Rational Numbers

$\pi$

$-\sqrt{2}$

$\sqrt{3}$

$\frac{1},{2}$ (correct)

$2x^2 + 3x - 5 = 0$

$\frac{x},{2} = 3$ (correct)

$\sqrt{x} = 5$

$x^3 - 2x^2 + x = 0$

$-2$

$2$ (correct)

$\frac{1},{4}$

$-4$