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Questions and Answers
For a second-order reaction, what is the relationship between half-life and the initial concentration of reactant A?
For a second-order reaction, what is the relationship between half-life and the initial concentration of reactant A?
- Half-life is proportional to the square of the initial concentration of A.
- Half-life is directly proportional to the initial concentration of A.
- Half-life is inversely proportional to the initial concentration of A. (correct)
- Half-life is independent of the initial concentration of A.
The rate constant, $k$, is found to be the same as the slope of the line when graphing [A]⁻¹ versus time. What is the order of the reaction?
The rate constant, $k$, is found to be the same as the slope of the line when graphing [A]⁻¹ versus time. What is the order of the reaction?
- Second order (correct)
- First order
- Third order
- Zeroth order
How does the half-life of a first-order reaction change as the reaction progresses?
How does the half-life of a first-order reaction change as the reaction progresses?
- It decreases linearly.
- It increases linearly.
- It decreases exponentially.
- It remains constant. (correct)
In a proposed reaction mechanism, a certain species appears in one step but is consumed in a later step. What is this species called?
In a proposed reaction mechanism, a certain species appears in one step but is consumed in a later step. What is this species called?
How does an increase in temperature generally affect the rate of a chemical reaction?
How does an increase in temperature generally affect the rate of a chemical reaction?
According to collision theory, what two factors influence whether a collision between reactant molecules will lead to a reaction?
According to collision theory, what two factors influence whether a collision between reactant molecules will lead to a reaction?
What is the primary role of a catalyst in a chemical reaction?
What is the primary role of a catalyst in a chemical reaction?
In the Arrhenius equation, $k = A e^{-E_a/RT}$, what does the term 'A' represent?
In the Arrhenius equation, $k = A e^{-E_a/RT}$, what does the term 'A' represent?
The elementary reaction $A + 2B \rightarrow C$ has what order rate law?
The elementary reaction $A + 2B \rightarrow C$ has what order rate law?
What does the steady-state approximation assume about the concentration of reaction intermediates in a reaction mechanism?
What does the steady-state approximation assume about the concentration of reaction intermediates in a reaction mechanism?
Which type of kinetics is described with the integrated rate law: $[A] = [A]_0 - kt$?
Which type of kinetics is described with the integrated rate law: $[A] = [A]_0 - kt$?
Consider the following two-step mechanism:
Step 1: $A \rightleftharpoons B$ (fast equilibrium)
Step 2: $B + C \rightarrow D$ (slow).
What is the rate law derived from this mechanism?
Consider the following two-step mechanism: Step 1: $A \rightleftharpoons B$ (fast equilibrium) Step 2: $B + C \rightarrow D$ (slow). What is the rate law derived from this mechanism?
For a unimolecular elementary reaction, what can be said about the rate law?
For a unimolecular elementary reaction, what can be said about the rate law?
The activation energy ($E_a$) for a reaction is determined to be $50 \text{ kJ/mol}$. By what factor will the rate constant increase when the temperature is raised from 300 K to 310 K? (Assume the pre-exponential factor A is constant.)
The activation energy ($E_a$) for a reaction is determined to be $50 \text{ kJ/mol}$. By what factor will the rate constant increase when the temperature is raised from 300 K to 310 K? (Assume the pre-exponential factor A is constant.)
Which statement best describes a 'rate-determining step' in a multi-step reaction?
Which statement best describes a 'rate-determining step' in a multi-step reaction?
If the rate of a reaction increases significantly when a catalyst is added, what can be inferred about the activation energy of the catalyzed reaction compared to the uncatalyzed reaction?
If the rate of a reaction increases significantly when a catalyst is added, what can be inferred about the activation energy of the catalyzed reaction compared to the uncatalyzed reaction?
Radioactive decay follows first-order kinetics. If a radioactive substance has a half-life of 10 years, how much of the substance will remain after 30 years?
Radioactive decay follows first-order kinetics. If a radioactive substance has a half-life of 10 years, how much of the substance will remain after 30 years?
For the elementary reaction, $A + B \rightarrow products$, the rate constant at 25°C is $5.0 \times 10^{-3} \text{ M}^{-1}s^{-1}$ and at 75°C is $9.0 \times 10^{-2} \text{ M}^{-1}s^{-1}$. What is the activation energy ($E_a$) for this reaction?
For the elementary reaction, $A + B \rightarrow products$, the rate constant at 25°C is $5.0 \times 10^{-3} \text{ M}^{-1}s^{-1}$ and at 75°C is $9.0 \times 10^{-2} \text{ M}^{-1}s^{-1}$. What is the activation energy ($E_a$) for this reaction?
Which of the following statements is true regarding the use of the steady-state approximation in kinetics?
Which of the following statements is true regarding the use of the steady-state approximation in kinetics?
