Solving Exponential Equations

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Questions and Answers

To solve the exponential equation $5^{2x+1} = 125$, which of the following is the correct first step?

  • Express 125 as $5^3$. (correct)
  • Subtract 1 from both sides.
  • Take the logarithm of both sides.
  • Divide both sides by 5.

Given the equation $4^{x} = 8^{(x-1)}$, identify the correct common base to rewrite both sides of the equation.

  • 2 (correct)
  • 8
  • 16
  • 4

Solve for x in the equation $9^{x+1} = 27^{x}$.

  • x = -2
  • x = 2 (correct)
  • x = 3
  • x = -3

What is the value of x in the equation $2^{x} = 10$, rounded to four decimal places?

<p>3.3219 (D)</p> Signup and view all the answers

Solve for x in the equation $e^{2x} = 5$.

<p>x = ln(5)/2 (C)</p> Signup and view all the answers

Determine the value of x in the following equation: $7 + 3^{x-4} = 16$

<p>x = 4 + log(9) / log(3) (C)</p> Signup and view all the answers

Find x if $5 + 2e^{2-x} = 11$.

<p>x = 2 - ln(3) (A)</p> Signup and view all the answers

Solve for x: $2^{x^2 - x} = \frac{1}{4}$

<p>x = -2, x = 1 (D)</p> Signup and view all the answers

Determine the solutions for x in the equation $5^{x^2} \cdot 5^{2x} = 625$.

<p>x = -4, x = 1 (C)</p> Signup and view all the answers

Given $9^{x} - 10 \cdot 3^{x} + 9 = 0$, use substitution to find the values of x.

<p>x = 0, x = 2 (C)</p> Signup and view all the answers

Find the value of x in the equation: $2^{2x} - 3 \cdot 2^{2x-2} = 5$.

<p>x = 2 (C)</p> Signup and view all the answers

How can you express the equation $4^{3x+2} = 8^{x-1}$ using a common base?

<p>$(2^2)^{3x+2} = (2^3)^{x-1}$ (A)</p> Signup and view all the answers

Given $25^{x} - 6 \cdot 5^{x} + 5 = 0$, use substitution to find the values of x.

<p>x = 0, x = 1 (D)</p> Signup and view all the answers

Flashcards

Solving Exponential Equations

Express both sides of the equation with the same base, then equate the exponents and solve.

Changing Bases Technique

Convert numbers in the equation to a common base, then set the exponents equal to each other.

Solving with Logarithms

Apply log or natural log (ln) to both sides of the equation to solve for the variable.

Isolating Exponential Terms

Isolate the exponential term, then apply logarithms to both sides of the equation.

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Solving Equations with Base e

Use natural logarithms (ln) when dealing with the base e.

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Fractions in Exponents

Rewrite fractions with negative exponents to match bases, then set and solve exponents.

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Multiplying Exponential Terms

When terms with the same base are multiplied, their exponents are added.

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Substitution in Exponentials

Use substitution to reduce a complex equation to a simpler quadratic equation.

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Factoring out GCF

Factor out the greatest common factor, then simplify and solve for the variable.

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Study Notes

Solving Exponential Equations with the Same Base

  • To solve an exponential equation, aim to express both sides with the same base.
  • If bases are equal, then exponents must also be equal.
  • For example, in 3^(x+2) = 9^(2x-3), convert 9 to 3^2, then equate the exponents.
  • When raising one exponent to another, multiply them (e.g., (3^2)^(2x-3) becomes 3^(4x-6)).

Techniques for Changing Bases

  • Convert numbers to a common base to solve exponential equations.
  • Recognizing common bases is crucial (e.g., 8 and 16 can both be expressed as powers of 2).
  • After establishing a common base, set the exponents equal to each other.

Solving Exponential Equations by Converting to a Common Base (Example)

  • Starting equation: 8^(4x-12) = 16^(5x-3)
  • Convert 8 to 2^3 and 16 to 2^4: (2^3)^(4x-12) = (2^4)^(5x-3)
  • Multiply exponents: 2^(12x-36) = 2^(20x-12)
  • Set exponents equal: 12x - 36 = 20x - 12
  • Solve for x: x = -3

Common Bases

  • 27 and 81 can both be expressed as powers of 3.

