Fertilizer Dose Calculation for Important Crops PDF

Determination The Amount of Fertilizer Dose Based on Soil Test Report 1  Need to Calculated Fertilizer Dose ✓ To Provide optimum quantity of nutrients to plants ✓ To Maintain the Health of Soil ✓ F...

Determination The Amount of Fertilizer Dose Based on Soil Test Report 1  Need to Calculated Fertilizer Dose ✓ To Provide optimum quantity of nutrients to plants ✓ To Maintain the Health of Soil ✓ For Balanced Nutrition For Plant Growth ✓ To Increase the Microbial Population ✓ To get Better growth and good yield from crop ✓ TO Reduce the Attack of Pest and Diseases ✓ To get Quality production 2 ✓ Soil samples are firstly collect from the field of the farmers and the quantity of available Nutrients are determined from them. ✓ Then the farmers are guided by the soil experts about the components required for the crop in that soil. ✓ The amount of nitrogen, phosphorus and potassium available in the soil is based on the nutrient requirements of the crop. ✓ For this, the amount of nutrients in the soil is categorized as very low, low, medium, slightly high, high and very high and the amount of fertilizer can be determined from that category. 3  Classification of Nutrients Organic Available Available Available Ec CaCO3 Class of Nutrients pH Carbon Nitrogen Phosphorus Potassium (dSm-1) (%) (%) (Kg/ha) (Kg/ha) (Kg/ha) Less Less Less Less than Less than Very Low Less than 0.5 Less than 10 than 5.0 than 2 than 0.2 140 100 Low 5.1-6.0 2-4 0.6-1.0 0.2-0.4 141-280 11-20 101-150 Medium 6.1-7.5 4-6 1-2 0.4-0.6 281-420 21-30 151-200 Moderately High 7.6-8.5 6-8 2-5 0.6-0.8 421-560 31-40 201-250 High 8.6-9.0 8-10 5-10 0.8-1.0 561-700 41-55 251-300 More More More More More than Very High More than 10 More than 55 than 9.1 than 10 than 1.0 than 700 300 4  Fertilizer quantity should be decided by studying the soil test report. If the amount of any nutrient is very low, low, medium, slightly high, high and very high, then the fertilizer quantity should be changed as follows- 5  Change in fertilizer quantity as recommended Class of Nutrients Dose Very Low Fertilizer quantity should be increased by 50% Low Fertilizer quantity should be increased by 25% Medium Fertilizer quantity should be kept as it is Moderately High Fertilizer quantity should be kept as it is High Fertilizer quantity should be decreased by 50% Very High Fertilizer quantity should be decreased by 25% 6  Recommended Dose of Fertilizer Some Important Crops Sr. No. Name of Crop Recommended Dose of Fertilizer 1 Wheat 120:60:60 2 Sorghum 80:40:40 3 Barley 30:20:20 4 Chickpea 20:50:00 5 Sugarcane (Adsali) 400:170:170 6 Sugarcane (Preseasonal) 340:170:170 7 Sugarcane(Suru) 250:115:115 8 Potato 120:80:120 9 Onion 100:50:50 10 Cotton 100:50:50 11 Maize 120:60:60 12 Soybean 40:20:20 13 Seasamum 50:60:30 7 14 Linseed 30:30:00  Examples of how to determine fertilizer quantity from soil test report: Example 1- After the soil test of Mr. Dagdu Patil's field, it was found that the amount of nutrients present in the soil of his farm is Nitrogen: Phosphorus: Potash, 125: 25: 270 kg/ha respectively. He wants to sow onion in 1ha land and they want to apply urea, single super phosphate (SSP) and muriate of potash (MOP) for onion. Find the quantity of urea, single super phosphate (SSP) and muriate of potash (MOP) required for onion crop.(Recommended dose of Fertilizer for onion crop is 100:50:50 kg/ha Nitrogen: Phosphorus: Potash respectively.) 8 While classifying the nutrients in Mr. Dagdu Patil's field, we can find that the soil in his field is very low in nitrogen, moderate in phosphorus and high in potash. 