Podcast
Questions and Answers
In Rust, what determines whether the assignment s2 = s1
performs a copy or a move operation?
In Rust, what determines whether the assignment s2 = s1
performs a copy or a move operation?
- Whether the `Student` type implements the `Copy` or `Move` trait. (correct)
- The mutability of `s1`.
- The scope in which `s1` and `s2` are defined.
- The size of the `Student` type in memory.
What does the Copy
trait imply for the assignment s2 = s1
when Student
implements it?
What does the Copy
trait imply for the assignment s2 = s1
when Student
implements it?
- `s1` is invalidated and can no longer be used after the assignment.
- `s2` becomes a reference to `s1`'s memory location.
- A deep copy of `s1`'s data is created for `s2`, including data pointed to by any pointers.
- A bitwise copy of `s1`'s data is created for `s2`. (correct)
If the Name
field of the Student
struct is a pointer to a heap-allocated string, what happens to the string's memory when s2 = s1
is executed and Student
implements Copy
?
If the Name
field of the Student
struct is a pointer to a heap-allocated string, what happens to the string's memory when s2 = s1
is executed and Student
implements Copy
?
- The string data is moved to `s2`, and `s1.Name` becomes invalid.
- The string data is duplicated in memory, and `s2.Name` points to the new copy.
- The memory occupied by the string is deallocated.
- Both `s1.Name` and `s2.Name` will point to the same memory location on the heap. (correct)
Given a Student
struct with a Name
field that is a pointer to a heap-allocated buffer, and assuming Student
implements the Copy
trait, what potential issue could arise if the string pointed to by Name
is modified after the assignment s2 = s1
?
Given a Student
struct with a Name
field that is a pointer to a heap-allocated buffer, and assuming Student
implements the Copy
trait, what potential issue could arise if the string pointed to by Name
is modified after the assignment s2 = s1
?
Consider the scenario where Student
contains a field transcript: File
, where File
represents an open file handle. If Student
implemented Copy
, what subtle but potentially devastating issue could arise after the assignment s2 = s1
?
Consider the scenario where Student
contains a field transcript: File
, where File
represents an open file handle. If Student
implemented Copy
, what subtle but potentially devastating issue could arise after the assignment s2 = s1
?
Why does the operation s += "A larger string"
imply the creation of a mutable reference?
Why does the operation s += "A larger string"
imply the creation of a mutable reference?
In Rust, what is the primary purpose of references?
In Rust, what is the primary purpose of references?
Consider the following Rust code snippet:
let mut s = String::from("hello"); let r1 = &s; let r2 = &s; println!("{}, {}", r1, r2);
Why does this code compile without errors?
Consider the following Rust code snippet:
let mut s = String::from("hello"); let r1 = &s; let r2 = &s; println!("{}, {}", r1, r2);
Why does this code compile without errors?
What is the significance of the len()
method requiring an immutable reference (&self
) in the String
struct in Rust?
What is the significance of the len()
method requiring an immutable reference (&self
) in the String
struct in Rust?
What is the key difference between a mutable and an immutable reference in Rust, concerning borrowing rules?
What is the key difference between a mutable and an immutable reference in Rust, concerning borrowing rules?
Consider the following scenario in Rust:
let mut s = String::from("hello");
let r1 = &mut s;
// some operation
let r2 = &mut s; //This line causes a compile error
Why does this code snippet result in a compile-time error?
Consider the following scenario in Rust:
let mut s = String::from("hello");
let r1 = &mut s;
// some operation
let r2 = &mut s; //This line causes a compile error
Why does this code snippet result in a compile-time error?
Given the following Rust code:
fn modify_string(s: &mut String) {
s.push_str(", world!");
}
fn main() {
let mut my_string = String::from("hello");
let len_before = my_string.len();
modify_string(&mut my_string);
let len_after = my_string.len();
println!("{} {}", len_before, len_after);
}
Predict the output of this program.
Given the following Rust code:
fn modify_string(s: &mut String) {
s.push_str(", world!");
}
fn main() {
let mut my_string = String::from("hello");
let len_before = my_string.len();
modify_string(&mut my_string);
let len_after = my_string.len();
println!("{} {}", len_before, len_after);
}
Predict the output of this program.
Consider a scenario where you have a complex data structure in Rust, and you want to allow multiple parts of your code to read from it concurrently, but only one part to modify it at any given time. How would you achieve this safely using Rust's borrowing rules and standard library features without using unsafe
code?
Consider a scenario where you have a complex data structure in Rust, and you want to allow multiple parts of your code to read from it concurrently, but only one part to modify it at any given time. How would you achieve this safely using Rust's borrowing rules and standard library features without using unsafe
code?
