Calculate the average of the discrete series using the short-cut method by taking 25 as the assumed average.

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Understand the Problem

The question asks to calculate the average of a discrete series using the short-cut method, assuming 25 as the assumed average. This involves using frequency data of different sizes to determine the mean value.

Answer

$24.925$
Answer for screen readers

$24.925$

Steps to Solve

  1. Calculate the deviations from the assumed mean

Let $A$ be the assumed mean, which is $25$. The deviation $d_i$ for each size $x_i$ is calculated as $d_i = x_i - A$.

Here are all the deviations: $30 - 25 = 5$ $29 - 25 = 4$ $28 - 25 = 3$ $27 - 25 = 2$ $26 - 25 = 1$ $25 - 25 = 0$ $24 - 25 = -1$ $23 - 25 = -2$ $22 - 25 = -3$ $21 - 25 = -4$

  1. Multiply each deviation by its corresponding frequency

Multiply each $d_i$ by its corresponding frequency $f_i$ to get $f_i d_i$.

Here are the $f_i d_i$ values: $5 * 2 = 10$ $4 * 4 = 16$ $3 * 5 = 15$ $2 * 3 = 6$ $1 * 2 = 2$ $0 * 7 = 0$ $-1 * 1 = -1$ $-2 * 4 = -8$ $-3 * 5 = -15$ $-4 * 7 = -28$

  1. Calculate the sum of the products of frequency and deviations

Calculate $\sum f_i d_i$ by adding up all the values calculated in Step 2.

$\sum f_i d_i = 10 + 16 + 15 + 6 + 2 + 0 - 1 - 8 - 15 - 28 = -3$

  1. Calculate the sum of the frequencies

Calculate $\sum f_i$. $\sum f_i = 2 + 4 + 5 + 3 + 2 + 7 + 1 + 4 + 5 + 7 = 40$

  1. Apply the short-cut formula for calculating the mean

The formula for the mean using the short-cut method is: $\text{Mean} = A + \frac{\sum f_i d_i}{\sum f_i}$

Substitute the values we calculated: $\text{Mean} = 25 + \frac{-3}{40} = 25 - 0.075 = 24.925$

$24.925$

More Information

The short-cut method simplifies the calculation of the mean, especially when dealing with large numbers or a wide range of data, by using an assumed mean as a reference point.

Tips

A common mistake is to forget to multiply the deviations by their corresponding frequencies. Another mistake is in the arithmetic when calculating the sum of the deviations multiplied by frequencies or the sum of the frequencies.

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