Simplify the expression $\log_a{\sqrt{a}} + \log_a{(a^2)}$

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Understand the Problem

The question asks us to simplify the logarithmic expression (\log_a{\sqrt{a}} + \log_a{(a^2)}). We will use properties of logarithms to combine and simplify these terms.

Answer

$\frac{5}{2}$
Answer for screen readers

$\frac{5}{2}$

Steps to Solve

  1. Rewrite the square root as an exponent Rewrite $\sqrt{a}$ as $a^{\frac{1}{2}}$. $$\log_a{\sqrt{a}} + \log_a{(a^2)} = \log_a{a^{\frac{1}{2}}} + \log_a{(a^2)}$$

  2. Apply the power rule of logarithms Use the property $\log_b{x^y} = y\log_b{x}$ to simplify the terms. $$\log_a{a^{\frac{1}{2}}} + \log_a{(a^2)} = \frac{1}{2}\log_a{a} + 2\log_a{a}$$

  3. Simplify $\log_a{a}$ Since $\log_a{a} = 1$, substitute 1 for $\log_a{a}$. $$\frac{1}{2}\log_a{a} + 2\log_a{a} = \frac{1}{2}(1) + 2(1) = \frac{1}{2} + 2$$

  4. Add the constants Add the two constants together. $$\frac{1}{2} + 2 = \frac{1}{2} + \frac{4}{2} = \frac{5}{2}$$

$\frac{5}{2}$

More Information

The logarithm $\log_a{x}$ answers the question, "To what power must $a$ be raised to produce $x$?" The expression simplifies to a constant, $\frac{5}{2}$. This means that $a^{\frac{5}{2}} = \sqrt{a} \cdot a^2$.

Tips

A common mistake is not remembering the power rule of logarithms, or not realizing that $\log_a{a} = 1$. Another mistake may involve arithmetical errors when adding the fractions.

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