What is the area of the figure?

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Understand the Problem

The question is asking to calculate the area of a composite figure given its dimensions. The figure consists of several rectangles, and the total area can be found by breaking it down into individual areas and summing them up.

Answer

$252 \, \text{in}^2$
Answer for screen readers

The area of the figure is $252 , \text{in}^2$.

Steps to Solve

  1. Identify the Dimensions Break the composite figure into smaller rectangles and identify their dimensions.

    • Rectangle 1 (top): Length = 12 in, Height = 15 in
    • Rectangle 2 (middle): Length = 9 in, Height = 6 in
    • Rectangle 3 (bottom): Length = 3 in, Height = 6 in
  2. Calculate the Area of Each Rectangle Use the formula for the area of a rectangle, which is given by $A = \text{Length} \times \text{Height}$.

    • Area of Rectangle 1: $$ A_1 = 12 , \text{in} \times 15 , \text{in} = 180 , \text{in}^2 $$

    • Area of Rectangle 2: $$ A_2 = 9 , \text{in} \times 6 , \text{in} = 54 , \text{in}^2 $$

    • Area of Rectangle 3: $$ A_3 = 3 , \text{in} \times 6 , \text{in} = 18 , \text{in}^2 $$

  3. Sum the Areas of Each Rectangle Add the areas calculated for each rectangle to get the total area of the composite figure.

    $$ \text{Total Area} = A_1 + A_2 + A_3 $$ $$ \text{Total Area} = 180 , \text{in}^2 + 54 , \text{in}^2 + 18 , \text{in}^2 $$

  4. Calculate the Final Area Perform the addition to find the total area.

    $$ \text{Total Area} = 180 + 54 + 18 = 252 , \text{in}^2 $$

The area of the figure is $252 , \text{in}^2$.

More Information

The area calculation involves breaking down a composite figure into simpler parts to make the measurement easier. By calculating the area of each rectangle and summing them up, we ensure that no section is overlooked.

Tips

  • Miscalculating the dimensions of each rectangle. Ensure you double-check the measurements before applying them in the area formula.
  • Forgetting to sum all areas after calculating them individually. Always perform the addition carefully.

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