You are working on a dataset. The recorded values are: 7, 9, 7, 7, 7, 6. Find the measures of central tendency and variability.

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Understand the Problem

The question is asking about the measures of central tendency, measures of variability, and other descriptive statistics such as ranking and questionnaires, applied to a dataset. We should calculate mean, variance, standard deviation and perform ranking and questionnaire analysis for the given dataset.

Answer

Mean: $\approx 7.17$ Variance: $\approx 0.8088$ Standard Deviation: $\approx 0.8993$ Ranking: $6$ (Rank $1$), $7$ (Rank $3.5$), $9$ (Rank $6$) Questionnaires: Method of gathering data.
Answer for screen readers

Mean: $\approx 7.17$ Variance: $\approx 0.8088$ Standard Deviation: $\approx 0.8993$ Ranking: $6$ (Rank $1$), $7$ (Rank $3.5$), $9$ (Rank $6$) Questionnaires: Method of gathering data.

Steps to Solve

  1. Calculate the mean

To find the mean (average) of the data set, sum all the values and divide by the number of values. The data set is: $7, 9, 7, 7, 7, 6$ $$ \text{Mean} = \frac{7 + 9 + 7 + 7 + 7 + 6}{6} = \frac{43}{6} \approx 7.17 $$

  1. Calculate the variance

Variance measures how spread out the data is from the mean. First, find the squared difference of each value from the mean, sum these squared differences, and then divide by the number of values (or $n-1$ for sample variance). In the given prompt, it does not specify "sample," so we will assume it wants the population variance.

Calculate the squared differences: $(7 - 7.17)^2 \approx 0.0289$ $(9 - 7.17)^2 \approx 3.3489$ $(7 - 7.17)^2 \approx 0.0289$ $(7 - 7.17)^2 \approx 0.0289$ $(7 - 7.17)^2 \approx 0.0289$ $(6 - 7.17)^2 \approx 1.3689$

Sum of squared differences: $0.0289 + 3.3489 + 0.0289 + 0.0289 + 0.0289 + 1.3689 \approx 4.8529$

Divide by the number of values (6): $$ \text{Variance} = \frac{4.8529}{6} \approx 0.8088 $$

  1. Calculate the standard deviation

The standard deviation is the square root of the variance: $$ \text{Standard Deviation} = \sqrt{0.8088} \approx 0.8993 $$

  1. Ranking

To rank the data, sort the data and assign ranks: Sorted data: $6, 7, 7, 7, 7, 9$ Ranks: 6 (Rank 1) 7 (Rank 2.5, average of ranks 2, 3, 4, 5, i.e. $(2+3+4+5)/4 = 14/4 = 3.5$) 9 (Rank 6)

  1. Questionnaires

Questionnaires are a method of gathering data from a sample of people. This is a qualitative or quantitative method of collecting data.

Mean: $\approx 7.17$ Variance: $\approx 0.8088$ Standard Deviation: $\approx 0.8993$ Ranking: $6$ (Rank $1$), $7$ (Rank $3.5$), $9$ (Rank $6$) Questionnaires: Method of gathering data.

More Information

The mean, variance, and standard deviation are measures of central tendency and variability, respectively. Ranking provides an ordinal scale of the data, and questionnaires gather structured information from individuals.

Tips

A common mistake would be to calculate sample variance instead of population variance in the calculations. Another mistake is to not calculate an average rank for repeated values.

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