Rust: Copy vs Move Semantics
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Questions and Answers

In Rust, what determines whether the assignment s2 = s1 performs a copy or a move operation?

  • Whether the `Student` type implements the `Copy` or `Move` trait. (correct)
  • The mutability of `s1`.
  • The scope in which `s1` and `s2` are defined.
  • The size of the `Student` type in memory.

What does the Copy trait imply for the assignment s2 = s1 when Student implements it?

  • `s1` is invalidated and can no longer be used after the assignment.
  • `s2` becomes a reference to `s1`'s memory location.
  • A deep copy of `s1`'s data is created for `s2`, including data pointed to by any pointers.
  • A bitwise copy of `s1`'s data is created for `s2`. (correct)

If the Name field of the Student struct is a pointer to a heap-allocated string, what happens to the string's memory when s2 = s1 is executed and Student implements Copy?

  • The string data is moved to `s2`, and `s1.Name` becomes invalid.
  • The string data is duplicated in memory, and `s2.Name` points to the new copy.
  • The memory occupied by the string is deallocated.
  • Both `s1.Name` and `s2.Name` will point to the same memory location on the heap. (correct)

Given a Student struct with a Name field that is a pointer to a heap-allocated buffer, and assuming Student implements the Copy trait, what potential issue could arise if the string pointed to by Name is modified after the assignment s2 = s1?

<p>Modifying the string through either <code>s1.Name</code> or <code>s2.Name</code> would affect the other, as they both point to the same memory location. (A)</p> Signup and view all the answers

Consider the scenario where Student contains a field transcript: File, where File represents an open file handle. If Student implemented Copy, what subtle but potentially devastating issue could arise after the assignment s2 = s1?

<p>Both <code>s1</code> and <code>s2</code> would attempt to write to the same file handle, leading to data corruption and unpredictable behavior, further complicated by the operating system's file locking mechanisms, potentially causing deadlocks or access violations. (D)</p> Signup and view all the answers

Why does the operation s += "A larger string" imply the creation of a mutable reference?

<p>Because the operation modifies the original string <code>s</code> in place, which requires a mutable reference to ensure exclusive access and prevent data races. (D)</p> Signup and view all the answers

In Rust, what is the primary purpose of references?

<p>To allow access to data without transferring ownership, preventing memory unsafety. (C)</p> Signup and view all the answers

Consider the following Rust code snippet:

let mut s = String::from("hello"); let r1 = &s; let r2 = &s; println!("{}, {}", r1, r2);

Why does this code compile without errors?

<p>Because the borrow checker allows multiple immutable references to the same data. (C)</p> Signup and view all the answers

What is the significance of the len() method requiring an immutable reference (&self) in the String struct in Rust?

<p>It allows the <code>len()</code> method to be called concurrently from multiple threads without causing data races, as it only reads the length. (B)</p> Signup and view all the answers

What is the key difference between a mutable and an immutable reference in Rust, concerning borrowing rules?

<p>Only one mutable reference to a piece of data can exist in a scope, while multiple immutable references are allowed. (B)</p> Signup and view all the answers

Consider the following scenario in Rust:

let mut s = String::from("hello");
let r1 = &mut s;
// some operation
let r2 = &mut s; //This line causes a compile error

Why does this code snippet result in a compile-time error?

<p>Because the Rust compiler disallows creating more than one mutable reference to a given variable in the same scope. (B)</p> Signup and view all the answers

Given the following Rust code:

fn modify_string(s: &mut String) {
    s.push_str(", world!");
}

fn main() {
    let mut my_string = String::from("hello");
    let len_before = my_string.len();
    modify_string(&mut my_string);
    let len_after = my_string.len();
    println!("{} {}", len_before, len_after);
}

Predict the output of this program.

<p><code>5 13</code> (D)</p> Signup and view all the answers

Consider a scenario where you have a complex data structure in Rust, and you want to allow multiple parts of your code to read from it concurrently, but only one part to modify it at any given time. How would you achieve this safely using Rust's borrowing rules and standard library features without using unsafe code?

