The direction field for dy/dx = 2x + y is shown in Figure 1. Answer the following questions about this direction field. (a) Sketch the solution curve that passes through (0, -2). F... The direction field for dy/dx = 2x + y is shown in Figure 1. Answer the following questions about this direction field. (a) Sketch the solution curve that passes through (0, -2). From this sketch, write the equation for the solution. (b) Sketch the solution curve that passes through (-1, 3). (c) What can you say about the solution in part (b) as x → +∞? How about x → -∞?

Question image

Understand the Problem

The question involves analyzing a direction field of a differential equation, which requires sketching solution curves based on given points and discussing long-term behavior. The objective is to understand the dynamics of the solutions represented in the field.

Answer

(a) $y = 2x - 2$; (b) $y = 7e^{x} - 2x - 2$; (c) As $x \to +\infty$, $y \to +\infty$; as $x \to -\infty$, $y \to -2$.
Answer for screen readers

(a) The specific solution curve through (0, -2) is

$$ y = 2x - 2 $$

(b) The specific solution curve through (-1, 3) is

$$ y = 7e^{x} - 2x - 2 $$

(c) As ( x \rightarrow +\infty ), ( y \rightarrow +\infty ) and as ( x \rightarrow -\infty ), ( y \rightarrow -2 ).

Steps to Solve

  1. Identify the Equation and Direction Field

The differential equation given is

$$ \frac{dy}{dx} = 2x + y $$

The direction field illustrates the slope defined by this equation at various points.

  1. Find the General Solution

To find the general solution, we can rewrite the equation in a standard linear form:

$$ \frac{dy}{dx} - y = 2x $$

This is a linear first-order differential equation.

  1. Solve the Homogeneous Equation

First, we solve the associated homogeneous equation:

$$ \frac{dy}{dx} - y = 0 $$

The solution is:

$$ y_h = Ce^x $$

where (C) is a constant.

  1. Find a Particular Solution

Next, we find a particular solution (y_p). We can use the method of undetermined coefficients. Assuming a solution of the form:

$$ y_p = Ax + B $$

Substituting (y_p) into the equation gives us:

$$ A = 2 \quad \text{and} \quad B = -2 $$

Thus, the particular solution is:

$$ y_p = 2x - 2 $$

  1. Combine Solutions

Now, we combine the homogeneous and particular solutions:

$$ y = Ce^x + 2x - 2 $$

  1. Sketch the Solutions

(a) Sketch the solution curve through (0, -2)

To find (C), substitute the point ((0, -2)):

$$ -2 = Ce^0 + 2(0) - 2 \rightarrow C = 0 $$

Thus, the specific solution is:

$$ y = 2x - 2 $$

(b) Sketch the solution curve through (-1, 3)

Substituting ((-1, 3)):

$$ 3 = Ce^{-1} + 2(-1) - 2 \rightarrow 3 = Ce^{-1} - 4 \rightarrow C = 7e $$

Thus, the specific solution is:

$$ y = 7e^{x} - 2x - 2 $$

(c) Discussing Long-term Behavior

As ( x \rightarrow +\infty ):

  • The term ( 7e^{x} ) dominates, so ( y \rightarrow +\infty ).

As ( x \rightarrow -\infty ):

  • The term ( 7e^{x} ) tends to zero, leading to ( y \rightarrow -2 ).

(a) The specific solution curve through (0, -2) is

$$ y = 2x - 2 $$

(b) The specific solution curve through (-1, 3) is

$$ y = 7e^{x} - 2x - 2 $$

(c) As ( x \rightarrow +\infty ), ( y \rightarrow +\infty ) and as ( x \rightarrow -\infty ), ( y \rightarrow -2 ).

More Information

The equation $\frac{dy}{dx} = 2x + y$ is a linear first-order differential equation. The direction field demonstrates the behavior of solutions with different initial conditions, highlighting their long-term trends.

Tips

  • Forgetting to consider both the homogeneous and particular solutions.
  • Not correctly applying initial conditions to find constants.
  • Misinterpreting the direction field, leading to incorrect long-term behavior conclusions.

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