In the triangle with dimensions 12, 30°, and 60°, find the height (h) and side (f).
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Understand the Problem
The question involves a right triangle with angles of 30° and 60°, and is asking to find the height (h) and side (f) related to given dimensions. We will apply trigonometric functions to determine these lengths.
Answer
The height is $h = 6$ and the side is $f = 6\sqrt{3}$.
Answer for screen readers
The height $h$ is 6, and the side $f$ is $6\sqrt{3}$.
Steps to Solve
- Identify the right triangle configuration
In a right triangle with angles of 30° and 60°, we can label the sides based on the known angle and the given length. The side opposite the 30° angle will be the smallest and can be denoted as $h$, while the side opposite the 60° angle will be the longer side denoted as $f$.
- Use sine to find height (h)
The sine function relates the angle to the opposite side over the hypotenuse. Here, we can use the formula
$$ \sin(30^\circ) = \frac{h}{12} $$
Since $ \sin(30^\circ) = \frac{1}{2} $, we have:
$$ \frac{1}{2} = \frac{h}{12} $$
Now, multiply both sides by 12 to isolate $h$:
$$ h = 12 \times \frac{1}{2} = 6 $$
- Use cosine to find side (f)
Next, we can find the length of side $f$ using the cosine function, which relates the angle to the adjacent side over the hypotenuse:
$$ \cos(30^\circ) = \frac{f}{12} $$
Since $ \cos(30^\circ) = \frac{\sqrt{3}}{2} $, we have:
$$ \frac{\sqrt{3}}{2} = \frac{f}{12} $$
Now, multiply both sides by 12 to solve for $f$:
$$ f = 12 \times \frac{\sqrt{3}}{2} = 6\sqrt{3} $$
The height $h$ is 6, and the side $f$ is $6\sqrt{3}$.
More Information
In a 30°-60°-90° triangle, the relationships between the lengths of the sides are fixed: the side opposite the 30° angle is half the hypotenuse, and the side opposite the 60° angle is $\sqrt{3}$ times the side opposite the 30° angle.
Tips
- Confusing which side corresponds to which angle could lead to incorrect application of sine and cosine functions.
- Forgetting to check the trigonometric values for sine and cosine at specific angles.
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