<p>Employ a combination of <code>Arc&lt;RwLock&lt;T&gt;&gt;</code>, where <code>Arc</code> provides atomic reference counting for thread-safe sharing, and <code>RwLock</code> allows multiple readers or a single writer at any time. (D)</p> Signup and view all the answers

In the given C/C++ code snippet, what is the primary risk associated with printf("%s\n",s2); after delete []s1; s1 = nullptr;?

<p>Undefined behavior due to <code>s2</code> pointing to already freed memory. (B)</p> Signup and view all the answers

What is the immediate consequence of the line char* s2 = s1; in the provided C/C++ code?

<p>It creates two pointers, <code>s1</code> and <code>s2</code>, that both point to the same memory location. (B)</p> Signup and view all the answers

What is the main problem the code tries to highlight in the assignment char* s2 = s1?

<p>Creating multiple owners for the same memory. (C)</p> Signup and view all the answers

In the context of the code, what does it mean to 'duplicate the pointer'?

<p>Creating a new pointer that points to the same memory location as the original pointer. (B)</p> Signup and view all the answers

What is the potential outcome if s2 accesses the memory location after s1 has deallocated it using delete[] s1?

<p>Undefined behavior, potentially leading to a crash or data corruption. (C)</p> Signup and view all the answers

In the context of memory management, what is the significance of setting s1 = nullptr after delete []s1;?

<p>It's considered good practice to avoid dangling pointers, although it does not directly prevent memory corruption if other pointers still reference the memory. (A)</p> Signup and view all the answers

If you wanted s2 to have its own independent copy of the string "abc" after the line char* s1 = new char{"abc"};, which of the following approaches would be most appropriate in C++?

<p><code>char* s2 = new char[4]; strcpy(s2, s1);</code> (D)</p> Signup and view all the answers

Insanely difficult question: Suppose a hypothetical language, 'LangX', has similar pointer behavior to C/C++ but introduces a compile-time feature called 'Ownership Verifier'. This verifier tracks pointer assignments and deallocations. How would 'Ownership Verifier' likely react to the given code, and what change would it suggest to ensure memory safety, without using garbage collection?

<p>Generate a compile-time error; 'Ownership Verifier' detects <code>s2</code> becomes a dangling pointer after <code>delete[] s1</code> and suggests deep copying <code>s1</code>'s contents into a newly allocated memory region for <code>s2</code> instead of simple assignment. (A)</p> Signup and view all the answers

In the provided Rust code, what is the primary issue that arises from modifying the String s after creating slice_of_s?

<p>A dangling pointer is created in 'slice_of_s', pointing to deallocated memory. (D)</p> Signup and view all the answers

What does the term "dangling pointer" refer to in the context of the provided Rust code?

<p>A pointer that points to a memory location that has already been deallocated or is no longer valid. (B)</p> Signup and view all the answers

In the given Rust code, what is the value of s.len after the line s.push_str("DDDDD"); is executed?

<p>12 (D)</p> Signup and view all the answers

In the context of the code provided, what is the value of slice_of_s.size?

<p>3 (B)</p> Signup and view all the answers

What is the primary reason Rust's borrow checker doesn't prevent the dangling pointer issue in the provided example, considering the code compiles successfully?

<p>The borrow checker cannot predict the reallocation behavior of <code>String</code> when <code>push_str</code> is used, as it depends on the current capacity and length. (A)</p> Signup and view all the answers

Given that the String type in Rust can reallocate its underlying buffer, under what condition is reallocation most likely to occur when using the push_str method?

<p>When the combined length of the existing string and the appended string exceeds the current capacity of the <code>String</code>. (B)</p> Signup and view all the answers

Suppose the initial capacity of String s is exactly enough to hold "AABBBCC" without any extra space. After creating slice_of_s = &s[2..5], what is the minimum capacity that s must have before the push_str operation to prevent reallocation and avoid creating a dangling pointer?

<p>12 (C)</p> Signup and view all the answers

Consider a modified scenario where, instead of push_str, we use insert_str to insert "DDDDD" at the beginning of s after creating slice_of_s. If this operation causes reallocation, describe a potential strategy to mitigate the dangling pointer issue, assuming direct memory manipulation is unsafe and discouraged in Rust.

