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Questions and Answers
The final velocity of a body thrown vertically upwards becomes zero at its maximum height.
The final velocity of a body thrown vertically upwards becomes zero at its maximum height.
True (A)
The equation $y = v_0t + rac{1}{2}gt^2$ is used for vertical upward motion.
The equation $y = v_0t + rac{1}{2}gt^2$ is used for vertical upward motion.
False (B)
The maximum height can be calculated using the formula $Y_{max} = rac{v_0^2}{2g}$.
The maximum height can be calculated using the formula $Y_{max} = rac{v_0^2}{2g}$.
True (A)
The equation $v_t^2 = v_0^2 - 2gy$ is specific to downward motion only.
The equation $v_t^2 = v_0^2 - 2gy$ is specific to downward motion only.
Acceleration due to gravity is represented by the variable $g$.
Acceleration due to gravity is represented by the variable $g$.
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Study Notes
Vertical Motion Upwards
- $v_0$: Initial velocity (m/s), this is the velocity when the object starts moving upwards
- $v_t$: Final velocity (m/s), this the velocity at any time, but particularly at the maximum height, where the object momentarily stops before falling
- $y$: Vertical distance traveled (m)
- $t$: Time (s), this is the time the object is moving upwards
- $g$: Acceleration due to gravity (m/s²), this is the force pulling the object down, represented by 9.8 m/s²
Equations of Motion
- $v_t = v_0 + at$: This equation is used to calculate the final velocity (v_t) of an object moving upwards at time (t), knowing its initial velocity (v_0) and the acceleration due to gravity (g).
- $y = v_0t + \frac{1}{2}gt^2$: This equation helps calculate the vertical distance (y) traveled by the object after a time (t), knowing the initial velocity (v_0) and the acceleration due to gravity (g).
- $v_t^2 = v_0^2 + 2gy$: This equation calculates the final velocity (v_t) knowing the initial velocity (v_0), the vertical distance (y) and the acceleration due to gravity (g).
Specific Equations for Upward Motion
- $v_t = v_0 - gt$: This equation is used to find the final velocity (v_t) knowing the initial velocity (v_0), the acceleration due to gravity (g) and the time (t)
- $y = v_0t - \frac{1}{2}gt^2$: This equation helps calculate the vertical distance (y) traveled by the object after a time (t), knowing the initial velocity (v_0) and the acceleration due to gravity (g).
- $v_t^2 = v_0^2 - 2gy$: This equation calculates the final velocity (v_t) knowing the initial velocity (v_0), the vertical distance (y) and the acceleration due to gravity (g).
Maximum Height
- The final velocity at the maximum height is zero. This helps calculate the maximum height using the following equation:
- $Y_{max} = \frac{v_0^2}{2g}$
- This equation uses the initial velocity (v_0) and the acceleration due to gravity (g) to calculate the maximum height.
Visual Representation
- A simple diagram represents an object thrown upwards with Point A as the initial point and Point B as the maximum height reached.
- The diagram also shows the downward motion of the object from Point B to Point A, although this is not explicitly mentioned in the text.
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