Theory of Computation Lecture 3

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Questions and Answers

What represents the accept state in the pattern recognition process described?

  • q
  • q001 (correct)
  • q00
  • q0

Which transition occurs when reading a 1 while in the state q00?

  • Moves to q001 (correct)
  • Moves to q0
  • Moves to q
  • Stays in q00

Which of the following operations is considered a unary operation?

  • Concatenation
  • Intersection
  • Union
  • Star operation (correct)

What is the purpose of the concatenation operation in the context of languages?

<p>To combine strings from two languages into one (C)</p> Signup and view all the answers

What is included in the set A* when A = {good, bad}?

<p>All combinations and repetitions of good and bad (C)</p> Signup and view all the answers

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Study Notes

Formal Definition of Computation

  • A finite automaton M is defined as a 5-tuple: M = (Q, Σ, δ, q0, F).
  • A string w = w1w2...wn consists of symbols from the alphabet Σ.
  • M accepts w if there exists a sequence of states r0, r1,..., rn in Q meeting three conditions:
    • r0 is the initial state q0.
    • Transition δ(r_i, w_{i+1}) leads to r_{i+1} for i = 0,..., n-1.
    • The final state rn must be in the set of accepting states F.
  • M recognizes language A defined as A = {w | M accepts w}.

Designing Finite Automata

  • To design a finite automaton to recognize strings with an odd number of 1s:
    • Track whether the count of 1s so far is even or odd instead of remembering the entire string.
    • Transition states are defined as:
      • State q_even (even number of 1s).
      • State q_odd (odd number of 1s).
    • On reading a 1, transition from q_even to q_odd, and vice versa. Reading a 0 retains the current state.
  • The start state for the automaton is q_even, accepting state is q_odd (as it represents odd occurrences).

Example of Recognizing Substrings

  • A finite automaton E2 for recognizing the pattern "001":
    • Represents four states based on the substring seen:
      • q (no symbols seen).
      • q0 (one 0 seen).
      • q00 (two 0s seen).
      • q001 (substring "001" seen).
    • Transition rules:
      • From q, stay in q for 1, move to q0 for 0.
      • From q0, move to q for 1, go to q00 for 0.
      • From q00, move to q001 for 1, stay in q00 for 0.
      • In q001, remain in q001 for any input.
    • The start state is q, and only the state q001 is accepting.

Regular Operations on Languages

  • Union: Combines strings from two languages A and B into one language.
  • Concatenation: Attaches strings from A in front of strings from B producing new strings in the resulting language.
  • Star Operation: A unary operation applied to a single language A, concatenating any number of strings in A to create new strings in the language. The empty string "" is always included in A*.
  • Example with the alphabet {a, b, ..., z}:
    • A = {good, bad} and B = {boy, girl} results in:
      • Union: A ∪ B = {good, bad, boy, girl}
      • Concatenation: A ∩ B = {goodboy, goodgirl, badboy, badgirl}
      • Star: A* = {", good, bad, goodgood, badbad,...}

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