<p>Clone <code>slice_of_s</code> into a new <code>String</code> immediately after its creation, ensuring it owns its own memory. (A)</p> Signup and view all the answers

In Rust, what is the primary purpose of using immutable references?

<p>To allow multiple parts of the code to read the same data without the risk of data races. (C)</p> Signup and view all the answers

In the provided Rust code snippet, what will be the value of s.len after the line s += "A larger string"; executes, assuming the code compiles successfully?

<p>19 (B)</p> Signup and view all the answers

Given the Rust code and the stack analysis, what is the most likely data type stored at the memory location s.chars?

<p><code>Box&lt;[u8]&gt;</code> (D)</p> Signup and view all the answers

What would happen if you tried to modify the value referenced by ref_to_s_1 directly (e.g., ref_to_s_1.push_str("test");) after the line let ref_to_s_1: &String = &s;?

<p>The code will not compile due to Rust's borrowing rules. (B)</p> Signup and view all the answers

Why do immutable references prevent data modification?

<p>To prevent data races by ensuring that data is not being read and written to concurrently. (C)</p> Signup and view all the answers

In the given code snippet, what is the significance of the stack alignment (8 bytes) in the context of memory management?

<p>It ensures that all variables occupy a multiple of 8 bytes in memory for optimal cache utilization. (C)</p> Signup and view all the answers

Given that ref_to_s_1, ref_to_s_2, and ref_to_s_3 are all immutable references to s, and s is later modified, what mechanism in Rust ensures that these references do not lead to data corruption or undefined behavior?

<p>The borrow checker's static analysis. (D)</p> Signup and view all the answers

Insanely Difficult: Consider a scenario where the println! macro is replaced with a custom function that uses unsafe Rust to bypass the borrow checker. If this custom function were to access ref_to_s_1 after s has been reallocated due to growing beyond its initial capacity, what is the most likely outcome?

<p>The program will likely crash due to accessing memory that is no longer valid or has been reallocated. (C)</p> Signup and view all the answers

In C, what is the likely outcome of attempting to printf the value pointed to by s2 after s1 has been deleted and set to nullptr, where s2 was initially assigned the same pointer value as s1?

<p>The program will print garbage data or potentially crash due to <code>s2</code> pointing to freed memory. (A)</p> Signup and view all the answers

In the provided C code examples, which scenario correctly avoids a double free or use-after-free vulnerability when dealing with dynamically allocated strings?

<p>COPY: Using <code>strdup</code> to create a copy of the string, allowing independent deletion of both pointers. (C)</p> Signup and view all the answers

In Rust, what is the default behavior when assigning one variable to another, where the underlying type does not implement the Copy trait?

<p>A move operation occurs, transferring ownership of the data to the new variable, and invalidating the original. (B)</p> Signup and view all the answers

Which of the following data types in Rust automatically implement the Copy trait by default?

<p><code>i32</code> (A)</p> Signup and view all the answers

In Rust, considering ownership rules, what happens when a variable x is passed as an argument to a function my_function(x)?

<p>Ownership of <code>x</code> is transferred to the function, and <code>x</code> is no longer valid in the calling scope unless the function returns ownership. (C)</p> Signup and view all the answers

Given the Rust code let s = String::from("hello"); let s2 = s; println!("{s}");, what is the expected compiler error and the reason behind it?

<p>Error: borrow of moved value: <code>s</code>; <code>s</code> was moved when assigned to <code>s2</code>, and is no longer valid for use in <code>println!</code>. (B)</p> Signup and view all the answers

In Rust, if a function print_s takes ownership of a String argument, what happens to the variable passed to print_s in the calling function?

<p>The variable in the calling function is moved, and therefore can no longer be used, unless ownership is returned. (B)</p> Signup and view all the answers

Consider a scenario in Rust where you want to allow a function to modify a String without taking ownership. Which approach should you use?

<p>Pass a mutable reference to the <code>String</code> (e.g., <code>my_function(s: &amp;mut String)</code>). (D)</p> Signup and view all the answers

In Rust, the concept of 'borrowing' allows you to do what?

