Single-Phase AC Power Analysis Quiz

$P = \frac{1}{T} \int_{0}^{T} p(t) dt$ or $P = \frac{1}{T} \int_{0}^{T} v(t)i(t) dt$

$P = VI cos\Phi = I^2R

$P = VI cos\Phi = 0

<p>A resistive load (R)</p> Signup and view all the answers

<p>A reactive load (L or C)</p> Signup and view all the answers

<p>The average power is the average of the instantaneous power over one period and can be calculated using the formula $P = \frac{1}{T} \int_{0}^{T} p(t) dt$. It is more convenient to measure than instantaneous power, and the wattmeter, the instrument for measuring power, responds to average power.</p> Signup and view all the answers

<p>The expression for average power in electrical circuits using phasor notation is given by $P = \frac{V_{rms}I_{rms}}{2} \cos(\theta_v - \theta_i)$, where $V_{rms}$ and $I_{rms}$ are the rms voltage and current, and $\theta_v$ and $\theta_i$ are the phase angles of the voltage and current, respectively.</p> Signup and view all the answers

<p>In a resistive circuit, the average power is given by $P = V_{rms}I_{rms}\cos(\Phi)$, where $\Phi = 0$. In a pure inductive or capacitive circuit, the average power is zero, as $\Phi = \pm 90$ and $\cos(\Phi) = 0.</p> Signup and view all the answers

<p>The complex power $S$ absorbed by the AC load is a combination of real power (average power) and reactive power. It is defined as $S = P + jQ$, where $P$ is the average power and $Q$ is the reactive power.</p> Signup and view all the answers

<p>A resistive load (R) always absorbs power, while a reactive load (L or C) absorbs zero average power. This is because the average power in a reactive load is dependent on the phase angle, leading to a power factor of zero.</p> Signup and view all the answers