Applications of Separable Equations in Differential Equations
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Questions and Answers

The differential equation dP/dt = t/(t^2 + 1) * P is separable.

True

The solution of the differential equation in the second example involves integrating I(t) = beta * s(t) * cos(Pi/12 * (t-6)).

False

The intensity of light is proportional to the area and the cosine of the angle between the light beam direction and the vertical.

True

The angle between the light beam and the vertical is assumed to be a quadratic function of time T.

<p>False</p> Signup and view all the answers

The temperature gradient is represented by DT/Dr, and the solution is found using the given initial conditions and the constant thermal conductivity.

<p>True</p> Signup and view all the answers

The solution for the temperature at a distance R from the center is given as T(R) = Q / (4πKR + K).

<p>False</p> Signup and view all the answers

The first example in the video discusses the growth of the right area of a circular leaf.

<p>False</p> Signup and view all the answers

The inner and outer radii of the hollow iron ball have the same temperature dependence on time and distance.

<p>False</p> Signup and view all the answers

Study Notes

  • The video discusses the applications of separable equations in differential equations, using two examples.
  • The first example is about the growth of a population described by the differential equation dP/dt = t/t^2 + 1 * P, where P(t) is the population function at time t.
  • The equation is separable, allowing the separation of variables: dP/P = t dt / t^2 + 1.
  • The solution is found by integrating both sides and obtaining ln(P(t)) = 12ln(t^2 + 1) + C.
  • The second example discusses the growth of the left area of a circular leaf, with the area being proportional to the left radius and the intensity of light.
  • The intensity of light is proportional to the area and the cosine of the angle between the light beam direction and the vertical.
  • The angle between the light beam and the vertical is assumed to be a linear function of time T.
  • The solution for the intensity is obtained by integrating I(t) = beta * s(t) * cos(Pi/12 * (t-6)).
  • A hollow iron ball's temperature is dependent on time and distance, with the inner and outer radii having different temperatures.
  • The temperature gradient is represented by DT/Dr, and the solution is found using the given initial conditions and the constant thermal conductivity.
  • The solution for the temperature at a distance R from the center is given as T(R) = Q / (4πKR + K).

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Explore the applications of separable equations in differential equations through examples involving population growth, leaf area growth, and temperature distribution in an iron ball. Understand the process of solving separable equations and applying them to real-world scenarios.

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