<p>Access a value without taking ownership, either immutably or mutably. (D)</p> Signup and view all the answers

Insanely difficult: Suppose you have a complex data structure in Rust, a Graph represented as struct Graph { nodes: Vec<Node> } where Node contains multiple String fields and internal references. You need to implement a method split that divides the graph into two independent subgraphs, ensuring no shared ownership or references between them. The original Graph should be consumed in the process. What is the most idiomatic and memory-safe approach to achieve this, considering Rust's ownership and borrowing rules?

<p>Utilize <code>std::mem::take</code> to move the <code>nodes</code> field out of the original <code>Graph</code>, then carefully construct the subgraphs using <code>Vec::drain_filter</code> or similar methods to avoid accidental data duplication or shared ownership. Return the two new <code>Graph</code> instances. (A)</p> Signup and view all the answers

Flashcards

What is the Copy trait in Rust?

Determines how Rust handles assignment operations for a type. If a type has the Copy trait, assigning it will create a duplicate of the original data.

What is trait?

A property defined as a function with a specific purpose.

What happens during Copy?

When a type has the Copy trait, assigning a variable of that type to another variable results in a bitwise copy of the data.

s2 = s1 with Copy Trait

s2 will receive an exact copy of the data contained within s1. Both variables are independently owned.

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Validity after Copy?

With the Copy trait, both s1 and s2 are independently valid after the assignment, each holding a copy of the data..

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delete []s1; s1 = nullptr;

A memory area allocated in the heap is freed, and the pointer is set to null to prevent further access.

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Problem with printing 's2' after deleting 's1'?

Accessing memory that has already been freed, which leads to unpredictable behavior and potential crashes.

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Multiple owners (pointers) of same memory?

Two pointers pointing to the same memory location on the heap, leading to double freeing.

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Dangers of duplicating pointers?

Duplicating the pointer, which results in having multiple pointers managing the same memory location.

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What is a trait in Rust?

A trait (property list) that determines how certain operations can be performed on a type. For example, copy or moving.

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Copy trait in Rust

A trait indicating that a type's value can be copied bitwise, creating a new, independent instance.

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Move trait (conceptually) in Rust

Transferring ownership of a resource from one variable to another, invalidating the original owner.

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Move vs Copy

Move: Transferring ownership. Copy: Creating an independent duplicate.

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Heap

A region of memory used for dynamic data allocation, where the size isn't known at compile time.

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Stack

Memory allocated in a LIFO (Last-In, First-Out) order, used for storing function calls and local variables.

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String Type

In Rust, a type that can grow or shrink at runtime and stores its data on the heap.

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Reference

An immutable, non-owning pointer that allows you to access data without taking ownership.

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Borrowing

The act of creating references to a value.

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Immutable References

References that do not allow you to change the underlying data.

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Offset

The location of a variable within the stack memory.

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Capacity

The number of elements a String can hold without reallocating.

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Mutable String (String)

A string that owns its data on the heap, allowing modification.

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String Slice

Creating a reference to a portion of a String.

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push_str

Adding more characters to the end of a String.

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Dangling Pointer

When a pointer references memory that has been freed.

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Memory Reallocation

Allocating new memory on the heap to accommodate larger data.

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Memory Deallocation

Automatically freeing memory that is no longer in use.

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Borrowing Rules

The concept that only one mutable reference to a particular piece of data can exist in a particular scope.

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Invalid Slice

Memory addresses become invalid after reallocation, leading to dangling pointers if slices still point to old addresses.

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Non-static Method References

Any non-static method call implies creating a reference to the object. This reference can be mutable if the method modifies the object or immutable if the method only reads data.

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Mutable Reference

Mutable references allow modification of the data they point to. Only one mutable reference can exist for a given piece of data at a time.

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+= and Mutable References

The += operator on a String implies a mutable reference because it modifies the String object by appending to it.

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.len() and Immutable References

The .len() method returns the length of a String, it only needs to read access to the String's internal data, thus requiring an immutable reference.

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String::len(&self)

The len() method implemented in Rust's String struct takes an immutable reference (&self) because it only needs to read the length, not modify the String.

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Multiple Immutable References

Calling s.len() when immutable references to s already exist is safe because .len() only requires an immutable reference, and multiple immutable references are allowed.

