Chemical Bonding PDF
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This document provides an introductory overview of chemical bonding, focusing on ionic, covalent, and metallic bonding. Examples of different types of bonds, along with their properties are included. The document also includes Lewis electron dot diagrams and the energy involved in ionic bonding, helping readers gain a good understanding of atoms, bonds and how they interact.
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Chemistry 101 Chapter 9 CHEMICAL BONDING · Chemical bonds are strong attractive force that exists between the atoms of a substance Chemical Bonds are commonly class...
Chemistry 101 Chapter 9 CHEMICAL BONDING · Chemical bonds are strong attractive force that exists between the atoms of a substance Chemical Bonds are commonly classified into 3 types: 1. IONIC BONDING Ø Ionic bonds usually form between metals and nonmetals Ø Bonds form by transfer of electrons Ø Ex: NaCl, MgBr2, AlF3, etc 2. COVALENT BONDING Ø Covalent bonds usually form between atoms of nonmetals Ø Nonmetallic atoms may be the same or different Ø Bonds form by sharing of electrons Ø Ex: H2, Cl2, N2, HCl, H2O, NH3, CO2, CCl4 3. METALLIC BONDING Ø Metallic bonds form between metallic ions Ø Bonds are formed through “nonlocalized” sharing of electrons commonly referred to as “Sea of electrons” Ø Ex: Cu, Al, Na 1 Chemistry 101 Chapter 9 LEWIS ELECTRON – DOT SYMBOLS · When atoms bond, the bonding is usually achieved by the interaction of valence electrons · Recall: Valence electrons are the “s” and “p” electrons of the outermost shell · In Lewis Electron – Dot Symbols the dots represent valence electrons Examples: Na Ga 1s 2s2 2p6 3s1 2 1s 2s 2p6 3s2 3p6 3d10 4s24p1 2 2 1s2 2s2 2p6 3s1 1s2 2s2 2p6 3s2 3p6 3d10 4s24p1 [Ne] 3s1 [Ar] 3d10 4s24p1 Lewis ElectronDot Na Ga Symbol Note: Na Ga stands for stands for [Ne] [Ar] 3d10 Noble Gas Core PseudoNoble Gas Core 2 2 6 1s 2s 2p 1s2 2s2 2p6 3s2 3p6 3d10 [Ne] [Ar] 3d10 Conclusion: In Lewis Electron – Dot Symbols: Ø dots represent valence electrons Ø symbols of elements represent Noble Gas Cores or Pseudo – Noble Gas Cores 2 Chemistry 101 Chapter 9 LEWIS ELECTRON DOT SYMBOLS FOR REPRESENTATIVE ELEMENTS IA IIA IIIA IVA VA VIA VIIA VIIIA Li Be B C N O F Ne [He]2s [He]2s [He]2s 2p [He]2s 2p [He]2s 2p [He]2s 2p [He]2s 2p [He]2s22p6 1 2 2 1 2 2 2 3 2 4 2 5 2 Li Be B C N O F Ne Na Mg Al Si P S Cl Ar [Ne]3s [Ne]3s [Ne]3s 3p [Ne]3s 3p [Ne]3s 3p [Ne] 3s 3p [Ne] 3s 3p [Ne]3s23p6 1 2 2 1 2 2 2 3 2 4 2 5 3 Na Mg Al Si P S Cl Ar ns1 ns2 ns2 np1 ns2 np2 ns2 np3 ns2 np4 ns2 np5 ns2 np6 X X X X X X X X Number of Dots = Number of Valence Electrons = Group Number 3 Chemistry 101 Chapter 9 IONIC BOND · Ionic bonds are commonly found in “SALTS” · Recall SALTS are made up of : CATIONS and ANIONS any positive ion any negative ion other than H+ other than OH- · Examples of Salts: NaCl KNO3 (NH4)2SO4 NH4C2H3O2 Properties of Salts: Ø crystalline solids at room temperature (RT) Ø have high Melting Points Ø are Strong Electrolytes in molten form and in aqueous solution FORMATION OF AN IONIC BOND Na + Cl Na+ Cl electron transfer 1 [Ne]3s [Ne] 3s23p5 [Ne] [Ne] 3s23p6 [Ar] Oppositely charged ions attract · The Ionic Bond is the electrostatic attraction between the oppositely charged ions. 4 Chemistry 101 Chapter 9 OTHER EXAMPLES OF FORMATION OF IONIC COMPOUNDS Mg + Cl Mg2+ 2 Cl MgCl2 [Ne]3s2 [Ne] 3s23p5 [Ne] [Ar] Ionic Formula Empirical Cl (Simplest) Formula [Ne] 3s23p5 2 Na + S 2 Na+ S 2 Na2S [Ne]3s1 [Ne] 3s23p4 [Ne] [Ar] 2 e- Ionic Empirical Formula (Simplest) Formula 5 Chemistry 101 Chapter 9 2 Al + 3 O 2 Al3+ 3 O 2 Al2O3 [Ne]3s2 [He]2s22p4 [Ne] [Ne] 6 electrons · Ionic Bond forms by the transfer of one or more valence electrons from a metallic atom to a nonmetallic atom transfer valence electrons Metals Nonmetals Metallic Nonmetallic Cation Anion (Electronic (Electronic Configuration Configuration of Noble Gas of Noble Gas preceding the following the the metallic atom nonmetallic atom) 6 Chemistry 101 Chapter 9 ENERGY INVOLVED IN IONIC BONDING Na(s) + ½ Cl2 Na+Cl-(s) DH = 411 kJ/mol NaCl (exothermic) · Where is this energy coming from? The reaction can be considered to take place in 5 steps: Step 1: Sublimation of Sodium (solid Na ® gaseous Na) Na (s) Na (g) DH1 = + 108 kJ/mol Na endothermic Step 2: Dissociation of Chlorine molecules (Cl 2molecules ® Cl atoms) ½ Cl2 Cl (g) DH2 = + 120 kJ/mol Cl endothermic Step 3: Ionization of Sodium (Na atoms ® Na+ ions) Na (g) Na+ (g) + e- DH3 = + 496 kJ/mol Na endothermic (First Ionization Energy of Na) Step 4: Formation of Cl- (Cl atoms ® Cl- ions) Cl (g) + e- Cl- (g) DH4 = –349 kJ/mol Na exothermic (Electron Affinity of Cl Step 5: Formation of NaCl(s) from ions Na+ (g) + Cl- (g) Na+Cl- (s) DH5 = –786 kJ/mol Na exothermic (Lattice Energy of NaCl = U) energy given off when ions form a crystalline structure Net Energy Released = + 108 kJ + 120 kJ + 496 kJ – 349 kJ – 786 kJ = – 411 kJ/mol 7 Chemistry 101 Chapter 9 Na+(g) + Cl(g) E. A. of Cl I. E. of Na (–349 kJ/mol) (+ 496 kJ/mol) Na+ (g) + Cl-(g) Na(g) + Cl(g) Dissociation of Cl2 (+ 120 kJ/mol) Na(g) + ½ Cl2(g) Sublimation of Na Lattice Energy (+ 108 kJ/mol) (–786 kJ/mol) Na(s) + ½ Cl2(g) DHf (NaCl) 411 kJ/mol 8 Chemistry 101 Chapter 9 INTERPRETING THE ENERGETICS OF IONIC BONDING · The Net Ionic Reaction of the formation of Na+Cl-(s) is exothermic: Na(s) + ½ Cl2(g) Na+Cl-(s) DHf = 411 kJ/mol Higher Energy Lower Energy Less stable More stable NOTE: 1. The system’s energy is lowered 2. The larger the energy given off: Ø the more stable the ionic compound Ø the easier the ionic compound forms CONCLUSIONS 1. Formation of an Ionic Compound is favored by any factor that increases the Net Energy Released: (a) Low Ionization Energy (characteristic of Metals) (b) High Electron Affinity (characteristic of Nonmetals) (c) High Lattice Energy. The Lattice Energy depends on: Ø respective charges of ions Ø respective sizes of ions 2. Most compounds formed between Metals and Nonmetals are Ionic Compounds Elements on the Elements on the lower lefthand side upper righthand side of Periodic Table of Periodic Table (Metals with low I.E.) (Nonmetals with high E.A.) (Noble Gases are excluded) 9 Chemistry 101 Chapter 9 IONS OF MAIN GROUP ELEMENTS IA IIA IIIA IVA VA VIA VIIA Period 1 H– Period 2 Li+ covalent covalent covalent N3– O2– F– Period 3 Na+ Mg2+ Al3+ covalent P3– S2– Cl– Period 4 K+ Ca2+ Ga3+ covalent As3– Se2– Br– Period 5 Rb+ Sr2+ In3+ Sn2+ Sn4+ Sb3+ Te2– I– Period 6 Ca+ Ba2+ Tl3+ Tl+ Pb2+ Pb4+ Bi3+ covalent radioactive NOTE: 1. Group IA through Group IVA Ø Charge of Cation = Group Number Ø Atoms lose all their valence electrons (“s” and “p” electrons) Ø Electronic Configuration of cations = Preceding Noble Gas electronic Configuration 2. Group IIIA through Group VA Ø Charge of Cation = Group Number – 2 Atoms lose only their “p” valence electrons ( “s” electrons are kept) Electronic Configuration of cations = Preceding Pseudo Noble Configuration + ns2 Sn – 2e Sn2+ Similarly: Pb2+ [Kr] 5s 4d 5p2 2 10 [Kr] 5s2 4d10 Sb – 3e Sb3+ Similarly: Bi3+ [Kr] 5s2 4d10 5p3 [Kr] 5s2 4d10 3. Group VA through Group VIIA Ø Charge of Anion = Group Number 8 Atoms gain electrons to achieve stable octet (or doublet in the case of H) Electronic Configuration of anions = Noble Gas electronic Configuration following the element. 