In the given C/C++ code snippet, what is the primary risk associated with printf("%s\n",s2);
after delete []s1; s1 = nullptr;
?
In the given C/C++ code snippet, what is the primary risk associated with printf("%s\n",s2);
after delete []s1; s1 = nullptr;
?
What is the immediate consequence of the line char* s2 = s1;
in the provided C/C++ code?
What is the immediate consequence of the line char* s2 = s1;
in the provided C/C++ code?
What is the main problem the code tries to highlight in the assignment char* s2 = s1
?
What is the main problem the code tries to highlight in the assignment char* s2 = s1
?
In the context of the code, what does it mean to 'duplicate the pointer'?
In the context of the code, what does it mean to 'duplicate the pointer'?
What is the potential outcome if s2
accesses the memory location after s1
has deallocated it using delete[] s1
?
What is the potential outcome if s2
accesses the memory location after s1
has deallocated it using delete[] s1
?
In the context of memory management, what is the significance of setting s1 = nullptr
after delete []s1;
?
In the context of memory management, what is the significance of setting s1 = nullptr
after delete []s1;
?
If you wanted s2
to have its own independent copy of the string "abc" after the line char* s1 = new char{"abc"};
, which of the following approaches would be most appropriate in C++?
If you wanted s2
to have its own independent copy of the string "abc" after the line char* s1 = new char{"abc"};
, which of the following approaches would be most appropriate in C++?
Insanely difficult question: Suppose a hypothetical language, 'LangX', has similar pointer behavior to C/C++ but introduces a compile-time feature called 'Ownership Verifier'. This verifier tracks pointer assignments and deallocations. How would 'Ownership Verifier' likely react to the given code, and what change would it suggest to ensure memory safety, without using garbage collection?
Insanely difficult question: Suppose a hypothetical language, 'LangX', has similar pointer behavior to C/C++ but introduces a compile-time feature called 'Ownership Verifier'. This verifier tracks pointer assignments and deallocations. How would 'Ownership Verifier' likely react to the given code, and what change would it suggest to ensure memory safety, without using garbage collection?
In the provided Rust code, what is the primary issue that arises from modifying the String s
after creating slice_of_s
?
In the provided Rust code, what is the primary issue that arises from modifying the String s
after creating slice_of_s
?
What does the term "dangling pointer" refer to in the context of the provided Rust code?
What does the term "dangling pointer" refer to in the context of the provided Rust code?
In the given Rust code, what is the value of s.len
after the line s.push_str("DDDDD");
is executed?
In the given Rust code, what is the value of s.len
after the line s.push_str("DDDDD");
is executed?
In the context of the code provided, what is the value of slice_of_s.size
?
In the context of the code provided, what is the value of slice_of_s.size
?
What is the primary reason Rust's borrow checker doesn't prevent the dangling pointer issue in the provided example, considering the code compiles successfully?
What is the primary reason Rust's borrow checker doesn't prevent the dangling pointer issue in the provided example, considering the code compiles successfully?
Given that the String
type in Rust can reallocate its underlying buffer, under what condition is reallocation most likely to occur when using the push_str
method?
Given that the String
type in Rust can reallocate its underlying buffer, under what condition is reallocation most likely to occur when using the push_str
method?
Suppose the initial capacity of String s
is exactly enough to hold "AABBBCC" without any extra space. After creating slice_of_s = &s[2..5]
, what is the minimum capacity that s
must have before the push_str
operation to prevent reallocation and avoid creating a dangling pointer?
Suppose the initial capacity of String s
is exactly enough to hold "AABBBCC" without any extra space. After creating slice_of_s = &s[2..5]
, what is the minimum capacity that s
must have before the push_str
operation to prevent reallocation and avoid creating a dangling pointer?
Consider a modified scenario where, instead of push_str
, we use insert_str
to insert "DDDDD" at the beginning of s
after creating slice_of_s
. If this operation causes reallocation, describe a potential strategy to mitigate the dangling pointer issue, assuming direct memory manipulation is unsafe and discouraged in Rust.
Consider a modified scenario where, instead of push_str
, we use insert_str
to insert "DDDDD" at the beginning of s
after creating slice_of_s
. If this operation causes reallocation, describe a potential strategy to mitigate the dangling pointer issue, assuming direct memory manipulation is unsafe and discouraged in Rust.
In Rust, what is the primary purpose of using immutable references?
In Rust, what is the primary purpose of using immutable references?
In the provided Rust code snippet, what will be the value of s.len
after the line s += "A larger string";
executes, assuming the code compiles successfully?
