热力学Process Quiz
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Questions and Answers

关于可逆过程的熵变化,下式正确的是?

  • ∆S(333K) = ∆S(373K) + ∫∆Cp,m dT (correct)
  • ∆S(333K) = ∆S(373K) / ∫∆Cp,m dT
  • ∆S(333K) = ∆S(373K) - ∫∆Cp,m dT
  • ∆S(333K) = ∆S(373K) × ∫∆Cp,m dT

在计算∆H(333K)时,需要考虑哪些因素?

  • ∆Cp 和 ∆T
  • ∆vapH 和 ∆Cp
  • ∆vapHmy 和 ∆CpΔT (correct)
  • ∆S 和 ∆G

∆H(333K)的值约为多少kJ?

  • 75.20kJ
  • 40.67kJ
  • 42.34kJ (correct)
  • 33.57kJ

什么是∆Cp,m?

<p>摩尔热容 (C)</p> Signup and view all the answers

什么是∆S(333K)的单位?

<p>J/K (D)</p> Signup and view all the answers

什么是基尔霍夫方程?

<p>应用基尔霍夫方程计算∆H (C)</p> Signup and view all the answers

∆S(333K)的值约为多少J·K⁻¹?

<p>113.7J·K⁻¹ (A)</p> Signup and view all the answers

Q的值约为多少J·K⁻¹?

<p>127.1J·K⁻¹ (B)</p> Signup and view all the answers

Study Notes

可逆过程设计

  • 设计了一定压可逆过程,用于计算定压下的焓变(ΔH)和熵变(ΔS)
  • 过程中,焓变和熵变的计算公式分别为:
    • ΔH(333K) = ΔH(373K) + ∫ΔCp,m dT
    • ΔS(333K) = ΔS(373K) + ∫ΔCp,m dT / T

热力学关系

  • 应用基尔霍夫方程,计算得出:
    • ΔH(333K) = 42.34 kJ
    • ΔS(333K) = 113.7 J·K⁻¹
  • 可以计算出熵变ΔS和焓变ΔH之间的关系:
    • ΔS = Q / T = 127.1 J·K⁻¹

物理参数

  • H2O(l, 60°C, p)到H2O(g, 60°C, py)的焓变:ΔvapHmy = 40.67 kJ
  • Cp,m,l 和 Cp,m,g 的值分别为:33.57 J·K⁻¹·mol⁻¹ 和 75.20 J·K⁻¹·mol⁻¹

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Description

测验热力学中的定压可逆过程,涉及焓和熵的变化。计算焓和熵的变化值。

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