Chemistry Past Paper PDF
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Uploaded by RejoicingActinium
Delta University Egypt
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Summary
The document appears to be handwritten notes or solutions to chemistry problems involving gas laws. It includes various formulas, calculations, like PV = nRT and examples of solving for variables like V2,T. and n. The content likely serves as practice for chemistry exams. No exam board is specified, nor any date/year.
Full Transcript
### تاريخ: الموضوع : 1. * P₁ = 19+m * V₁ = 2L * P₂=0,809+m * V₂=? * P₁V₁=P₂V₂ * 1X1=0g80 V₂ * V₂= 295L 2. * R=0,0821 * N = 3 + Litter * P=0,94 at m * T=50+273=323 K * $n = \frac{PV}{RT}$ * $n = \frac{0,94 \times 3}{...
### تاريخ: الموضوع : 1. * P₁ = 19+m * V₁ = 2L * P₂=0,809+m * V₂=? * P₁V₁=P₂V₂ * 1X1=0g80 V₂ * V₂= 295L 2. * R=0,0821 * N = 3 + Litter * P=0,94 at m * T=50+273=323 K * $n = \frac{PV}{RT}$ * $n = \frac{0,94 \times 3}{0,0821 \times 323} = 0,9120$ * molecular weight = $\frac{mass}{number of moles} = \frac{75}{0,9120} = 47,919$ 3. * mass of CO₂)=29 * V = 2L * P=1, 21 atm * T=2 * $PV=nRT$ * $n = \frac{PV}{RT}$ * $n = \frac{1,21 \times 2}{0,0821 \times 2} = 0,0625$ * $T = \frac{PV}{nR}$ * $T = \frac{1,21 \times 2}{0,0625 \times 0,0821} = 47196 K$ * $T = 47196 - 273 =198,60^\circ C$ 4. * V₁ = 197L * V₂ = 197L * h₁ = 3 * h₂= 3+5=8 * $\frac{V_1}{h_1} = \frac{V_2}{h_2}$ * $\frac{197}{3} = \frac{V_2}{8}$ * $V_2 = \frac{197 \times 8}{3} = 4353L$