In the provided Rust code snippet, what will be the value of s.len
after the line s += "A larger string";
executes, assuming the code compiles successfully?
Given the Rust code and the stack analysis, what is the most likely data type stored at the memory location s.chars
?
Given the Rust code and the stack analysis, what is the most likely data type stored at the memory location s.chars
?
What would happen if you tried to modify the value referenced by ref_to_s_1
directly (e.g., ref_to_s_1.push_str("test");
) after the line let ref_to_s_1: &String = &s;
?
What would happen if you tried to modify the value referenced by ref_to_s_1
directly (e.g., ref_to_s_1.push_str("test");
) after the line let ref_to_s_1: &String = &s;
?
Why do immutable references prevent data modification?
Why do immutable references prevent data modification?
In the given code snippet, what is the significance of the stack alignment (8 bytes) in the context of memory management?
In the given code snippet, what is the significance of the stack alignment (8 bytes) in the context of memory management?
Given that ref_to_s_1
, ref_to_s_2
, and ref_to_s_3
are all immutable references to s
, and s
is later modified, what mechanism in Rust ensures that these references do not lead to data corruption or undefined behavior?
Given that ref_to_s_1
, ref_to_s_2
, and ref_to_s_3
are all immutable references to s
, and s
is later modified, what mechanism in Rust ensures that these references do not lead to data corruption or undefined behavior?
Insanely Difficult: Consider a scenario where the println!
macro is replaced with a custom function that uses unsafe
Rust to bypass the borrow checker. If this custom function were to access ref_to_s_1
after s
has been reallocated due to growing beyond its initial capacity, what is the most likely outcome?
Insanely Difficult: Consider a scenario where the println!
macro is replaced with a custom function that uses unsafe
Rust to bypass the borrow checker. If this custom function were to access ref_to_s_1
after s
has been reallocated due to growing beyond its initial capacity, what is the most likely outcome?
In C, what is the likely outcome of attempting to printf
the value pointed to by s2
after s1
has been deleted and set to nullptr
, where s2
was initially assigned the same pointer value as s1
?
In C, what is the likely outcome of attempting to printf
the value pointed to by s2
after s1
has been deleted and set to nullptr
, where s2
was initially assigned the same pointer value as s1
?
In the provided C code examples, which scenario correctly avoids a double free or use-after-free vulnerability when dealing with dynamically allocated strings?
In the provided C code examples, which scenario correctly avoids a double free or use-after-free vulnerability when dealing with dynamically allocated strings?
In Rust, what is the default behavior when assigning one variable to another, where the underlying type does not implement the Copy
trait?
In Rust, what is the default behavior when assigning one variable to another, where the underlying type does not implement the Copy
trait?
Which of the following data types in Rust automatically implement the Copy
trait by default?
Which of the following data types in Rust automatically implement the Copy
trait by default?
In Rust, considering ownership rules, what happens when a variable x
is passed as an argument to a function my_function(x)
?
In Rust, considering ownership rules, what happens when a variable x
is passed as an argument to a function my_function(x)
?
Given the Rust code let s = String::from("hello"); let s2 = s; println!("{s}");
, what is the expected compiler error and the reason behind it?
Given the Rust code let s = String::from("hello"); let s2 = s; println!("{s}");
, what is the expected compiler error and the reason behind it?
In Rust, if a function print_s
takes ownership of a String
argument, what happens to the variable passed to print_s
in the calling function?
In Rust, if a function print_s
takes ownership of a String
argument, what happens to the variable passed to print_s
in the calling function?
Consider a scenario in Rust where you want to allow a function to modify a String
without taking ownership. Which approach should you use?
Consider a scenario in Rust where you want to allow a function to modify a String
without taking ownership. Which approach should you use?
In Rust, the concept of 'borrowing' allows you to do what?
In Rust, the concept of 'borrowing' allows you to do what?
Insanely difficult: Suppose you have a complex data structure in Rust, a Graph
represented as struct Graph { nodes: Vec<Node> }
where Node
contains multiple String
fields and internal references. You need to implement a method split
that divides the graph into two independent subgraphs, ensuring no shared ownership or references between them. The original Graph
should be consumed in the process. What is the most idiomatic and memory-safe approach to achieve this, considering Rust's ownership and borrowing rules?
Insanely difficult: Suppose you have a complex data structure in Rust, a Graph
represented as struct Graph { nodes: Vec<Node> }
where Node
contains multiple String
fields and internal references. You need to implement a method split
that divides the graph into two independent subgraphs, ensuring no shared ownership or references between them. The original Graph
should be consumed in the process. What is the most idiomatic and memory-safe approach to achieve this, considering Rust's ownership and borrowing rules?
