Calculate the percentage decrease, percentage increase or decrease, or the new value after an increase or decrease for each problem.

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Understand the Problem

The image contains math problems related to percentage increase and decrease. The problems vary in context, including simple numerical decreases, decreases involving units of measurement (meters, kilograms, degrees Celsius, milliliters), and increases.

Answer

2. (a) 20% (b) 28% (c) 25% (d) 75% 3. (a) 8 (b) 12 (c) 105 $m^2$ (d) 12 °C 4. (a) 81 (b) 264 (c) 165 hours (d) 42 mL
Answer for screen readers
  1. (a) 20% (b) 28% (c) 25% (d) 75%
  2. (a) 8 (b) 12 (c) 105 $m^2$ (d) 12 °C
  3. (a) 81 (b) 264 (c) 165 hours (d) 42 mL

Steps to Solve

  1. 2(a): Calculate the percentage decrease

To find the percentage decrease, divide the amount of the decrease by the original amount, then multiply by 100. $Percentage\ Decrease = \frac{Decrease}{Original\ Amount} \times 100$ In this case, the decrease is 6 and the original amount is 30. $Percentage\ Decrease = \frac{6}{30} \times 100 = 0.2 \times 100 = 20$%

  1. 2(b): Calculate the percentage decrease

The original amount is 25 and the new amount is 18. The decrease is $25 - 18 = 7$. $Percentage\ Decrease = \frac{7}{25} \times 100 = 0.28 \times 100 = 28$%

  1. 2(c): Calculate the percentage decrease

The decrease is 15 m and the original amount is 60 m. $Percentage\ Decrease = \frac{15}{60} \times 100 = 0.25 \times 100 = 25$%

  1. 2(d): Calculate the percentage decrease

The original amount is 56 kg, and the new amount is 14 kg. The decrease is $56 - 14 = 42$ kg. $Percentage\ Decrease = \frac{42}{56} \times 100 = 0.75 \times 100 = 75$%

  1. 3(a): Calculate the increase

To increase 50 by 16%, we multiply 50 by 16% (or 0.16) to find the amount of the increase. $Increase = 50 \times 0.16 = 8$

  1. 3(b): Calculate the decrease

To decrease 48 by 25%, we multiply 48 by 25% (or 0.25) to find the amount of the decrease. $Decrease = 48 \times 0.25 = 12$

  1. 3(c): Calculate the increase

To increase 70 $m^2$ by 150%, we multiply 70 by 150% (or 1.50) to find the amount of the increase. $Increase = 70 \times 1.50 = 105\ m^2$

  1. 3(d): Calculate the decrease

To decrease 80°C by 15%, we multiply 80 by 15% (or 0.15) to find the amount of the decrease. $Decrease = 80 \times 0.15 = 12\ °C$

  1. 4(a): Calculate the new value

To increase 75 by 8%, first calculate the increase: $75 \times 0.08 = 6$. Then add this to the original value: $75 + 6 = 81$. $New\ Value = 81$

  1. 4(b): Calculate the new value

To decrease 300 by 12%, first calculate the decrease: $300 \times 0.12 = 36$. Then subtract this from the original value: $300 - 36 = 264$. $New\ Value = 264$

  1. 4(c): Calculate the new value

To increase 125 hours by 32%, first calculate the increase: $125 \times 0.32 = 40$. Then add this to the original value: $125 + 40 = 165$. $New\ Value = 165\ hours$

  1. 4(d): Calculate the new value

To decrease 168 mL by 75%, first calculate the decrease: $168 \times 0.75 = 126$. Then subtract this from the original value: $168 - 126 = 42$. $New\ Value = 42\ mL$

  1. (a) 20% (b) 28% (c) 25% (d) 75%
  2. (a) 8 (b) 12 (c) 105 $m^2$ (d) 12 °C
  3. (a) 81 (b) 264 (c) 165 hours (d) 42 mL

More Information

Percentage increase/decrease problems are common in everyday life, such as calculating discounts, interest rates, or changes in population size.

Tips

A common mistake is dividing by the wrong amount when calculating percentage decrease. Always divide by the original amount. Additionally, students might forget to multiply by 100 to convert the decimal to a percentage. Also, in problems 3 and 4, students might misinterpret whether they have to find the amount of increase/decrease or the final value after the increase/decrease.

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