Document Details

MomentousSanJose9188

Uploaded by MomentousSanJose9188

Agincourt Collegiate Institute

Tags

gas laws chemistry ideal gas law scientific principles

Summary

This document discusses gas laws, providing explanations and examples related to molar volume, gas stoichiometry, and the ideal gas law. It includes a section for practice problems.

Full Transcript

Chapter 12 Exploring Gas Laws Chapter 11.1: The Ideal Gas Law  Law of Combining Volumes: When gases react, volumes of the reactants and products, measured at equal temperatures and pressures, are always in whole number ratios.  Formulated by Joseph Louis Gay-Lussac  Example: 2...

Chapter 12 Exploring Gas Laws Chapter 11.1: The Ideal Gas Law  Law of Combining Volumes: When gases react, volumes of the reactants and products, measured at equal temperatures and pressures, are always in whole number ratios.  Formulated by Joseph Louis Gay-Lussac  Example: 2 volumes of hydrogen gas react with one volume of oxygen gas to produce two volume of water vapour.  Law of Multiple proportions: the masses of the elements that combine can be expressed in small whole number ratios.  Formulated by John Dalton  Amedeo Avogadro, 9 August 1776 – 9 July 1856, was an Italian scientist  Contributed to the molecular theory now known as Avogadro’s Law.  Combined the ideas of Gay-Lussac and John Dalton  Related the volume of a gas to the amount that is present calculated from the mass.  Avogadro’s Law: equal volumes of gases under the same conditions of temperature and pressure will contain equal numbers of molecules  Based on Avogadro’s Law, one mole of a gas occupies the same volume as one mole of another gas at the same temperature and pressure.  Molar volume: is the space that is occupied by one mole of a gas and is expressed as L/mol Example:  A resealable 1.30 L container has a mass of 7.43g. Nitrogen gas (N2(g)) is added to the container until the pressure is 98.0 kPa at 22.0°C. Together, the container and the gas have a mass of 6.18 g. Calculate the molar volume of nitrogen gas at STP.  Solution:  What is required?  Volume of one mole of nitrogen at STP  Given:  P1 = 98.0 kPa  P2 = 101.3 kPa  V1 = 1.30 L  V2 = ?  T1 = 22.0°C, or 295 K  T2 = 0°C or 273 K  m1 = 1.45 g (6.18 g – 4.73 g)  m2 = 1.45 g (mass does not change)  Step 1: calculate number of moles of nitrogen gas 𝑚 1.45 𝑔  n= = = 0.0517 mol 𝑀 28.02 𝑔/𝑚𝑜𝑙  Step 2: find the volume of nitrogen at STP, using the Combined Gas Law 𝑃1𝑉1 𝑃2𝑉2  = 𝑇1 𝑇2 𝑃1𝑉1 𝑇2  V2 = × 𝑇1 𝑃2 98.0 𝑘𝑃𝑎 ×1.30 𝐿 ×273 𝐾  V2 = 295 𝐾 ×101.3 𝑘𝑃𝑎 = 1.16 L  Step 3: Find the molar volume 𝑉 1.16 𝐿  Molar volume = = = 22.4 L/mol 𝑛 0.0517 𝑚𝑜𝑙  Therefore: the molar volume of nitrogen gas is 22.4 L/mol at STP Homework:  Practice Problems:  Questions 1-4 on page 477  Questions 5-11 on page 482 Volumes of Real Gases:  At STP gases behave like ideal gases.  At high pressure and/or low temperatures gases no longer behave like ideal gases.  This is because gas molecules have a volume of their own.  There is attraction between gas molecules.  Molecules don’t necessarily move in straight lines.  Collisions are not completely elastic, there is loss of energy.  In these conditions of low temperature and/or high pressure, gases have smaller volumes.  Molecules are closer together allowing for attraction.  Smaller volumes of the gas also means that the volume of the gas particles becomes more important. The Ideal Gas Law  Vαn 𝑇  Vα 𝑃 𝑛 ×𝑇  Therefore: V α 𝑃 nRT  Introduce a constant, R, V = 𝑃 𝑃𝑉  R= 𝑛𝑇 The Universal Gas Constant, R  One mole of a gas at STP:  P = 101.3 kPa  T = 273 K  V = 22.4 L  n = 1.00 mol 𝑃𝑉  R= 𝑛𝑇 101.3 𝑘𝑃𝑎 ×22.4 𝐿 𝑘𝑃𝑎 × 𝐿  R= = 8.314 1.00 𝑚𝑜𝑙 ×273 𝐾 𝑚𝑜𝑙 ×𝐾 The Universal Gas Law  PV = nRT Homework  Practice Problems:  Questions 12-15 on page 487-488.  Section Review Questions:  Questions 1-7 on page 488. Chapter 12.3: Gas Law Stoichiometry  Volume to volume stoichiometry  When gases react with other gases Gay-Lussac’s law of combining volumes can be used to solve these problems  As usual, it requires a balanced chemical equation  Example: what volume of ammonia gas can be produced from 12.0 L of nitrogen and excess hydrogen gas at same temperature and pressure?  N2(g) + 3 H2(g)  2 NH3(g)  There is a 1 mol N2(g) to 2 mol 2 NH3(g) ratio between nitrogen and ammonia 𝑥 𝐿 𝑁𝐻3 𝑔 2 𝑚𝑜𝑙  Therefore, ( ) = 1 𝑚𝑜𝑙 12.0𝐿 𝑁2 𝑔 ( )  x = 24.0 L  Using the ideal gas law it is possible to solve problems in stoichiometry when gases are involved.  Solve the problem by first converting the volumes into number of moles  Compare the moles  Then convert back to volumes  Often reactions occur in solutions which then release gas  If this is the case, the pressure of water vapour needs to be considered  This can be corrected for using Dalton’s partial pressure law  Pgas = Ptotal – Pwater vapour  Use the table for water vapour pressure to correct for this Homework  Practice Problems:  Questions 25-28 on page 503  Questions 29-34 on page 506  Questions 35-39 on page 511  Section Review Questions 1-8 on page 514

Use Quizgecko on...
Browser
Browser