Flashcards
What is the Copy trait in Rust?
What is the Copy trait in Rust?
Determines how Rust handles assignment operations for a type. If a type has the Copy trait, assigning it will create a duplicate of the original data.
What is trait?
What is trait?
A property defined as a function with a specific purpose.
What happens during Copy
?
What happens during Copy
?
When a type has the Copy trait, assigning a variable of that type to another variable results in a bitwise copy of the data.
s2 = s1
with Copy
Trait
s2 = s1
with Copy
Trait
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Validity after Copy
?
Validity after Copy
?
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delete []s1; s1 = nullptr;
delete []s1; s1 = nullptr;
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Problem with printing 's2' after deleting 's1'?
Problem with printing 's2' after deleting 's1'?
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Multiple owners (pointers) of same memory?
Multiple owners (pointers) of same memory?
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Dangers of duplicating pointers?
Dangers of duplicating pointers?
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What is a trait in Rust?
What is a trait in Rust?
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Copy trait in Rust
Copy trait in Rust
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Move trait (conceptually) in Rust
Move trait (conceptually) in Rust
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Move vs Copy
Move vs Copy
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Heap
Heap
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Stack
Stack
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String Type
String Type
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Reference
Reference
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Borrowing
Borrowing
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Immutable References
Immutable References
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Offset
Offset
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Capacity
Capacity
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Mutable String (String)
Mutable String (String)
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String Slice
String Slice
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push_str
push_str
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Dangling Pointer
Dangling Pointer
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Memory Reallocation
Memory Reallocation
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Memory Deallocation
Memory Deallocation
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Borrowing Rules
Borrowing Rules
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Invalid Slice
Invalid Slice
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Non-static Method References
Non-static Method References
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Mutable Reference
Mutable Reference
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+=
and Mutable References
+=
and Mutable References
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.len()
and Immutable References
.len()
and Immutable References
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String::len(&self)
String::len(&self)
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Multiple Immutable References
Multiple Immutable References
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Undefined Behavior (C)
Undefined Behavior (C)
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Move (C)
Move (C)
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Copy (C)
Copy (C)
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Ownership (Rust)
Ownership (Rust)
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Move Operation (Rust)
Move Operation (Rust)
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Copy Trait (Rust)
Copy Trait (Rust)
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Ownership Rule Application
Ownership Rule Application
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Borrow of Moved Value Error
Borrow of Moved Value Error
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Ownership Transfer to Function
Ownership Transfer to Function
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Error E0382 (Rust)
Error E0382 (Rust)
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Study Notes
Rust Programming Course 2
- The course will cover the String type, Ownership management, Borrowing and References, Reborrowing and Optimizations
Prerequisite: String Type
- Some things about strings need to be quickly understood for this course.
- The rust type is String
- It is Dynamic and can increase in size
- The encoding is UTF-8
- Common operations are addition, substring, find, etc
- Strings will be covered in more detail in another course.
String Examples
- To create a string,
String::from("a string")
is used - To get the length of a string, the
.len()
method can be used String::from("a string").len()
will output 8- To concatenate strings, the
+=
operator can be used, or the.push_str(...)
method - To concatenate
"456"
to string"123"
,s += "456"
ors.push_str("456")
can be used - The
.push_str()
method will add the string to the end of the original - To obtain a substring of a string, the range operator can be used
&s[1..3]
will be"BC"
whens
is"ABCDEFG"
Additional Information On Strings
- Strings in Rust are complex and require more in-depth analysis.
- The explanation given should be sufficient for the moment.
Ownership
- In Rust, every memory zone has one and only one owner at a time.
- Every owner has a lifetime, which means it exists within a scope.
- Once an owner goes out of scope, its memory zone is freed.
- "Freed" in the context of ownership has a different meaning and it depends on where the memory zone lies - stack, heap, or global.
Variable Ownership Example
- Every variable or a parameter can own the memory zone it represents
- A variable of type
u32
takes up 4 bytes in stack memory - You can say that the memory from offset 99.996 to 100.000 is owned by the variable sum
Owner and Memory Case
- The main function contains a mutable
u32
variablesz
initialized to 0, and a nested scope - Within the nested scope, a mutable String variable
s
is created from "abc" - Then,
"456"
is pushed intos
andsz
gets the length ofs
as au32
and thens
is printed - After the scope,
sz
is printed Sz
is located on the stack and takes up 4 bytess
is located in the stack and the heaps
stack(12 or 24 bytes) and heap (3 bytes)- A new space of 6 characters is allocated on the heap when “456” is added
- The original text
"abc"
is copied in the new location in the head - The old (3 bytes) space from the heap is freed
- The scope of
"s"
has ended so the compiler decides to free all memory owned by"s"
- Freeing
"s"
means all heap memory is freed - Stack memory where len, capacity, and chars pointer are stored are also cleared
- "s" is no longer valid, and accessing it results in a compiler error
- At that point, the scope of "sz" has ended and as such it is freed (all stack space is cleared).
