∫ (1 / (x√(x² - a²))) dx = (1/a) sec⁻¹(x/a) + c
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Understand the Problem
The question presents an integral that is being solved, showing the solution process for integrating the given function involving x and a, where both variables appear in a specific algebraic form under a square root. The high-level approach includes applying integration techniques relevant to the problem.
Answer
The integral evaluates to $$ \frac{1}{a} \sec^{-1}\left(\frac{x}{a}\right) + c $$
Answer for screen readers
The final answer is
$$ \int \frac{1}{x \sqrt{x^2 - a^2}} , dx = \frac{1}{a} \sec^{-1}\left(\frac{x}{a}\right) + c $$
Steps to Solve
- Identify the integral form
We start with the integral
$$ \int \frac{1}{x \sqrt{x^2 - a^2}} , dx $$
This requires recognizing how we can manipulate the expression to facilitate integration.
- Use substitution
We use the substitution
$$ x = a \sec(\theta) $$
This leads to
$$ dx = a \sec(\theta) \tan(\theta) , d\theta $$
- Substitute in the integral
Now, substituting into the integral we get
$$ \int \frac{1}{a \sec(\theta) \sqrt{(a \sec(\theta))^2 - a^2}} \cdot a \sec(\theta) \tan(\theta) , d\theta $$
This simplifies since
$$ (a \sec(\theta))^2 - a^2 = a^2(\sec^2(\theta) - 1) = a^2 \tan^2(\theta) $$
- Simplify the integrand
The integral now looks like
$$ \int \frac{a \sec(\theta) \tan(\theta)}{a \sec(\theta) \sqrt{a^2 \tan^2(\theta)}} , d\theta $$
This further simplifies to
$$ \int d\theta $$
- Integrate
Integrating gives
$$ \theta + C $$
- Back substitute
Recall our substitution
$$ \theta = \sec^{-1}\left(\frac{x}{a}\right) $$
Therefore, the final answer becomes
$$ \frac{1}{a} \sec^{-1}\left(\frac{x}{a}\right) + C $$
The final answer is
$$ \int \frac{1}{x \sqrt{x^2 - a^2}} , dx = \frac{1}{a} \sec^{-1}\left(\frac{x}{a}\right) + c $$
More Information
This result is important in calculus and is often used in physics and engineering, particularly in problems involving hyperbolic functions and integrals related to certain geometric properties. The inverse secant function appears in many contexts, including relativity and other areas of analysis.
Tips
- Forgetting to correctly apply the chain rule when substituting.
- Neglecting to simplify radicals properly during substitution.
- Confusing secant and cosecant functions, especially when dealing with inverse trigonometric identities.
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