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What is the bank angle in a banked turn?
What is the bank angle in a banked turn?
- The angle at which the vehicle is inclined about its transverse axis with respect to the horizontal
- The angle at which the vehicle is inclined about its vertical axis with respect to the lateral
- The angle at which the vehicle is inclined about its longitudinal axis with respect to the horizontal (correct)
- The angle at which the vehicle is inclined about its lateral axis with respect to the vertical
What is the relationship between the centripetal force and friction in a banked turn?
What is the relationship between the centripetal force and friction in a banked turn?
- Friction must be large enough to provide the centripetal force, expressed as $μmg > \frac{mv^2}{r}$ (correct)
- Friction must be less than the centripetal force, expressed as $μmg < \frac{mv^2}{r}$
- Friction is unrelated to the centripetal force in a banked turn
- Friction is the only force providing the centripetal force in a banked turn
What happens if the bank angle is zero in a turn on flat surfaces?
What happens if the bank angle is zero in a turn on flat surfaces?
- The vehicle will tilt to the outside of the turn
- The vehicle will skid off the path due to lack of centripetal force
- The vehicle will experience a higher centripetal force
- The surface is flat and the normal force is vertically upward, and the only force keeping the vehicle turning is friction (correct)
What is the force required to turn the vehicle in a banked turn?
What is the force required to turn the vehicle in a banked turn?
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What does the expression $μmg > \frac{mv^2}{r}$ represent in a banked turn?
What does the expression $μmg > \frac{mv^2}{r}$ represent in a banked turn?
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