'C'' and 'C++' Code
- A similar "C" code implies freeing the heap manually and if the action is not performed, memory leak will happen
- Modern C++ has unique pointers which are similar to Rust's system
C/C++ Ownership Problem
- In the following C/C++ code,
char* s2 = s1;
is problematic - Both s1 and s2 point to the same memory location, thus there can be only one owner, not two
- Once s1 pointer is deleted, the memory zone assigned to s1 is freed
- When the program accesses the content of s2, now pointing to already freed memory, the behavior is undefined, and it will likely crash
Rust Concept: Traits
- Rust has traits which act as properties for each variable, and explain how operations can be performed
- Copy, and Move are important traits in Rust
- Move trait does not exist in Rust
- It exits in the slides only to simplify the explanation
- Copy trait does exits in Rust
Example
- There exists a called Student:
- MathGrade is a
type u8
- EnglishGrade is a
type u8
- Name is a
heap buffer
- If type Student implements Copy trait then doing
s2 = s1
statement will copy MathGrade, EnglishGrade and Name to s2
- MathGrade is a
- Name pointer to address 200.000
- If type Student implements Move trait then doing
s2 = s1
statement will copy MathGrade, EnglishGrade and sets a pointer to address 100.000
Details On Copy
Bitwise copy the value of s1.MathGrade into s2.MathGrade
Bitwise copy the value of s1.EnglishGrade into s2.EnglishGrade
Allocated 4 bytes to a new location on the heap and assign s2.Name pointer to that location
Bitwise copy 4 bytes from address 100.000 (s1.Name) to address 200.000 (s2.Name)
Details On Move
Bitwise copy the value of s1.MathGrade into s2.MathGrade
Assign s2.Name pointer to the offset 100.000
Clear the value of pointer s1.Name so that only one object points to the offset 100.000
Move Vs Copy
- The worst thing is to duplicate the pointer (make two owners).
- Copy and Move traits prevent this issue
- The undefined behabior C code can be prevented using different strategies:
- Make copy - C code
- Make move - C code
- Rust defaults to move for all objects except for the case where Copy trait is set
- Basic types types (u8..u128, i8..i128, bool, isize, usize, char) implement Copy trait
Advantages to move or copy trait
- No dangling pointers
- No data races
- Every assignment, passing a parameter or return to/from function triggers Ownership rules
Rust examples with move and copy
- Copy
let s2 = s; println!("{s2}");
- Compile Ok - Move
let s2 = s; println!("{s}");
- Compile Error - Transfer from function will also cause Compiler Error
value borrowed here after move
- Returning the variable to the original owner solves the borrow issue, at the cost of readability/usability
Borrowing
- Sometimes the original rules for ownership are too restrictive, so there exists a concept called borrowing
- Most programming languages use references, so Rust decided to use Borrowing paradigm
- An object has been borrowed and will be returned to its owner
- references in Rust is denoted by the symbol
&
- a dereference process is performed with the symbol
*
- Immutable and mutable references
- By default it is immutable
- Use mut for mutable
How does Borrowing work
- Putting ‘rdx” register to show the offset where the constant string “123” lies in memory
- Then “rcx” stack offset where variable "s” should be created
- Copy was created in code “rcx” so there is no modification of register value.
Rules for References
- Only one mutable refernce can exists toward object over time
- Many immutable references can exits and can not change the value of the object.
- Immutable and mutable object should be used and called as needed, and should't be long life so the compilation could occur without error
What are Slices
- They hold a pointer to a size
Reborrowing
- When an object is passed, it is expected to be unable to be reused, reborrowing allows rust to reuse objects.
- Rust performs Copy for immutable variables, and Move for mutable variables. For references it uses a new concept called reborrowing allowing for easier code
- If ownership was lost after first object, code wouldn't work at all if it calls the object twice
- It is still only temporary and for singular scopes.
Under The Hood
-
We create
mut_ref_to_s
(only ONE mutable reference towards variable s) -
We reborrow
mut_ref_to_s
to function foo -
Where it will be used as “x"
-
this as we temporary create an alias for
mut_ref_to_s
that is called x -
Can only be used within the function foo.
-
At any given time, there is only ONE available to use mutable reference towards object “s"
-
While the 2nd mutable reference is in action, the is not so the code still functions correctly
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