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Undefined Behavior (C)

Behavior in C where the result of an operation is unpredictable due to actions like deleting memory that is still referenced.

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Move (C)

In C, transferring ownership of a pointer. After the move, the original pointer should not be used.

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Copy (C)

Duplicating data in C, creating a new independent copy. Changes to the copy do not affect the original.

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Ownership (Rust)

A system in Rust for managing memory. It ensures that each value has a single owner, preventing dangling pointers and data races.

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Move Operation (Rust)

Rust's default behavior for value assignment, transferring ownership to the new variable. The original variable can no longer be used.

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Copy Trait (Rust)

A trait in Rust that enables types to be copied without transferring ownership. Basic data types like integers and booleans have this trait.

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Ownership Rule Application

Situations where Rust's ownership rules are triggered, such as variable assignment, function parameter passing, and function return.

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Borrow of Moved Value Error

In Rust, attempting to use a variable after its ownership has been transferred (moved) to another variable.

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Ownership Transfer to Function

Transferring ownership of a String to a function. The function now owns the String and can manage its memory.

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Error E0382 (Rust)

An error that occurs when you try to use a variable after its value has been moved to another variable.

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Study Notes

Rust Programming Course 2

  • The course will cover the String type, Ownership management, Borrowing and References, Reborrowing and Optimizations

Prerequisite: String Type

  • Some things about strings need to be quickly understood for this course.
  • The rust type is String
  • It is Dynamic and can increase in size
  • The encoding is UTF-8
  • Common operations are addition, substring, find, etc
  • Strings will be covered in more detail in another course.

String Examples

  • To create a string, String::from("a string") is used
  • To get the length of a string, the .len() method can be used
  • String::from("a string").len() will output 8
  • To concatenate strings, the += operator can be used, or the .push_str(...) method
  • To concatenate "456" to string "123", s += "456" or s.push_str("456") can be used
  • The .push_str() method will add the string to the end of the original
  • To obtain a substring of a string, the range operator can be used
  • &s[1..3] will be "BC" when s is "ABCDEFG"

Additional Information On Strings

  • Strings in Rust are complex and require more in-depth analysis.
  • The explanation given should be sufficient for the moment.

Ownership

  • In Rust, every memory zone has one and only one owner at a time.
  • Every owner has a lifetime, which means it exists within a scope.
  • Once an owner goes out of scope, its memory zone is freed.
  • "Freed" in the context of ownership has a different meaning and it depends on where the memory zone lies - stack, heap, or global.

Variable Ownership Example

  • Every variable or a parameter can own the memory zone it represents
  • A variable of type u32 takes up 4 bytes in stack memory
  • You can say that the memory from offset 99.996 to 100.000 is owned by the variable sum

Owner and Memory Case

  • The main function contains a mutable u32 variable sz initialized to 0, and a nested scope
  • Within the nested scope, a mutable String variable s is created from "abc"
  • Then, "456" is pushed into s and sz gets the length of s as a u32 and then s is printed
  • After the scope, sz is printed
  • Sz is located on the stack and takes up 4 bytes
  • s is located in the stack and the heap
  • s stack(12 or 24 bytes) and heap (3 bytes)
  • A new space of 6 characters is allocated on the heap when “456” is added
  • The original text "abc" is copied in the new location in the head
  • The old (3 bytes) space from the heap is freed
  • The scope of "s" has ended so the compiler decides to free all memory owned by "s"
  • Freeing "s" means all heap memory is freed
  • Stack memory where len, capacity, and chars pointer are stored are also cleared
  • "s" is no longer valid, and accessing it results in a compiler error
  • At that point, the scope of "sz" has ended and as such it is freed (all stack space is cleared).

