If a plant with genotype SsMm is self-fertilized, what proportion of the offspring will exhibit a wrinkled leaf phenotype?
Understand the Problem
The question describes a genetic scenario involving two genes. The first gene determines leaf texture (smooth or wrinkled), and the second is a modifier gene that can suppress the expression of the leaf texture gene. We need to calculate the proportion of offspring that will display the wrinkled leaf phenotype when a plant with the genotype SsMm is self-fertilized, taking into account the modifying effect of the 'mm' genotype.
Answer
Assuming 'm' is recessive and 'S' doesn't affect leaf phenotype, 25% of the offspring will have wrinkled leaves.
To determine the proportion of offspring with a wrinkled leaf phenotype from a self-fertilized SsMm plant, we need to know the dominance relationships. The search results do not provide enough information to answer the question. Assuming that wrinkled leaves are recessive and represented by 'mm', and that the 'S' allele is irrelevant to leaf phenotype, the proportion of offspring exhibiting the wrinkled leaf phenotype (mm) would be 1/4 or 25%.
Answer for screen readers
To determine the proportion of offspring with a wrinkled leaf phenotype from a self-fertilized SsMm plant, we need to know the dominance relationships. The search results do not provide enough information to answer the question. Assuming that wrinkled leaves are recessive and represented by 'mm', and that the 'S' allele is irrelevant to leaf phenotype, the proportion of offspring exhibiting the wrinkled leaf phenotype (mm) would be 1/4 or 25%.
More Information
The question cannot be definitively answered without knowing the dominance relationships of the alleles. The answer assumes a simple recessive inheritance for the wrinkled leaf trait.
Tips
A common mistake is not considering the dominance relationships between alleles when predicting phenotypes.
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