Consider a reaction mechanism with the following steps:
Step 1: $A + B \rightleftharpoons C$ (fast equilibrium)
Step 2: $C + A \rightarrow D$ (slow)
If the rate of the overall reaction is found to be $Rate = k[A]^2[B]$, what can be concluded about the reaction?
Consider a reaction mechanism with the following steps: Step 1: $A + B \rightleftharpoons C$ (fast equilibrium) Step 2: $C + A \rightarrow D$ (slow) If the rate of the overall reaction is found to be $Rate = k[A]^2[B]$, what can be concluded about the reaction?
The half-life of a radioactive isotope is 1 hour. If you start with 100 grams of the isotope, how much will remain after 3 hours?
The half-life of a radioactive isotope is 1 hour. If you start with 100 grams of the isotope, how much will remain after 3 hours?
In enzyme kinetics, a homogeneous catalyst affects a reaction by existing in what physical state compared to the reactants?
In enzyme kinetics, a homogeneous catalyst affects a reaction by existing in what physical state compared to the reactants?
How does an increase in the structural complexity of reactants affect the rate of an elementary process, assuming all other factors remain constant?
How does an increase in the structural complexity of reactants affect the rate of an elementary process, assuming all other factors remain constant?
Given the following rate constants ($k$) measured at two temperatures ($T$) for a particular reaction: $k_1 = 1.0 \times 10^{-4} s^{-1}$ at $T_1 = 300 K$ and $k_2 = 5.0 \times 10^{-4} s^{-1}$ at $T_2 = 330 K$. Calculate the activation energy ($E_a$) for this reaction in kJ/mol.
Given the following rate constants ($k$) measured at two temperatures ($T$) for a particular reaction: $k_1 = 1.0 \times 10^{-4} s^{-1}$ at $T_1 = 300 K$ and $k_2 = 5.0 \times 10^{-4} s^{-1}$ at $T_2 = 330 K$. Calculate the activation energy ($E_a$) for this reaction in kJ/mol.
Flashcards
Reaction Mechanism
Reaction Mechanism
A sequence of elementary processes that shows how reactants are converted into products.
Elementary Process
Elementary Process
A specific collisional event or molecular process in a reaction mechanism.
Reaction Intermediate
Reaction Intermediate
Species that appears in the mechanism but cancels out to form the chemical equation
Collision Theory
Collision Theory
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Activated Complex
Activated Complex
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Transition State
Transition State
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Activation Energy (Ea)
Activation Energy (Ea)
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Multistep Reaction
Multistep Reaction
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Rate Determining Step
Rate Determining Step
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Rate of Consumption
Rate of Consumption
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Steady-State Approximation
Steady-State Approximation
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Arrhenius Equation
Arrhenius Equation
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Catalyst
Catalyst
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Homogeneous Catalysis
Homogeneous Catalysis
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Heterogeneous Catalysis
Heterogeneous Catalysis
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Graphical Method
Graphical Method
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Half-life (t1/2)
Half-life (t1/2)
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Zeroth-Order Half-Life
Zeroth-Order Half-Life
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First-Order Half-Life
First-Order Half-Life
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Second-Order Half-Life
Second-Order Half-Life
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Study Notes
- Graphical approach can determine if a reaction is zeroth, first, or second-order.
- Plot the data to analyze the reaction order and find the rate constant, k.
Reaction Orders
- For the reaction NH4NCO(aq) → (NH2)2CO(aq), the data is plotted for zeroth, first, and second orders to determine reaction order
- [A] versus t plot isn't linear; the reaction isn't zeroth order
- ln[A] versus t plot isn't linear; the reaction isn't first order
- 1/[A] versus t plot is linear; the reaction is determined to be second order
- The second-order rate equation is y = 0.0502x + 10.164
- The slope equals the rate constant, k
- k = 0.0502 mol-1 L min-1
Half-Life
- The half-life (t1/2) is the time for the concentration of A to decrease to one-half of its initial amount: [A] = (1/2)[A]₀ at t = t1/2
- Expressions can be derived for half-lives of zeroth-, first-, and second-order reactions.
Zeroth-Order Reaction Half-Life
- t = t1/2, [A]₀ = [A]₀ - kt1/2
- t1/2 = [A]₀ / 2k
- The half-life is directly proportional to the starting concentration.
- As the concentration of A decreases, so does the half-life.
First-Order Reaction Half-Life
- t = t1/2, ln([A]₀/[A]) = kt1/2
- t1/2 = ln(2)/k
- The half-life is independent of the starting concentration.
Second-Order Reaction Half-Life
- t = t1/2, 1/[A] = 1/[A]₀ + kt1/2
- t1/2 = 1/(k[A]₀)
- The half-life is inversely proportional to the starting concentration.
- As the concentration of A decreases, the half-life increases.
