Podcast
Questions and Answers
The final velocity of a body thrown vertically upwards becomes zero at its maximum height.
The final velocity of a body thrown vertically upwards becomes zero at its maximum height.
True
The equation $y = v_0t + rac{1}{2}gt^2$ is used for vertical upward motion.
The equation $y = v_0t + rac{1}{2}gt^2$ is used for vertical upward motion.
False
The maximum height can be calculated using the formula $Y_{max} = rac{v_0^2}{2g}$.
The maximum height can be calculated using the formula $Y_{max} = rac{v_0^2}{2g}$.
True
The equation $v_t^2 = v_0^2 - 2gy$ is specific to downward motion only.
The equation $v_t^2 = v_0^2 - 2gy$ is specific to downward motion only.
Signup and view all the answers
Acceleration due to gravity is represented by the variable $g$.
Acceleration due to gravity is represented by the variable $g$.
Signup and view all the answers
Study Notes
Vertical Motion Upwards
- $v_0$: Initial velocity (m/s), this is the velocity when the object starts moving upwards
- $v_t$: Final velocity (m/s), this the velocity at any time, but particularly at the maximum height, where the object momentarily stops before falling
- $y$: Vertical distance traveled (m)
- $t$: Time (s), this is the time the object is moving upwards
- $g$: Acceleration due to gravity (m/s²), this is the force pulling the object down, represented by 9.8 m/s²
Equations of Motion
- $v_t = v_0 + at$: This equation is used to calculate the final velocity (v_t) of an object moving upwards at time (t), knowing its initial velocity (v_0) and the acceleration due to gravity (g).
- $y = v_0t + \frac{1}{2}gt^2$: This equation helps calculate the vertical distance (y) traveled by the object after a time (t), knowing the initial velocity (v_0) and the acceleration due to gravity (g).
- $v_t^2 = v_0^2 + 2gy$: This equation calculates the final velocity (v_t) knowing the initial velocity (v_0), the vertical distance (y) and the acceleration due to gravity (g).
Specific Equations for Upward Motion
- $v_t = v_0 - gt$: This equation is used to find the final velocity (v_t) knowing the initial velocity (v_0), the acceleration due to gravity (g) and the time (t)
- $y = v_0t - \frac{1}{2}gt^2$: This equation helps calculate the vertical distance (y) traveled by the object after a time (t), knowing the initial velocity (v_0) and the acceleration due to gravity (g).
- $v_t^2 = v_0^2 - 2gy$: This equation calculates the final velocity (v_t) knowing the initial velocity (v_0), the vertical distance (y) and the acceleration due to gravity (g).
Maximum Height
- The final velocity at the maximum height is zero. This helps calculate the maximum height using the following equation:
- $Y_{max} = \frac{v_0^2}{2g}$
- This equation uses the initial velocity (v_0) and the acceleration due to gravity (g) to calculate the maximum height.
Visual Representation
- A simple diagram represents an object thrown upwards with Point A as the initial point and Point B as the maximum height reached.
- The diagram also shows the downward motion of the object from Point B to Point A, although this is not explicitly mentioned in the text.
Studying That Suits You
Use AI to generate personalized quizzes and flashcards to suit your learning preferences.
Description
Test your understanding of vertical motion, focusing on objects moving upwards. This quiz covers key concepts like initial and final velocity, acceleration due to gravity, and relevant equations of motion. Assess your grasp of how these factors influence the motion of objects in physics.
