Find the perpendicular line of y = 1/3x + 5 that passes through the point (-2, 3).

Understand the Problem

The question is asking us to find the equation of a line that is perpendicular to the given line (y = 1/3x + 5) and passes through the point (-2, 3). To solve it, we'll first determine the slope of the perpendicular line and then use the point-slope form of the equation of a line.

Answer

The equation of the perpendicular line is $y = -3x - 3$.
Answer for screen readers

The equation of the line that is perpendicular to $y = \frac{1}{3}x + 5$ and passes through the point $(-2, 3)$ is:

$$ y = -3x - 3 $$

Steps to Solve

  1. Identify the slope of the given line

The equation of the given line is in the slope-intercept form $y = mx + b$, where $m$ is the slope. For the line $y = \frac{1}{3}x + 5$, the slope $m$ is $\frac{1}{3}$.

  1. Calculate the slope of the perpendicular line

The slope of a line that is perpendicular to another is the negative reciprocal of the original slope. Therefore, if the slope of the given line is $\frac{1}{3}$, the slope of the perpendicular line is:

$$ m_{perpendicular} = -\frac{1}{\frac{1}{3}} = -3 $$

  1. Use the point-slope form to find the equation

Now we will use the point-slope form of a line, which is given by:

$$ y - y_1 = m(x - x_1) $$

where $(x_1, y_1)$ is a point on the line. Here, the point is $(-2, 3)$, and the slope we found is $-3$. Substituting these values into the equation:

$$ y - 3 = -3(x + 2) $$

  1. Simplify the equation

Distributing the right side of the equation:

$$ y - 3 = -3x - 6 $$

Now, add 3 to both sides:

$$ y = -3x - 6 + 3 $$

This simplifies to:

$$ y = -3x - 3 $$

The equation of the line that is perpendicular to $y = \frac{1}{3}x + 5$ and passes through the point $(-2, 3)$ is:

$$ y = -3x - 3 $$

More Information

This equation represents a line with a slope of -3 that intersects the y-axis at -3. Perpendicular lines have slopes that multiply to -1, which confirms that the calculations are correct.

Tips

  • A common mistake is forgetting to take the negative reciprocal when calculating the slope of the perpendicular line. Always remember to invert the slope and change the sign.
  • Another mistake can be improperly applying the point-slope formula, especially when substituting the point coordinates. Carefully check the coordinates used in the formula.

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