A solid of mass 100g at a temperature of 90°C is placed in 100g of water at 20°C in a container of negligible heat capacity. If the final steady temperature is 60°C, calculate the... A solid of mass 100g at a temperature of 90°C is placed in 100g of water at 20°C in a container of negligible heat capacity. If the final steady temperature is 60°C, calculate the specific heat capacity of the solid (specific heat capacity of water equals to 4.2 x 10³ j/kg/K). Read more

Understand the Problem

The question asks to calculate the specific heat capacity of a solid. We can apply the principle of calorimetry, which states that the heat lost by the solid is equal to the heat gained by the water. We'll use the formula Q = mcΔT, where Q is the heat exchanged, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. We will set the heat lost by the solid equal to the heat gained by the water and solve for the specific heat capacity of the solid.