10 Chemistry 101 Chapter 9 CATIONS OF TRANSITION METALS · These ions are very often colored Loss of electrons Ionic Charge Examples The “ns” electrons are lost first (most common) 2+ Zn2+ Cd2+ 2+ In some cases in addition to the “s” electrons, some “d” and/or larger Fe2+ Fe3+ electrons from an inner shell (n1) may be lost. than 2+ Unusual charges are due to irregular electronic 2+ Cu2+ Cu+ configurations associated with the stability of halffilled and/or 1+ Ag+ or filled subshells Fe2+ [Ar] -¯ - - - -. 4s 3d Fe0 [Ar] -¯ -¯ - - - - Fe3+ [Ar] - - - - -. 4s 3d 4s 3d Cu 2+ Cu+ Ag+ [Ar] 4s0 3d 9 [Ar] 4s 0 3d 10 [Kr] 5s 0 4d10 11 Chemistry 101 Chapter 9 IONIC RADII Ionic Radius Ø is the radius of the spherical region around the nucleus within which the electrons are most likely to be found. Ø is obtained from known distances between nuclei in ionic crystals (obtained by Xray diffraction crystallography, a method that makes the positions of the nuclei visible) Determining the Radius of the I - (iodide) ion in LiI (lithium iodide) · Distance between the nuclei of two I - ions = 426 pm 426 pm - Radius of the I ion = ¾¾¾ = 213 pm 2 · From this information the radius of the Li+ ion can be determined from the experimentally determined distance between Li+ ion and the I - ion. d Radius of Li + = d (Li + I - ) – 213 pm 12 Chemistry 101 Chapter 9 RADII OF CATIONS Radii of atoms > Radii of Cations Na0 Na+ 1s2 2s22p6 3s1 1s2 2s22p6 3 shells 2 shells isoelectronic with Ne · Isoelectronic = species having the same number of electrons and electron configuration. · Arrange the following species in order of increasing size: Fe 0 Fe 3+ Fe 2+ 26 p, 26 e 26 p, 23 e 26 p, 24 e [Ar] 4s2 3d 6 [Ar] 3d 5 [Ar] 3d 6 4 shells 3 shells 3 shells weaker stronger interelectron interelectron repulsions repulsions smaller ion larger ion Fe 3+ < Fe 2+ < Fe 0 smallest largest Conclusion: · For cations of the same element (same number of protons): The larger the positive ionic charge, the smaller the cation · Reason: Larger positive ionic charge means fewer electrons 13 Chemistry 101 Chapter 9 Size of Cations in The Periodic Table (Main Group Elements) IA IIA IIIA 2 Li+ (isoelectronic with He) 3 Na+ Mg 2+ Al 3+ (isoelectronic with Ne) 11 protons 12 protons 13 protons 4 K+ Ca 2+ Ga3+ (isoelectronic with Ar) 19 protons 20 protons 5 Rb + Sr2+ In3+ (isoelectronic with Kr) 37 protons 38 protons 6 Cs + Ba2+ Tl 3+ (isoelectronic with Xe) 55 protons 56 protons 14 Chemistry 101 Chapter 9 RADII OF ANIONS Radii of Atoms < Radii of Anions Cl 0 Cl - 1s2 2s22p6 3s23p5 1s2 2s22p6 3s23p6 isoelectronic with Ne 3 shells 3 shells 17 p , 17 e 17p, 18 e Nuclear Charge= + 17 Nuclear Charge = + 17 Holds 17 electrons strongly Holds 18 electrons less strongly · Arrange the following species in order of increasing size: O0 O 2- O- 8 p, 8 e 8 p, 10 e 8 p, 9 e [He] 2s2 2p 4 [He] 2s2 2p 6 [He] 2s2 2p5 2 shells 2 shells 2 shells some strongest stronger interelectron interelectron interelectron repulsions repulsions repulsions larger ion smaller anion O0 < O- < O 2- smallest largest Conclusion: · For anions of the same element (same number of protons): The larger the negative ionic charge, the larger the anion · Reason: Larger negative ionic charge means more electrons. 15 Chemistry 101 Chapter 9 Size of Anions in the Periodic Table VA VIA VIIA Noble Gases 2 N3- O2- F- (isoelectronic with Ne) 7 protons 8 protons 9 protons 3 P3- S2- Cl - (isoelectronic with Ar) 15 protons 16 protons 17 protons 4 As 3 - Se 2 - Br - (isoelectronic with Kr) 33 protons 34 protons 35 protons Te 2 - I- 5 52 protons 53 protons (isoelectronic with Xe) 16