9  1) Firstly we calculate the amount of urea (nitrogen): ✓ Urea contains 46% nitrogen ✓ 100 kg urea = 46 kg N ✓ We need 100 kg nitrogen so 100/46 * 100 = 217 kg urea (as per RDF) ✓ That means you get 100 kg of nitrogen from 217 kg of urea(as per RDF) ✓ But there is Very low nitrogen in the patils fields, ✓ so we want to increase the nitrogen, i.e. urea, by 50%. ✓ 217/100 * 50 = 108.5 ✓ That is 217(as per RDF) + 108.5 (increase RDF by 50%) = 325.5 kg urea / ha. 10  2) Now let us determine the amount of Phosphorus (SSP): ✓ The phosphorus content in S.S.P. fertilizer is 16% ✓ i.e. 100 kg SSP. = 16 kg P ✓ But we want 50 kg of phosphorus as per RDF ✓ 100/16 * 50 = 312 kg S.S.P. ✓ This means that you will get 50 kg of phosphorus from 312 kg of SSP. ✓ The amount of phosphorus in Patils field is moderate ✓ so there was no need to change the amount of phosphorus, i.e. the amount of SSP and we can apply same quantity of SSP i.e.312 kg/ha. 11  3) Now let us determine the quantity of Potash (MOP): ✓ The Potash content in MOP fertilizer is 60% ✓ That is 100 kg MOP = 60 kg Potash ✓ We want 50 kg of potash ✓ So 100/60 * 50 = 83 kg MOP (as per RDF) ✓ That means we get 50kg of potash from 83kg of MOP (as per RDF) ✓ But there patils fields is high in potash the, ✓ so we need to reduced the quantity of Potash i.e. MOP by 25% of RDF ✓ 83/100 * 25 = 21 ✓ That is 83(as per RDF) - 21 (decrease RDF by 25%) = 62 kg MOP/ hectare. 12  Recommendation for Mr. Dagdu Patil is to apply 325 kg of urea, 312 kg of SSP and 62 kg of MOP for growing of 1hectore of onion crop to get optimum yield. 13 Example 2- After the soil test of Mr. shantanu’s field, it was found that the amount of nutrients present in the soil of his farm is Nitrogen: Phosphorus: Potash, 437: 48: 125 kg/ha respectively. He wants to sow Rice in 1Ac land and they want to apply urea, Diammonium phosphate (DAP) and muriate of potash (MOP) for Rice. Find the quantity of urea, Diammonium phosphate (DAP) and muriate of potash (MOP) required for 1 Acre onion crop.(Recommended dose of Fertilizer for Rice crop is 150:75:75 kg/ha (60:30:30 kg/Acre) Nitrogen: Phosphorus: Potash respectively.) 14  While classifying the nutrients in Mr. Shantanu's field, we can find that the soil in his field is Moderately high in nitrogen, High in phosphorus and low in potash. 15  1) Firstly we calculate the amount of DAP (Nitrogen and Phosphorus): We know that the nutrient content of DAP is 18: 46: 00 Per 100 kg Means when we apply 100 kg DAP We Add 18kg Nitrogen and 46 gg of Phosphorus in soil A) Calculate the amount of phosphorus ✓ We require 30 kg (As per RDF) ✓ 100/ 46* 30= 65 kg DAP (As per RDF) ✓ That means you get 30 kg of Phosphorus from 65 kg of DAP (as per RDF) ✓ But there is Moderate Phosphorus in the shantanus fields, ✓ But there patils fields is high in Phosphorus the, ✓ so we need to reduced the quantity of Phosphorus i.e. DAP by 25% of RDF ✓ 65/100 * 25 = 16 ✓ That is 65 kg DAP (as per RDF) – 16 kg DAP (reduce by RDF by 25%) = 49 kg DAP / ha. ✓ But we know that the DAP content 18% nitrogen ✓ It means in 49 kg DAP Contain some quantity of nitrogen and that’s calculated as follows- ✓ 100 kg DAP= 18 kg N ✓ 49 kg DAP= x Kg N ✓ 18/ 100* 49= 9 kg N ✓ Means we apply 30 kg P and 9 kg N from 49 kg of DAP 17  2. Now we calculate the amount of Nitrogen (From Urea & DAP) ✓ We require 60 kg N (as per RDF) ✓ Out these 60 kg we already added 9 kg N ✓ Means our dose is reduced by 9 kg (60-9=51 kg N) ✓ Means we can apply only 51 kg N ✓ Urea contains 46% nitrogen ✓ 100 kg urea = 46 kg N ✓ We need 51 kg nitrogen so 100/46 * 51 = 111 kg urea (as per RDF) ✓ That means you get 51 kg of nitrogen from 111 kg of urea (as per RDF) ✓ The amount of Nitrogen in Shantanus field is moderately high ✓ so there was no need to change the amount of Nitrogen, i.e. 60 kg 18 ✓ The 60 kg Nitrogen is applied from 51 kg from urea and 9 kg from DAP.  3) Now let us determine the quantity of Potash (MOP): ✓ The Potash content in MOP fertilizer is 60% ✓ That is 100 kg MOP = 60 kg Potash ✓ We want 30 kg of potash ✓ So 100/60 * 30 = 50 kg MOP (as per RDF) ✓ That means we get 30 kg of potash from 50 kg of MOP (as per RDF) ✓ But there patils fields is low in potash the, ✓ so we need to increased the quantity of Potash i.e. MOP by 25% of RDF ✓ 50/100 * 25 = 12.5 ✓ That is 30(as per RDF) + 12.5 (increase RDF by 25%) = 42.5 kg MOP. 19 Recommendation for Mr. Shantanu is to apply 111 kg of urea, 49 kg of DAP and 42.2 kg of MOP for growing of 1 Acre of Rice crop to get optimum yield. 20 Thank you 21