The flag-down fare of a taxi is PKR m. The taxi charges PKR n for each kilometre it travels. Use the graph to find the value of m and n.
Understand the Problem
The problem asks us to find the values of 'm' and 'n' based on the provided graph, where 'm' represents the flag-down (initial) fare of a taxi in Pakistani Rupees (PKR), and 'n' represents the charge per kilometer in PKR. We need to extract the 'm' from the graph and find the slope to calculate 'n'.
Answer
$m = 200$ $n = 100$
Answer for screen readers
$m = 200$ $n = 100$
Steps to Solve
- Find the flag-down fare 'm'
The flag-down fare is the y-intercept of the graph, which is the charge when the distance traveled is 0. From the graph, the y-intercept is 200. Therefore, $m = 200$.
- Find two points on the line to calculate the slope
We can read two points from the graph: $(0, 200)$ and $(2, 400)$.
- Calculate the slope 'n'
The slope $n$ is the change in charge divided by the change in distance: $$ n = \frac{y_2 - y_1}{x_2 - x_1} = \frac{400 - 200}{2 - 0} = \frac{200}{2} = 100 $$ So, $n = 100$.
$m = 200$ $n = 100$
More Information
The flag-down fare 'm' represents the initial charge regardless of the distance traveled. The charge per kilometer 'n' represents the additional cost incurred for each kilometer covered.
Tips
People might misread the graph and choose incorrect points, leading to errors in slope calculation. Ensure you accurately identify the coordinates of the points on the graph.
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