Recent Lessons

Show all results for ""

Feature Overview

Ace your exams with our all-in-one platform for creating and sharing quizzes and tests.

Quizzes

Create quizzes and tests automatically from your content using AI.

Flashcards

Automatically turn your notes into digital flashcards.

Share, Export & Embed

Share with classmates or export to Excel and your learning management system.

Stats & Reporting

Auto-grading quizzes and tests with detailed stats and reports.

Mobile Apps

The smarter way to study – wherever you are.

Pricing

Search...

Qualitative Analysis of Group I Cations Experiment

15 Questions

1 Views

Qualitative Analysis of Group I Cations Experiment

Choose a study mode

Play Quiz

Study Flashcards

Spaced Repetition

Chat to lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

Lead(II) chloride can be separated from the other two chlorides based on its increased solubility at higher temperatures. This means that lead(II) chloride will dissolve in hot water, leaving the mercury(I) chloride and the silver chloride in solid form: ______(s) ⟶ Pb2+ (aq) + 2Cl− (aq)

PbCl2

The presence of in the aqueous solution can then be confirmed by the formation of a yellow precipitate of PbCrO4 upon the addition of aqueous K2CrO4: (aq) + CrO4−2 (aq) ⟶ PbCrO4.

Pb2+

Their separation from all other ______ may be accomplished by the addition of 6 M HCl (aq) resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s)

ions

Resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s): AgNO3 + HCl → AgCl ↓+ HNO3 Pb(NO3)2 + 2HCl → PbCl2↓ + 2HNO3 Hg2(NO3)2 + 2HCl → Hg2Cl2↓+ 2HNO3

addition of 6 M HCl (aq) Signup and view all the answers

Their separation from all other ions may be accomplished by the addition of 6 M HCl (aq) resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s)

insoluble chlorides Signup and view all the answers

What are the products formed when AgNO3 reacts with HCl?

AgCl Signup and view all the answers

What is the increased solubility at higher temperatures used for in the separation of lead(II) chloride?

Dissolving lead(II) chloride in hot water Signup and view all the answers

What is the confirmation of the presence of Pb2+ in the aqueous solution?

Formation of a yellow precipitate of PbCrO4 upon addition of aqueous K2CrO4 Signup and view all the answers

How can lead(II) chloride be separated from the other two chlorides?

By its increased solubility at higher temperatures Signup and view all the answers

What happens when Hg2(NO3)2 reacts with 2HCl?

Formation of Hg2Cl2 Signup and view all the answers

Match the following ions with their corresponding insoluble chlorides:

Ag+ = AgCl Pb2+ = PbCl2 Hg22+ = Hg2Cl2 Cl- = PbCrO4 Signup and view all the answers

Match the following reactions with their resulting precipitates:

AgNO3 + HCl = AgCl ↓ Pb(NO3)2 + 2HCl = PbCl2↓ Hg2(NO3)2 + 2HCl = Hg2Cl2↓ Pb2+ (aq) + CrO4−2 (aq) = PbCrO4 Signup and view all the answers

Match the following substances with their primary role in separation:

6 M HCl (aq) = Precipitation of insoluble chlorides Hot water = Increased solubility of PbCl2 Aqueous K2CrO4 = Confirmation of Pb2+ presence AgNO3, Pb(NO3)2, Hg2(NO3)2 = Formation of precipitates Signup and view all the answers

Match the following substances with their respective uses in the process:

AgNO3, Pb(NO3)2, Hg2(NO3)2 = Formation of precipitates 6 M HCl (aq) = Separation from other ions Hot water = Dissolving lead(II) chloride Aqueous K2CrO4 = Confirming presence of Pb2+ Signup and view all the answers

Match the following statements with their corresponding processes:

Addition of 6 M HCl (aq) = Separation from all other ions Increased solubility at higher temperatures = Dissolving lead(II) chloride Formation of yellow precipitate of PbCrO4 = Confirmation of Pb2+ presence Precipitation of AgCl, PbCl2, and Hg2Cl2 = Resulting from addition of HCl Signup and view all the answers