'C'' and 'C++' Code

  • A similar "C" code implies freeing the heap manually and if the action is not performed, memory leak will happen
  • Modern C++ has unique pointers which are similar to Rust's system

C/C++ Ownership Problem

  • In the following C/C++ code, char* s2 ​​= s1; is problematic
  • Both s1 and s2 point to the same memory location, thus there can be only one owner, not two
  • Once s1 pointer is deleted, the memory zone assigned to s1 is freed
  • When the program accesses the content of s2, now pointing to already freed memory, the behavior is undefined, and it will likely crash

Rust Concept: Traits

  • Rust has traits which act as properties for each variable, and explain how operations can be performed
  • Copy, and Move are important traits in Rust
  • Move trait does not exist in Rust
  • It exits in the slides only to simplify the explanation
  • Copy trait does exits in Rust

Example

  • There exists a called Student:
    • MathGrade is a type u8
    • EnglishGrade is a type u8
    • Name is a heap buffer
    • If type Student implements Copy trait then doing s2 = s1 statement will copy MathGrade, EnglishGrade and Name to s2
  • Name pointer to address 200.000
  • If type Student implements Move trait then doing s2 = s1 statement will copy MathGrade, EnglishGrade and sets a pointer to address 100.000

Details On Copy

  • Bitwise copy the value of s1.MathGrade into s2.MathGrade
  • Bitwise copy the value of s1.EnglishGrade into s2.EnglishGrade
  • Allocated 4 bytes to a new location on the heap and assign s2.Name pointer to that location
  • Bitwise copy 4 bytes from address 100.000 (s1.Name) to address 200.000 (s2.Name)

Details On Move

  • Bitwise copy the value of s1.MathGrade into s2.MathGrade
  • Assign s2.Name pointer to the offset 100.000
  • Clear the value of pointer s1.Name so that only one object points to the offset 100.000

Move Vs Copy

  • The worst thing is to duplicate the pointer (make two owners).
  • Copy and Move traits prevent this issue
  • The undefined behabior C code can be prevented using different strategies:
    • Make copy - C code
  • Make move - C code
  • Rust defaults to move for all objects except for the case where Copy trait is set
  • Basic types types (u8..u128, i8..i128, bool, isize, usize, char) implement Copy trait

Advantages to move or copy trait

  • No dangling pointers
  • No data races
  • Every assignment, passing a parameter or return to/from function triggers Ownership rules

Rust examples with move and copy

  • Copy let s2 = s; println!("{s2}"); - Compile Ok
  • Move let s2 = s; println!("{s}"); - Compile Error
  • Transfer from function will also cause Compiler Error
  • value borrowed here after move
  • Returning the variable to the original owner solves the borrow issue, at the cost of readability/usability

Borrowing

  • Sometimes the original rules for ownership are too restrictive, so there exists a concept called borrowing
  • Most programming languages use references, so Rust decided to use Borrowing paradigm
  • An object has been borrowed and will be returned to its owner
  • references in Rust is denoted by the symbol &
  • a dereference process is performed with the symbol *
  • Immutable and mutable references
  • By default it is immutable
  • Use mut for mutable

How does Borrowing work

  • Putting ‘rdx” register to show the offset where the constant string “123” lies in memory
  • Then “rcx” stack offset where variable "s” should be created
  • Copy was created in code “rcx” so there is no modification of register value.

Rules for References

  • Only one mutable refernce can exists toward object over time
  • Many immutable references can exits and can not change the value of the object.
  • Immutable and mutable object should be used and called as needed, and should't be long life so the compilation could occur without error

What are Slices

  • They hold a pointer to a size

Reborrowing

  • When an object is passed, it is expected to be unable to be reused, reborrowing allows rust to reuse objects.
  • Rust performs Copy for immutable variables, and Move for mutable variables. For references it uses a new concept called reborrowing allowing for easier code
  • If ownership was lost after first object, code wouldn't work at all if it calls the object twice
  • It is still only temporary and for singular scopes.

Under The Hood

  • We create mut_ref_to_s (only ONE mutable reference towards variable s)

  • We reborrow mut_ref_to_s to function foo

  • Where it will be used as “x"

  • this as we temporary create an alias for mut_ref_to_s that is called x

  • Can only be used within the function foo.

  • At any given time, there is only ONE available to use mutable reference towards object “s"

  • While the 2nd mutable reference is in action, the is not so the code still functions correctly

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Description

Understanding move and copy semantics in Rust is crucial for preventing memory issues. The Copy trait dictates whether an assignment results in a bitwise copy or a move. When dealing with heap-allocated data and the Copy trait, potential issues like double frees and data races arise.

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