Solving Exponential Equations Using Logarithms

  • Logarithms can be used to solve exponential equations when you can't easily manipulate to get the same base
  • Apply log or natural log (ln) to both sides of the equation

Using Logarithms to Solve for x

  • In the equation 3^x = 8, take the log of both sides: log(3^x) = log(8).
  • Use the power rule to move the exponent: x * log(3) = log(8).
  • Isolate x: x = log(8) / log(3).
  • Calculate x: x ≈ 1.8928.

Natural Logarithms

  • Natural logarithms (ln) are particularly useful when dealing with the base e.
  • If e^x = 7, take the natural log of both sides: ln(e^x) = ln(7).
  • Simplify: x * ln(e) = ln(7), where ln(e) = 1, so x = ln(7).
  • Decimal approximation: x ≈ 1.9459.

Isolating Exponential Terms Before Applying Logarithms

  • Simplify the equation by isolating the exponential term.
  • Apply logarithms after isolating the exponential term.
  • Solve for x after applying logarithms and using log properties.
  • In the equation 5 + 4^(x-2) = 23, subtract 5 from both sides to get 4^(x-2) = 18.
  • Apply log to both sides: log(4^(x-2)) = log(18).
  • Move the exponent: (x - 2) * log(4) = log(18).
  • Isolate x: x = 2 + log(18) / log(4).
  • Calculate x: x ≈ 4.08496.

Solving Exponential Equations with Base e

  • For equations with base e, use natural logarithms (ln).
  • Before taking the natural log, isolate the exponential term.
  • Use properties of logarithms to solve for x.
  • If 3 + 2e^(3-x) = 7, isolate the exponential term to get 2e^(3-x) = 4.
  • Divide by 2: e^(3-x) = 2.
  • Apply ln to both sides: ln(e^(3-x)) = ln(2).
  • Simplify: 3 - x = ln(2).
  • Solve for x: x = 3 - ln(2).
  • Approximation: x ≈ 2.3069.

Exponential Equation with Variable in the Exponent and a Fraction

  • Rewrite fractions with negative exponents to match bases.
  • Set the exponents equal after establishing common bases.
  • Solve for x after equating the exponents.
  • If 3^(x^2 + 4x) = 1/27, rewrite as 3^(x^2 + 4x) = 3^(-3).
  • Then, x^2 + 4x = -3.
  • Rewrite as x^2 + 4x + 3 = 0.
  • Factor: (x + 3)(x + 1) = 0.
  • Solutions: x = -3, x = -1

Solving Exponential Equations with Combined Terms

  • When multiplying terms with the same base, add the exponents.
  • Factor the resulting quadratic equation to find solutions for x.
  • Check solutions by substituting back into original equation.
  • For 2^(x^2) * 2^(3x) = 16, rewrite as 2^(x^2 + 3x) = 2^4.
  • Then, x^2 + 3x = 4.
  • Rewrite as x^2 + 3x - 4 = 0.
  • Factor: (x + 4)(x - 1) = 0.
  • Solutions: x = -4, x = 1

Substitution to Simplify Factoring

  • Use substitution to reduce to a quadratic equation when direct factoring isn't obvious.
  • Factor the quadratic equation and solve for the substitute variable.
  • Substitute back to find values for the original variable x.
  • For 4^(2x) - 20 * 4^x + 64 = 0, let a = 4^x, then the equation becomes a^2 - 20a + 64 = 0.
  • Factor: (a - 16)(a - 4) = 0.
  • Solutions: a = 16, a = 4.
  • If a = 16, 4^x = 16, so x = 2.
  • If a = 4, 4^x = 4, so x = 1

Factoring Out the Greatest Common Factor (GCF)

  • When terms have a common exponential expression, factor out the GCF.
  • Simplify and solve for x.
  • For 3^(2x) - 3^(2x-1) = 18, factor out 3^(2x) to get 3^(2x) * (1 - 3^(-1)) = 18.
  • Simplify: 3^(2x) * (1 - 1/3) = 18.
  • Further simplification: 3^(2x) * (2/3) = 18.
  • Multiply by 3/2: 3^(2x) = 27.
  • Rewrite 27 as 3^3 so, 3^(2x) = 3^3, thus 2x = 3.
  • Solve for x: x = 3/2.

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