Precalculus Study Notes on Exponents and Inequalities

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Questions and Answers

The negative exponent rule states that a^{-n} = \frac{1}{a^______}

n

For the absolute value inequality |x| < a, the solution is -a < x < ______

a

To factor a cubic polynomial like ax^3 + bx^2 + cx + d, one possible method is ______ by grouping.

factoring

In the example x^3 - 3x^2 - 4x + 12, it factors to (x - 2)(x^2 - x - ______).

<p>6</p> Signup and view all the answers

When simplifying complex fractions, the first step is to find a common ______ for all fractions involved.

<p>denominator</p> Signup and view all the answers

For the absolute value inequality |x| > a, the solutions are x < -a or x > ______.

<p>a</p> Signup and view all the answers

To simplify the fraction \frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}}, combine the numerator to get ______.

<p>5/6</p> Signup and view all the answers

Using synthetic division can help to find ______ and factor cubic polynomials.

<p>roots</p> Signup and view all the answers

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Study Notes

Precalculus Study Notes

Factoring Negative Exponents

  • Negative Exponent Rule: ( a^{-n} = \frac{1}{a^n} )
  • Basic Steps:
    1. Convert negative exponents to fractions.
    2. Simplify fractions if necessary.
    3. Combine like terms and express in standard form.
  • Example: ( x^{-2} = \frac{1}{x^2} )

Absolute Value Inequalities

  • Definition: An inequality involving the absolute value of a variable.
  • Types:
    1. Linear Inequalities: ( |x| < a ) or ( |x| > a ).
    2. Solutions:
      • For ( |x| < a ): ( -a < x < a )
      • For ( |x| > a ): ( x < -a ) or ( x > a )
  • Graphical Interpretation:
    • Represents distances on a number line.
    • Solutions can be visualized as segments or rays.

Factoring Cubics

  • General Form: ( ax^3 + bx^2 + cx + d )
  • Methods:
    1. Factoring by Grouping: Group terms and factor common factors.
    2. Synthetic Division: Use to find roots and factor.
    3. Rational Root Theorem: Test possible rational roots.
  • Example:
    • For ( x^3 - 3x^2 - 4x + 12 ):
      • Factor to ( (x - 2)(x^2 - x - 6) )
      • Further factor ( (x - 2)(x - 3)(x + 2) )

Simplifying Complex Fractions

  • Definition: A fraction where the numerator, denominator, or both are also fractions.
  • Steps to Simplify:
    1. Find a common denominator for all fractions involved.
    2. Combine fractions into a single fraction for both the numerator and denominator.
    3. Simplify the resulting fraction if possible.
  • Example:
    • Simplifying ( \frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}} ):
      • Combine numerator: (\frac{3}{6} + \frac{2}{6} = \frac{5}{6})
      • Rewrite: ( \frac{\frac{5}{6}}{\frac{1}{4}} = \frac{5}{6} \times 4 = \frac{20}{6} = \frac{10}{3} )

Factoring Negative Exponents

  • Negative exponent indicates the reciprocal, following the rule ( a^{-n} = \frac{1}{a^n} ).
  • Converting negative exponents to fractions simplifies expressions.
  • Example: The expression ( x^{-2} ) can be rewritten as ( \frac{1}{x^2} ).

Absolute Value Inequalities

  • Absolute value inequalities express the distance from zero on a number line.
  • Types include:
    • Linear inequalities of the form ( |x| < a ) or ( |x| > a ).
  • Solution for ( |x| < a ) yields ( -a < x < a ).
  • Solution for ( |x| > a ) results in two conditions: ( x < -a ) or ( x > a ).
  • Graphically represented as segments (for ( < )) or rays (for ( > )) on a number line.

Factoring Cubics

  • Cubic polynomials typically take the form ( ax^3 + bx^2 + cx + d ).
  • Common methods of factoring include:
    • Factoring by grouping to extract common factors from grouped terms.
    • Using synthetic division to find roots which helps in factoring the polynomial.
    • The Rational Root Theorem assists in testing potential rational roots.
  • Example: The cubic ( x^3 - 3x^2 - 4x + 12 ) factors into ( (x - 2)(x^2 - x - 6) ), which can be further factored into ( (x - 2)(x - 3)(x + 2) ).

Simplifying Complex Fractions

  • A complex fraction is one where the numerator, denominator, or both are fractions themselves.
  • Steps to simplify:
    • Identify a common denominator for all constituent fractions.
    • Combine fractions in both the numerator and denominator into a single fraction.
    • Simplify the resulting fraction if possible.
  • Example: To simplify ( \frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}} ), combine terms in the numerator to obtain ( \frac{5}{6} ), then compute ( \frac{\frac{5}{6}}{\frac{1}{4}} = \frac{5}{6} \times 4 = \frac{20}{6} = \frac{10}{3} ).

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