- In all cases, half-life is inversely proportional to k, where a larger k results in a faster reaction and a shorter half-life.
Successive Half-Lives
- Successive half-lives are the lengths of time it takes for the concentration of A to be successively "cut in half"
- First half-life refers to the time it takes for [A] to decrease from [A]₀ to (1/2)[A]₀
- Second half-life refers to the time it takes for [A] to decrease from (1/2)[A]₀ to (1/4)[A]₀
- Third half-life refers to the time it takes for [A] to decrease from (1/4)[A]₀ to (1/8)[A]₀
Graphical Deduction of Half-Lives
- In a zeroth-order reaction, successive half-lives decrease by a factor of two each time
- In a first-order reaction, successive half-lives are equal and do not change
- In a second-order reaction, successive half-lives increase by a factor of two each time
Nuclear Decay
- Nuclear decay follows first-order kinetics
- The nuclear decay of carbon-14 is: ¹⁴C → ¹⁴N + e⁻
- The half-life of carbon-14 is 5730 years
- Living organisms maintain constant levels of ¹⁴C; the amount of ¹⁴C decreases slowly with time after death
Summary of Zero-Order Kinetics
- Differential rate law: Rate = k
- Integrated rate law: [A] = [A]₀ - kt
- Units of k: mol L⁻¹ s⁻¹
- Half-life: t₁/₂ = [A]₀ / 2k
- Successive half-lives: decrease by a factor of two each time
- Graphical: [A] versus t is linear with slope -k
Summary of First-Order Kinetics
- Differential rate law: Rate = k[A]
- Integrated rate law: [A] = [A]₀e^(-kt)
- Units of k: s⁻¹
- Half-life: t₁/₂ = ln(2) / k
- Successive half-lives: are equal/do not change
- Graphical: ln[A] versus t is linear with slope -k
Summary of Second-Order Kinetics
- Differential rate law: Rate = k[A]²
- Integrated rate law: 1/[A] = 1/[A]₀ + kt
- Units of k: mol⁻¹ L s⁻¹
- Half-life: t₁/₂ = 1 / (k[A]₀)
- Successive half-lives: increase by a factor of two each time
- Graphical: 1/[A] versus t is linear with slope +k
Reaction Mechanisms
- The reaction mechanism is a sequence of elementary processes that shows how reactants are converted into products
- An elementary process is a specific collisional event or molecular process
Elementary Steps and Intermediates
- Each elementary step has its own rate constant
- An intermediate appears in the mechanism but not in the overall reaction (e.g., O atom in ozone conversion)
- A reversible step is emphasized with ⇌, while an irreversible step is emphasized with →
Conversion of Ozone
- The mechanism shows that the conversion of O₃ into O₂ involves:
- Dissociation of O₃ into O₂ + O
- A reactive collision between O₃ and O
- The overall equation shows the net conversion of 2 molecules of O₃ to 3 molecules of O₂, not a direct collision between O₃ molecules
IUPAC Convention for Rate Constants
- Rate constants for each step are numbered sequentially (k₁, k₂, k₃, etc.)
- The rate constant for the reverse reaction of step "n" is denoted as k₋ₙ
Factors Affecting the Rate of an Elementary Process
- Collision theory is used to predict the rates of elementary processes
- Rate of an elementary process is ∝ ZAB × f × p
Collision Theory Terms
- ZAB = total collision rate ∝ [A][B]
- f = fraction of collisions with sufficient kinetic energy
- p = fraction of collisions with correct alignment
- Typically, ZAB is greater than 10³⁰ collisions per litre per second
Reaction Requirements
- A reaction results only if the reactants collide with sufficient energy and a favorable alignment
- Not all collisions lead to a reaction
Favorable Collision Example
- NO₂Cl + Cl → NO₂ + Cl₂ is a favorable collision forming NO₂ and Cl₂
- The short-lived, high-energy complex formed when kinetic energy is converted into potential energy is called the activated complex
- A collision between NO₂Cl and Cl that is much less favourable for forming NO₂ and Cl₂ occurs with incorrect alignment
Potential Energy Diagrams and Reaction Profiles
- Potential energy (PE) diagrams and reaction profiles illustrate the changes in potential energy during an elementary process
- The transition state is the state of maximum potential energy where the activated complex is present
- The activation energy (Ea) is the energy required to form the activated complex
Activation Energy and Reaction Rates
- Ea is the activation energy
- The activation energies for forward and reverse reactions are related by: ΔH = Efor - Erev
- The activated complex can either go towards products or revert back to reactants
- Reactant molecules must collide with sufficient kinetic energy (KE ≥ Efor) to form products
- The higher the activation energy for an elementary process, the slower the rate
- The greater the structural complexity of the reactants, the slower the rate
Rate Laws for Elementary Processes
- Collision theory states the rate law for an elementary process is determined by the number of reactant molecules involved
- For two reactants A and B: Rate ∝ ZAB × f × p
Kinetic Theory
- The collision frequency is proportional to [A] and [B]
- Given the constant "k", Rate = constant × [A][B] × e^(-Ea/RT) × p
