Solving Separable Equations in Differential Equations
12 Questions
19 Views

Solving Separable Equations in Differential Equations

Created by
@InvincibleViolet

Questions and Answers

Separable equations can be written as y' = P(X)Q(Y), where P(X) and Q(Y) are continuous functions.

True

The equation 2xy - 1 dX + x^2 - 1 dy = z, has the formal solution ln(x^2 - 1)(y - 1) = C, with the restriction that X is not equal to +/-1 and y is not equal to 1.

False

The video provides an example of finding the general solution for the equation 1 + e^(-y) dX - e^(-2y) sin(Q(x)) dy = 0, with the initial value y = Pi/2 = 0.

False

Singular points are points where a differential equation is not separable and require separate discussion.

<p>True</p> Signup and view all the answers

The differential equation DP/DT = t/(t^2 + 1) * P(T) is separable

<p>True</p> Signup and view all the answers

The left area of a circular plant leaf is directly proportional to the intensity of light

<p>False</p> Signup and view all the answers

The angle, Θ(T), is a linear function of time between sunrise and sunset

<p>True</p> Signup and view all the answers

The temperature at a distance of 8 cm from the center of the hollow iron ball can be solved using the given temperature gradient and thermal conductivity

<p>False</p> Signup and view all the answers

Homogeneous equations are defined as functions G(x, y) that maintain the same degree when all variables are multiplied by a nonzero constant.

<p>True</p> Signup and view all the answers

To solve a differential equation dy/dx = x² + y²/xy, a substitution is made by letting y = Vx, resulting in a separable equation.

<p>False</p> Signup and view all the answers

A nonlinear differential equation y' = F(ax + b, y + C) can be transformed into a new equation when taking the derivative, resulting in V' = a + bF(V).

<p>True</p> Signup and view all the answers

The general solution for the differential equation dy/dx = x² + y²/xy is found by integrating both sides and solving for V, resulting in Ln(Cx) or Ln(C) + Ln(x).

<p>True</p> Signup and view all the answers

Study Notes

  • The video discusses the concept of separable equations in the context of solving differential equations.
  • An equilibrium point or stationary point is a constant solution to a differential equation, which holds for all X in the given domain.
  • Separable equations are a type of differential equation where the function F(X,Y) is a product of a function of X and a function of Y.
  • Separable equations can be written as y' = P(X)Q(Y), where P(X) and Q(Y) are continuous functions.
  • To solve a separable equation, divide both sides by Q(Y) to get y' = P(X)/Q(Y).
  • Integrating both sides and assuming u = Y, the general solution can be written in implicit form as ∫1/Q(Y)dY + C = ∫P(X)dX.
  • Singular points are points where a differential equation is not separable and require separate discussion.
  • Given the equation 2xy - 1 dX + x^2 - 1 dy = z, the formal solution is ln(x^2 - 1)(y - 1) = C, with the restriction that X is not equal to +/-1 and y is not equal to 1.
  • The video provides an example of finding the general solution for the equation 1 + e^(-y) dX - e^(-2y) sin(Q(x)) dy = 0, with the initial value y = Pi/2 = 0.
  • The equation has infinite constant solutions, and the solution for x = n (an integer) is not valid if n is not in the domain of sin(cx)^3.
  • The video invites the audience for further exercise in continuing the solution for the example problem.
  • The video concludes by encouraging questions and subscribing for more videos.

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

Description

Learn to solve separable equations and understand concepts like equilibrium points, singular points, and general solutions in the context of differential equations. The video provides examples and encourages further practice.

More Quizzes Like This

Use Quizgecko on...
Browser
Browser