A new dog park is being designed by a city planner. The park is enclosed by a fence and shaped like a parallelogram. What is the area and perimeter of the dog park? Round your answ... A new dog park is being designed by a city planner. The park is enclosed by a fence and shaped like a parallelogram. What is the area and perimeter of the dog park? Round your answers to the nearest hundredth, if necessary.
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Understand the Problem
The question asks us to find the area and perimeter of a parallelogram-shaped dog park. The coordinates of the vertices of the parallelogram are given in a coordinate plane where 1 unit equals 5 meters. We need to calculate the side lengths using the distance formula and then use these to find the perimeter and area. Finally, you must round the answers to the nearest hundredth.
Answer
Perimeter $\approx 203.30$ meters Area $= 2125.00$ square meters
Answer for screen readers
Perimeter $\approx 203.30$ meters Area $= 2125.00$ square meters
Steps to Solve
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Calculate the lengths of the sides of the parallelogram
We use the distance formula to find the lengths of the sides. The distance formula is $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Let's find the length of the side between $(-8, 0)$ and $(-4, -5)$: $d_1 = \sqrt{((-4) - (-8))^2 + ((-5) - 0)^2} = \sqrt{(4)^2 + (-5)^2} = \sqrt{16 + 25} = \sqrt{41}$. Now let's find the length of the side between $(-4, -5)$ and $(9, 0)$: $d_2 = \sqrt{(9 - (-4))^2 + (0 - (-5))^2} = \sqrt{(13)^2 + (5)^2} = \sqrt{169 + 25} = \sqrt{194}$.
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Calculate the perimeter of the parallelogram
The perimeter of a parallelogram is $2(a + b)$, where $a$ and $b$ are the lengths of the adjacent sides. In this case, $a = \sqrt{41}$ and $b = \sqrt{194}$. Since 1 unit = 5 meters, we need to multiply each length by 5 to convert it into meters before calculating the perimeter. So, the perimeter is $2(5\sqrt{41} + 5\sqrt{194}) = 10(\sqrt{41} + \sqrt{194}) \approx 10(6.40 + 13.93) = 10(20.33) = 203.3$ meters.
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Calculate the area of the parallelogram
We can find the area using the determinant method with the coordinates of the vertices. List the coordinates in a cycle: $(-8, 0)$, $(-4, -5)$, $(9, 0)$, $(5, 5)$, $(-8, 0)$. The area is given by $A = \frac{1}{2} |(x_1y_2 + x_2y_3 + x_3y_4 + x_4y_5) - (y_1x_2 + y_2x_3 + y_3x_4 + y_4x_5)|$. $A = \frac{1}{2} |((-8)(-5) + (-4)(0) + (9)(5) + (5)(0)) - ((0)(-4) + (-5)(9) + (0)(5) + (5)(-8))|$ $A = \frac{1}{2} |(40 + 0 + 45 + 0) - (0 - 45 + 0 - 40)| = \frac{1}{2} |85 - (-85)| = \frac{1}{2} |170| = 85$ square units. Since 1 unit = 5 meters, 1 square unit = $5^2 = 25$ square meters. So, the area in square meters is $85 \times 25 = 2125$ square meters.
Perimeter $\approx 203.30$ meters Area $= 2125.00$ square meters
More Information
The area calculation using the determinant method works because it essentially calculates the area of the parallelogram using vectors formed by the vertices.
Tips
A common mistake is forgetting to convert the lengths in units to meters by multiplying by 5. Also, when calculating the area using determinant, sign errors can occur if not careful. Another common error is in the arithmetic itself.
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