Statics: Moment of Force and Free Body Diagrams
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Questions and Answers

In structural analysis, what does a Free Body Diagram (FBD) primarily represent?

  • A diagram showing only the external dimensions of a structure.
  • A representation of a particle or rigid body isolated from its surroundings, showing all applied forces and reactions. (correct)
  • A graphical method for solving complex kinematic problems.
  • A detailed illustration of the internal stresses within a body.

According to Newton's first law of motion, an object will remain at rest only if no forces are acting on it.

False (B)

Briefly explain the condition for equilibrium in a two-dimensional system.

For a body to be in equilibrium in a 2D system, the sum of the forces in both the x and y directions must be zero, and the sum of the moments about any point must also equal zero.

In the context of forces, forces are applied at the same point or particle.

<p>concurrent</p> Signup and view all the answers

Which of the following conditions must be met for forces acting on a particle to be in equilibrium?

<p>The sum of the forces in both the x and y directions must equal zero. (A)</p> Signup and view all the answers

What characterizes collinear forces?

<p>Forces acting along the same line of action. (D)</p> Signup and view all the answers

The moment of a force is always a positive value.

<p>False (B)</p> Signup and view all the answers

What is the first step in analyzing forces?

<p>Draw a Free Body Diagram (FBD).</p> Signup and view all the answers

A body will remain or constant velocity unless acted upon by a force.

<p>at rest</p> Signup and view all the answers

In a two-dimensional equilibrium problem, if $\Sigma Fx = 0$ and $\Sigma Fy = 0$, what can be definitively concluded?

<p>The body may be in translational equilibrium but not necessarily rotational equilibrium. (B)</p> Signup and view all the answers

Match the following terms with their descriptions:

<p>Equilibrium = A state where the net force and net torque on a system are zero. Concurrent Forces = Forces whose lines of action intersect at a common point. Collinear Forces = Forces acting along the same line. Free Body Diagram = A diagram showing all forces acting on an isolated object or system.</p> Signup and view all the answers

Consider a beam subjected to a single force P at a certain point. If the moment of force P with respect to point A is negative, what does this imply?

<p>The force P causes a clockwise rotation about point A. (B)</p> Signup and view all the answers

If a body is in equilibrium, it implies that there are no forces acting on it.

<p>False (B)</p> Signup and view all the answers

Briefly describe how to determine whether the moment of a force about a point is positive or negative.

<p>The direction of the rotation caused by the force determines its sign. Counterclockwise rotation is typically considered positive, while clockwise rotation is negative.</p> Signup and view all the answers

In analyzing structural equilibrium, if the sum of the forces in the x and y directions is zero, but the sum of the moments is not, the body is in equilibrium.

<p>translational</p> Signup and view all the answers

Flashcards

What is a moment of force?

The turning effect of a force around a point. It can be either positive or negative depending on the direction of the force relative to the point.

What is a Free Body Diagram (FBD)?

A diagram representing a particle or rigid body isolated from its surroundings, showing all applied forces and reactions.

What are Concurrent Forces?

Forces whose lines of action intersect at a single point.

What are Collinear Forces?

Forces acting along the same line of action.

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What is Newton's First Law of Motion?

A body will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

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What is Two-Dimensional Equilibrium?

The condition where the sum of forces and moments acting on a body equals zero, resulting in no net force or rotation.

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What are Lark vs. Owl preferences?

A learning preference for mornings (lark) or evenings (owl), affecting productivity.

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Study Notes

  • Read Book 1, pages 60-73, and Book 2, Chapter 3
  • Complete problem 2.28 on page 72
  • In groups, complete problems 2.29 and 2.30 on page 72
  • Homework 5: complete problems 2.29 and 2.30 on page 72
  • Review lectures L1, L2, L3, L4, and L5 for a quiz next week

Moment of Force P with Respect to A

  • Determine if the moment of force P with respect to point A is negative or positive
  • The direction of the force and its distance from point A affects the sign of the moment

Free Body Diagrams (FBD)

  • A free body diagram (FBD) represents a particle, joint, or rigid body isolated from its surroundings
  • It shows all applied forces and reactions acting on the body
  • Free Body Diagrams include:
    • Externally applied forces and moments
    • The weight of the rigid body
    • Reactions forces and moment reactions (or constraints)
    • Forces developed within a sectioned member

Two-Dimensional Equilibrium (XY Plane)

  • Rx = ∑Fx = 0
  • Ry = ∑Fy = 0
  • Mi = ∑Mi = 0; where i = any point

Collinear Forces

  • Forces act along the same line
  • If an elevator with Joe (180 lbs) and Ana moves at a constant speed and is in equilibrium, then ∑Fy = 0 = T - Fj - Fa; 0 = 300 lb - 180 - Fa, so Fa = 120 lb
  • If T = 250 lb, and Ana and Joe (same weight as before) take the elevator again, the elevator is not in equilibrium because Σ Fy = T - F」 - FA = 250 lb - 180 - 120 = -50 lb ≠ 0
  • The elevator is changing velocity, accelerating downward

Concurrent Forces

  • Forces applied at the same point or particle
  • For forces to be in equilibrium, the following equations apply: ΣFx = 0 and ΣFy = 0
  • An example: ΣFx = 0 = - Sac Cos 40 + Sab Cos 50, ΣFy = 0 = Sac Sin 40 + Sab Sin 50 – 10
    • After solving: Sab Cos50 Sin40 + Sab Sin50 Cos40 – 10 Cos40 = 0, therefore Sab = 7.66 lb
    • Substituting reveals: Sac = 6.42 lb

FBD and Equilibrium of Particles

  • Free body diagrams include concurrent forces at a particle or point in the structure
  • Equations of equilibrium for a particle: ΣFx = 0 and ΣFy = 0
  • Case 2 Example:
    • ΣFx = 0 = - Sba - Sbc Cos 30
    • ΣFy = 0 = Sbc Sin 30 - 1000
    • Solving for Sbc in equation 2: Sbc = 1000 / sin 30 = 2000 lb
    • Substituting in equation 1 and solving for Sba: Sba = -Sbc Cos 30 = - 2000 x Cos 30 = - 1732 lb

Newton’s First Law of Motion

  • A body remains at rest or at a constant velocity unless a force acts upon it

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Learn about the moment of force and free body diagrams (FBD) used to represent forces on a rigid body. Understand how to determine the sign of a moment with respect to a point. Comprehend the conditions for two-dimensional equilibrium in the XY plane.

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