Reaction Classifications
- A → products is a unimolecular process with Rate = k[A], following a first-order rate law
- A + A → products is a bimolecular process with Rate = k[A]²
- A + B → products is a bimolecular process with Rate = k[A][B]
- Bimolecular processes have second-order rate laws
- A + A + A → products is a termolecular process with Rate = k[A]³
- 2A + B → products is a termolecular process with Rate = k[A]²[B]
- A + B + C → products is a termolecular process with Rate = k[A][B][C]
- Termolecular processes have third-order rate laws
- The rules apply only when the process occurs in a single step
Multi-step Reactions
- Involve two or more elementary processes, the reaction profile includes two or more transition states, one for each step
- The rate-determining step corresponds to the elementary step with the transition state of highest energy
- Having highest activation energy does not necessarily make a step rate-determining
Mechanisms
- Step 1 has the highest activation energy but is not the slowest step
- Once B is formed, it will be converted back into A more rapidly than it will be converted into C
- As a result, the concentration of B is very small, and the rate of conversion of B into C is very slow
- The rate of production of C is ultimately determined by the rate of conversion of B into C
- In the given reaction profile, step 2 is the rate-determining step, even though step 1 has the smallest rate constant
Determining Rate Law
- Combine the rate laws for individual elementary processes to deduce the rate law for the overall reaction
- To ensure consistency with the observed rate law, derive the rate law for the mechanism
- Two important cases to consider; whether or not we know which step is the rate-determining step
Case One
- Case #1: Deriving the rate law when the rate-determining step is known
- If which step is the slowest is assumed, the slowest step determines how fast products will be formed
- Rate of the overall reaction ≈ Rate of the slowest step
Case Two
- Case #2: Deriving the rate law when the rate-determining step is not known
- Deriving the rate law if the energies of the various transition states in a multistep reaction are approximately equal
- The following strategy can be employed:
- Pick any reactant or product appearing in the overall reaction
- Identify steps in the mechanism that involve that particular reactant or product
- Combine the rate laws for those steps algebraically to obtain an expression for the rate of consumption or the rate of production of that particular reactant or product
- Simplify the resulting expression to obtain the rate law for the overall reaction (cannot include the concentration of any intermediate species)
Steady State Approximation
- The steady-state approximation assumes that the rate of production of an intermediate is approximately equal to the rate of its consumption
Justifying Steady State Approximation
- Step 1: NO₂Cl ⇌ NO₂ + Cl
- Step 2: NO₂Cl + Cl → NO₂ + Cl₂
- Overall: 2 NO₂Cl → 2 NO₂ + Cl₂
- Rate of producing Cl = k[NO₂Cl]
- Rate of consuming Cl = k₋₁[NO₂][Cl] + k₂[NO₂Cl][Cl] = {k₋₁[NO₂] + k₂[NO₂Cl]}[Cl]
Changing Rates
- The rate of producing Cl is large initially because [NO₂Cl] is large in the initial stages
- However, the rate of production decreases as NO₂Cl is consumed
- The rate of consuming Cl is zero initially because [Cl] = 0 at time t = 0
- Initially, Cl is being produced faster than it is being consumed, and as [Cl] increases, so too does the rate of consumption of Cl
- Eventually, the rate of production and the rate of consumption become equal, [Cl] remains constant until the later stages of the reaction
- In later stages, [NO₂Cl] becomes very small, and the rate of production of Cl decreases
Arrhenius Equation
- k = A * e^(-Ea/RT) where the fraction of molecules, f, that has KE ≥ Ea, is given by f≈ e^(-Ea/RT)
Temperature
- According to collision theory, the rate of an elementary reaction depends on these factors:
- the collision frequency
- the fraction of collisions with sufficient kinetic energy to lead to a reaction
- the fraction of collisions that have a favorable alignment for a given reaction to occur
- Rate ∝ ZAB × f × p, where ZAB is the collision rate, f is the collision kinetic energy, and p is the fraction for correct alignment
- A relatively small decrease in activation energy can cause a significant increase in the value of the rate constant
Steric Factor
- p represents steric factor to show that the steric factor decreases as the the structural complexity the reactants increase
Catalysts
- Catalyst ↔ provides a new mechanism with a lower activation energy
- A catalyst lowers the energy requirements which allows a greater fraction of collisions and changes the mechanism
- The uncatalyzed has Ea = 75.3 kJ mol⁻¹, but the number of steps in the mechanism is not known, so its impossible to be completely specified completely
- Catalyzed reaction proceeds via a two-step mechanism
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