Qualitative Analysis of Group I Cations Experiment

Choose a study mode

Podcast

Questions and Answers

Lead(II) chloride can be separated from the other two chlorides based on its increased solubility at higher temperatures. This means that lead(II) chloride will dissolve in hot water, leaving the mercury(I) chloride and the silver chloride in solid form: ______(s) ⟶ Pb2+ (aq) + 2Cl− (aq)

The presence of in the aqueous solution can then be confirmed by the formation of a yellow precipitate of PbCrO4 upon the addition of aqueous K2CrO4: (aq) + CrO4−2 (aq) ⟶ PbCrO4.

Their separation from all other ______ may be accomplished by the addition of 6 M HCl (aq) resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s)

Resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s): AgNO3 + HCl → AgCl ↓+ HNO3 Pb(NO3)2 + 2HCl → PbCl2↓ + 2HNO3 Hg2(NO3)2 + 2HCl → Hg2Cl2↓+ 2HNO3

Their separation from all other ions may be accomplished by the addition of 6 M HCl (aq) resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s)

What are the products formed when AgNO3 reacts with HCl?

What is the increased solubility at higher temperatures used for in the separation of lead(II) chloride?

What is the confirmation of the presence of Pb2+ in the aqueous solution?

How can lead(II) chloride be separated from the other two chlorides?

What happens when Hg2(NO3)2 reacts with 2HCl?

Match the following ions with their corresponding insoluble chlorides:

Match the following reactions with their resulting precipitates:

Match the following substances with their primary role in separation:

Match the following substances with their respective uses in the process:

Match the following statements with their corresponding processes:

More Like This

Pharmaceutical Analytical Chemistry-I Methods Quiz

Chemical Analysis: Qualitative and Quantitative Analysis

Analytical Chemistry Chapter 1

Introduction to Analytical Chemistry

Upgrade to continue

Qualitative Analysis of Group I Cations Experiment

Choose a study mode

Podcast

Questions and Answers

Lead(II) chloride can be separated from the other two chlorides based on its increased solubility at higher temperatures. This means that lead(II) chloride will dissolve in hot water, leaving the mercury(I) chloride and the silver chloride in solid form: ______(s) ⟶ Pb2+ (aq) + 2Cl− (aq)

The presence of ______ in the aqueous solution can then be confirmed by the formation of a yellow precipitate of PbCrO4 upon the addition of aqueous K2CrO4: ______ (aq) + CrO4−2 (aq) ⟶ PbCrO4.

Their separation from all other ______ may be accomplished by the addition of 6 M HCl (aq) resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s)

Resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s): AgNO3 + HCl → AgCl ↓+ HNO3 Pb(NO3)2 + 2HCl → PbCl2↓ + 2HNO3 Hg2(NO3)2 + 2HCl → Hg2Cl2↓+ 2HNO3

Their separation from all other ions may be accomplished by the addition of 6 M HCl (aq) resulting in the precipitation of AgCl(s), PbCl2(s), and Hg2Cl2(s)

What are the products formed when AgNO3 reacts with HCl?

What is the increased solubility at higher temperatures used for in the separation of lead(II) chloride?

What is the confirmation of the presence of Pb2+ in the aqueous solution?

How can lead(II) chloride be separated from the other two chlorides?

What happens when Hg2(NO3)2 reacts with 2HCl?

Match the following ions with their corresponding insoluble chlorides:

Match the following reactions with their resulting precipitates:

Match the following substances with their primary role in separation:

Match the following substances with their respective uses in the process:

Match the following statements with their corresponding processes:

More Like This

Pharmaceutical Analytical Chemistry-I Methods Quiz

Chemical Analysis: Qualitative and Quantitative Analysis

Analytical Chemistry Chapter 1

Introduction to Analytical Chemistry

The presence of in the aqueous solution can then be confirmed by the formation of a yellow precipitate of PbCrO4 upon the addition of aqueous K2CrO4: (aq) + CrO4−2 (aq) ⟶ PbCrO4.