Find the derivative of the function f(x) = 3√x - x^(-2). Also, find the equation of the normal to the graph of f(x) = x^3 - 5x.

Question image

Understand the Problem

The image shows a partially completed calculus problem. The initial problem is to find the derivative of f(x) = 3√x - x^(-2). The image also shows work towards finding the equation of the normal line to the graph of f(x) = x^3 - 5x, but the question is incomplete.

Answer

$f'(x) = \frac{3}{2\sqrt{x}} + 2x^{-3}$
Answer for screen readers

$f'(x) = \frac{3}{2\sqrt{x}} + 2x^{-3}$

Steps to Solve

  1. Rewrite the function using exponents

To easily apply the power rule, rewrite the square root and the negative exponent as follows:

$f(x) = 3x^{\frac{1}{2}} - x^{-2}$

  1. Apply the power rule to the first term

The power rule states that if $f(x) = ax^n$, then $f'(x) = n \cdot ax^{n-1}$. Applying this to the first term:

$\frac{d}{dx}(3x^{\frac{1}{2}}) = 3 \cdot \frac{1}{2} x^{\frac{1}{2}-1} = \frac{3}{2}x^{-\frac{1}{2}}$

  1. Apply the power rule to the second term

Applying the power rule to the second term:

$\frac{d}{dx}(-x^{-2}) = -(-2)x^{-2-1} = 2x^{-3}$

  1. Combine the derivatives

Using the difference rule, combine the derivatives of the two terms:

$f'(x) = \frac{3}{2}x^{-\frac{1}{2}} + 2x^{-3}$

  1. Rewrite with radicals and positive exponents

Rewrite the derivative using radicals and positive exponents to match the answer in the image:

$f'(x) = \frac{3}{2\sqrt{x}} + \frac{2}{x^3}$ or $f'(x) = \frac{3}{2\sqrt{x}} + 2x^{-3}$ This is the exact solution in the image

$f'(x) = \frac{3}{2\sqrt{x}} + 2x^{-3}$

More Information

The derivative $f'(x)$ represents the slope of the tangent line to the curve of $f(x)$ at any point $x$.

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