Pre-AP Chemistry Solutions
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Questions and Answers

What type of solution is created when 100g of NH3 is dissolved in 150 mL of water at 25°C, and how do you know?

A basic solution, as NH3 is a base. This is known because NH3 is a weak base and accepts H+ ions, increasing the pH of the solution.

What is the purpose of cooling a saturated solution of KNO3 from 65°C to 35°C, and what will happen as a result?

The purpose is to create a supersaturated solution. As a result, precipitate will form as the solubility of KNO3 decreases with decreasing temperature.

What is the relationship between pH and pOH in a solution, and why is it significant?

pH + pOH = 14, which is significant because it allows us to calculate one value if the other is known, as they are inversely related.

What is the conjugate acid-base pair in the reaction HBr(aq) + H2O(l) -> H3O(aq) + Br(aq), and what does this imply?

<p>The conjugate acid-base pair is H3O+/Br-, implying that HBr is a strong acid and completely dissociates in water.</p> Signup and view all the answers

What is the purpose of titration in calculating the concentration of an acid or base, and how is it achieved?

<p>The purpose of titration is to determine the concentration of an acid or base by reacting it with a known volume and concentration of a strong acid or base.</p> Signup and view all the answers

A student needs to prepare 250.0 mL of a 0.050 M solution of potassium phosphate. Describe the procedure to prepare this solution from a 5.00 M stock solution, specifying the volume of the stock solution required.

<p>To prepare 250.0 mL of a 0.050 M solution of potassium phosphate, the student needs to dilute the 5.00 M stock solution. The volume of the stock solution required can be calculated as follows: volume of stock solution = (desired volume) x (desired concentration) / (stock concentration) = 250.0 mL x 0.050 M / 5.00 M = 2.50 mL. Therefore, the student needs to take 2.50 mL of the 5.00 M stock solution and dilute it with water to a final volume of 250.0 mL.</p> Signup and view all the answers

In the reaction HNO2(aq) + H2O(l) -> H3O(aq) + NO2(aq), what are the conjugate acid-base pairs?

<p>The conjugate acid-base pairs are HNO2 (acid) and NO2- (conjugate base), and H3O+ (conjugate acid) and H2O (base).</p> Signup and view all the answers

A solution of HBr is created by dissolving 120g into 150 mL of water at 25°C. What type of solution is this and how do you know?

<p>This is a saturated solution. The student knows this because the amount of HBr dissolved is greater than the solubility of HBr in water at 25°C.</p> Signup and view all the answers

A saturated solution of KOH is made with 1.75L of water at 85°C and cooled to 35°C. Assuming a supersaturated solution is not created, how much precipitate will form?

<p>To find the amount of precipitate, the student needs to find the solubility of KOH at 35°C and subtract it from the initial amount of KOH dissolved at 85°C. The difference will be the amount of precipitate formed.</p> Signup and view all the answers

What mass of Ca(OH)2 would be required to make 305 mL of a 0.66M solution?

<p>The student needs to calculate the number of moles of Ca(OH)2 required and then multiply it by the molar mass of Ca(OH)2. moles = (volume) x (concentration) = 0.305 L x 0.66 M = 0.201 mol. mass = moles x molar mass = 0.201 mol x 74.1 g/mol = 14.9 g.</p> Signup and view all the answers

Study Notes

Pre-ap Solutions

  • pH is calculated as -log[H+]
  • pOH is calculated as -log[OH-]
  • pH + pOH = 14

Solutions and Stoichiometry

  • A solution of NH3 created by dissolving 100g into 150 mL of water at 25°C is an unsaturated solution.
  • A saturated solution of KNO3 made with 1.75L of water at 65°C and cooled to 35°C will form precipitate.
  • To make a saturated solution of ammonium chloride, the student needs to add a certain amount of ammonium chloride to 220 mL of water at 30°C with a concentration of 0.45g/mL.
  • To make 302 mL of 0.66M K2SO4 solution, a certain mass of K2SO4 is required.

Stoichiometry Solutions

  • To completely neutralize 45.65μL of sulfuric acid, a certain volume of 0.889mM magnesium hydroxide is required.
  • The resulting solution will have a certain molar concentration of magnesium sulfate.
  • To make 125.0mL of a 25.0mM solution of sodium phosphate, the student needs to dilute a certain amount of 7.00M stock solution.
  • HBr(aq) and H3O(aq) are conjugate acid/base pairs.
  • To titrate 25.0 mL of a solution containing H3PO4, a certain volume of 0.500 M NaOH is required.
  • To neutralize 50.0 mL of 0.45 M hydrobromic acid, a certain volume of 0.750M potassium hydroxide is required.

Stoichiometry Solutions (continued)

  • To completely neutralize 30.5 μL of hydrochloric acid, a certain volume of 1.25 mM calcium hydroxide is required.
  • The resulting solution will have a certain molar concentration of aluminum sulfate.
  • To make 150.0mL of a 30.0mM solution of potassium phosphate, the student needs to dilute a certain amount of 5.00M stock solution.
  • HNO2(aq) and H3O(aq) are conjugate acid/base pairs.
  • To titrate 35.0 mL of a solution containing H2SO4, a certain volume of 0.750 M KOH is required.
  • To neutralize 60.0 mL of 0.60 M hydroiodic acid, a certain volume of 1.0M sodium hydroxide is required.

Solubility and Saturation

  • A solution of HBr created by dissolving 120g into 150 mL of water at 25°C is an unsaturated solution.
  • A saturated solution of KOH made with 1.75L of water at 85°C and cooled to 35°C will form precipitate.
  • To make a saturated solution of lithium chloride, the student needs to add a certain amount of lithium chloride to 220 mL of water at 30°C with a concentration of 0.55g/mL.
  • To make 305 mL of 0.66M Ca(OH)2 solution, a certain mass of Ca(OH)2 is required.
  • To make a certain volume of 1.5 M glucose solution, a certain mass of glucose is required.
  • To combust 360mL of a 1.5M solution of sucrose, a certain mass of oxygen is required.

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Description

Quiz on chemistry solutions, including types of solutions, dissolving, concentration, and precipitation. Problems involve calculating concentrations, precipitates, and solution properties.

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