ,... , an≠1 , p - an , p2 - a0 ∆ f is irreducible over Q. There is always a polynomial of degree n which is irreducible over Q, which is xn ≠ p where p is a prime. © 2024, Kenneth James Nuguid, DMS, PUP Manila 4

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