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Physics on Banked Roads Quiz

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On a banked road, what primarily provides the centripetal force necessary for a car to move in a circular path?

The horizontal component of the normal force. (correct)

The frictional force acting parallel to the road.

The normal force's vertical component.

The car's weight acting vertically downwards.

Which equation represents the balance of vertical forces acting on a car on a banked road?

N sin θ + f cos θ = mv²/R

N sin θ + f sin θ = mv²/R

N cos θ = mg - f sin θ

N cos θ = mg + f sin θ (correct)

What forces contribute to the horizontal force in the equation: N sin θ + f cos θ = mv²/R?

The car's weight only.

Weight and normal force.

The horizontal components of normal and frictional forces. (correct)

Only the frictional force.

In the case of a level road, what is the main difference in the force equation compared to a banked road?

<p>The angle of banking is considered zero degrees.</p> Signup and view all the answers

Given that 'm' represents mass, 'v' represents velocity, and 'R' represents the radius of the circular path, what does 'mv²/R' represent in the equations?

<p>The centripetal force.</p> Signup and view all the answers

Physics on Banked Roads Quiz

Choose a study mode

Podcast

Questions and Answers

On a banked road, what primarily provides the centripetal force necessary for a car to move in a circular path?

Which equation represents the balance of vertical forces acting on a car on a banked road?

What forces contribute to the horizontal force in the equation: N sin θ + f cos θ = mv²/R?

In the case of a level road, what is the main difference in the force equation compared to a banked road?

Given that 'm' represents mass, 'v' represents velocity, and 'R' represents the radius of the circular path, what does 'mv²/R' represent in the equations?

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