Radical Equations Algebra 2 Flashcards
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Questions and Answers

What is the solution to the equation that results in x = 32?

  • x = -32
  • x = 0
  • x = 32 (correct)
  • x = 16
  • What are the possible solutions to the equation resulting in x = ±125?

  • x = 0
  • x = -125
  • x = 125
  • Both A and B (correct)
  • What is the solution for x if x = 20 (x ≠ 5)?

  • x = 20 (correct)
  • x = -5
  • x = 5
  • No solution
  • What is the solution if x = 5 (x ≠ -2)?

    <p>x = 5</p> Signup and view all the answers

    What is the solution for x when x = 67?

    <p>67</p> Signup and view all the answers

    What are the solutions if x = 1 or x = 3?

    <p>1, 3</p> Signup and view all the answers

    What is the solution for x if x = 3 (x ≠ -2)?

    <p>3</p> Signup and view all the answers

    What is the solution to the equation when x = 4?

    <p>4</p> Signup and view all the answers

    What is the solution for x if x = 44?

    <p>44</p> Signup and view all the answers

    What is the solution when x = 8?

    <p>8</p> Signup and view all the answers

    What is the solution when x = 3?

    <p>3</p> Signup and view all the answers

    What is the solution when x = -1?

    <p>-1</p> Signup and view all the answers

    What is the solution to the radical equation √x = 7?

    <p>49</p> Signup and view all the answers

    What is the solution for the equation 4 = √-2y?

    <p>-8</p> Signup and view all the answers

    What is the solution to the equation √(2x - 5) = 7?

    <p>27</p> Signup and view all the answers

    What is the solution for the equation √(x - 7) = 3?

    <p>16</p> Signup and view all the answers

    What is the solution to the equation -10 + √x = 5?

    <p>225</p> Signup and view all the answers

    What is the solution to the equation 4√(2x - 1) = 12?

    <p>5</p> Signup and view all the answers

    What is the solution for √(12x - 3) = √(4x + 93)?

    <p>12</p> Signup and view all the answers

    What is the solution for √(x - 1) = √(3x - 5)?

    <p>2</p> Signup and view all the answers

    What is the solution for the equation 5 = √(x + 1)?

    <p>24</p> Signup and view all the answers

    What is the solution when 2 = √(-2x)?

    <p>-2</p> Signup and view all the answers

    What is the solution to the equation √(4x - 8) = 6?

    <p>11</p> Signup and view all the answers

    What is the solution to 4 + √(x + 10) = 12?

    <p>54</p> Signup and view all the answers

    What is the solution to √(4x - 8) = √(x + 3)?

    <p>11/3</p> Signup and view all the answers

    What is the solution to ∛(2x + 14) = 4?

    <p>25</p> Signup and view all the answers

    What are the solutions to the equation √(8x - 15) = x?

    <p>5, 3</p> Signup and view all the answers

    What is the solution to the equation √(2x + 24) = x?

    <p>6</p> Signup and view all the answers

    What is the solution for the equation √(3x + 28) - x = 0?

    <p>7</p> Signup and view all the answers

    What is the solution for -4 ³√(x + 10) + 3 = 15?

    <p>-37</p> Signup and view all the answers

    What is the solution for (c + 2)¾ - 1 = 7?

    <p>14</p> Signup and view all the answers

    What is the solution when √(7x + 15) = x + 1?

    <p>7</p> Signup and view all the answers

    Study Notes

    Solving Radical Equations

    • Solutions to radical equations must be verified for extraneous roots which can appear during the solving process.
    • Various forms of solutions include single values, positives and negatives, or multiple disallowed values.

    Specific Solutions

    • x = 32: A straightforward radical equation with no extraneous solutions.
    • x = ±125: Indicates two possible solutions; check for extraneous values.
    • x = 20 (x ≠ 5) and x = 5 (x ≠ -2): Requires verification to exclude invalid results.
    • x = 67, x = 44, x = 1 or 3, x = 4, x = 8, x = 3 (x ≠ -2), x = 12: All solutions require extraneous checks.
    • x = -1, x = 49, x = -8: Solutions obtained from solving simple radical equations, some needing verification for extraneous results.
    • x = 27: Result from the equation √(2x - 5) = 7.
    • x = 16: Obtained from solving √(x - 7) = 3.
    • x = 225: Derived from -10 + √x = 5.
    • x = 5: Found through the equation 4√(2x - 1) = 12.
    • x = 2: Result from √(x - 1) = √(3x - 5).
    • x = 24: Solution to 5 = √(x + 1).
    • x = -2: From the equation 2 = √(-2x).
    • x = 11, x = 54, x = 11/3, x = 25: Each of these results comes from different radical equations requiring careful investigation of all potential solutions.

    Critical Concepts

    • Solutions may appear valid but must be tested against the criteria of the original equation.
    • Disallowed values (e.g., x ≠ -2) indicate restrictions based on radical equations, preventing certain solutions from being legitimate.
    • Certain problems involve cube roots (e.g., x = 25 from ∛(2x + 14) = 4) which expands the type of radical equations encountered.

    General Strategy

    • Isolate the radical expression before squaring both sides to eliminate the root.
    • Retain attention on the potential for extraneous solutions that could arise from the squaring process.
    • Always simplify and communicate solutions clearly, addressing any restrictions explicitly.

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    Description

    Test your knowledge of solving radical equations with these flashcards designed for Algebra 2 students. Each card presents a unique equation to solve while reminding you to check for extraneous solutions. This quiz will reinforce your understanding of key concepts in radical equations.

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