Independent and Dependent Events & Conditional Probability PDF

Summary

This document contains probability and statistics quizzes covering independent and dependent events and conditional probability. It includes questions, answer choices, and solutions. It focuses on important concepts like conditional probability and independent events that students of probability should understand.

Full Transcript

Topic: Independent and dependent events and conditional probability Question: Events A and B are independent events. Find P(B) if P(A and B) = 0.25 and P(A) = 0.5. Answer choices: A P(B) = 0.125 B P(B) = 0.45 C P(B) = 0.5 D Not enough information...

Topic: Independent and dependent events and conditional probability Question: Events A and B are independent events. Find P(B) if P(A and B) = 0.25 and P(A) = 0.5. Answer choices: A P(B) = 0.125 B P(B) = 0.45 C P(B) = 0.5 D Not enough information 133 Solution: C Since the events are independent, events we know that P(A and B) = P(A) ⋅ P(B) We can plug in P(A and B) = 0.25 and P(A) = 0.5 and solve for P(B). 0.25 = 0.5 ⋅ P(B) 0.25 P(B) = 0.5 P(B) = 0.5 134 Topic: Independent and dependent events and conditional probability Question: Events A and B are dependent events. If P(A and B) = 0.7 and P(B) = 0.875, what is P(A)? Answer choices: A P(A) = 0.875 B P(A) = 0.8 C P(A) = 0.6125 D Not enough information 135 Solution: D These events are dependent events, so we can say P(A and B) = P(A) ⋅ P(B | A) We know that P(A and B) = 0.7, but we would also need to know P(B | A) in order to be able to solve for P(A). Therefore, we don’t have enough information to solve the problem. 136 Topic: Independent and dependent events and conditional probability Question: Suppose that Katie rolls a six-sided die twice. Event A is that the first roll is a 6, so P(A) is the probability that the first roll is a 6. Event B is that the second roll is a 6, so P(B) is the probability that the second roll is a 6. Which statement is false? Answer choices: A The events are independent. B The events are dependent. C P(A and B) = P(A) ⋅ P(B | A) D P(A and B) = P(A) ⋅ P(B) 137 Solution: B Events can’t be independent and dependent at the same time, so either answer choice A is false or answer choice B is false. The rolls are independent if we can show that P(A and B) = P(A) ⋅ P(B). If events are independent, it doesn’t necessarily mean that P(A and B) = P(A) ⋅ P(B | A) is a false statement. It just means that P(B) = P(B | A). P(A) is the probability that the first die lands on 6, so P(A) = 1/6. P(B) is the probability that the second die lands on 6, so P(B) = 1/6. P(A and B) is the probability of rolling a 6 on both dice, so P(A and B) = 1/36. Now we can check for independence. P(A and B) = P(A) ⋅ P(B) 1 1 1 = ⋅ 36 6 6 1 1 = 36 36 Because this equation is true, the events are independent, not dependent. 138

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