Physics Motion in a Straight Line

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Questions and Answers

An iron ball and a wooden ball of the same radius are released from a height H in a vacuum. Which statement is correct about the times taken for them to reach the ground?

  • The times will be in the inverse ratio of their diameters.
  • The wooden ball will reach the ground first.
  • They will reach the ground at the same time. (correct)
  • The iron ball will reach the ground first.

A stone is dropped from a bridge and takes 2 seconds to reach the water. Given that g = 9.8 m/s², what is the height of the bridge above the water?

  • 19.6 m (correct)
  • 4.9 m
  • 21.4 m
  • 9.8 m

An object is dropped. What is its velocity after 5 seconds, assuming the acceleration due to gravity is 10 m/s²?

50 m/s

The time it takes for an object to fall a certain distance is directly proportional to the square of the distance.

<p>False (B)</p> Signup and view all the answers

If an object is dropped from a height of 80 meters, the time of flight is ______ seconds, given that g = 10 m/s².

<p>4</p> Signup and view all the answers

A body is projected vertically upwards with a velocity u and returns to the starting point in 4 seconds. Assuming g = 10 m/s², the value of u is:

<p>20 m/s (C)</p> Signup and view all the answers

A stone is dropped from the top of a tower. Its speed after it has fallen 20 m is [Take g = 10 ms⁻²]

<p>20 ms⁻¹ (D)</p> Signup and view all the answers

Match the following scenarios with the correct time to hit the ground when dropped from the given height:

<p>80 meters with g=10 m/s² = 4 seconds 45 meters with g=10 m/s² = 3 seconds 20 meters with g=10 m/s² = 2 seconds 5 meters with g=10 m/s² = 1 second</p> Signup and view all the answers

Flashcards

Free Fall in a Vacuum

The time taken for an object to fall from a height is independent of its mass in a vacuum. This is because acceleration due to gravity is constant for all objects, regardless of their mass.

Calculating Bridge Height

The height of a bridge can be calculated using the time it takes for an object to fall from the bridge to the water below. The formula for the distance fallen is: distance = 1/2 * g * t^2, where g is the acceleration due to gravity (9.8 m/s²) and t is the time taken.

Velocity after Falling a Distance

The velocity of a freely falling object after falling a certain distance is directly proportional to the square root of the distance fallen. This is because the object's velocity increases linearly with time, and the distance fallen is proportional to the square of time.

Free Fall Velocity

When an object is dropped, its velocity increases linearly with time due to the acceleration due to gravity (g). The formula for velocity after time t is: velocity = g * t, where g = 9.8 m/s².

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Time to Fall Half the Distance

The time taken for a freely falling object to cover the first half of its total height is equal to the square root of 2 multiplied by the time taken to cover the second half. This can be derived from the equations of motion for constant acceleration.

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Time of Flight for Vertical Projectile

The time taken for an object projected vertically upward to return to its starting point is twice the time taken to reach its maximum height.

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Displacement in nth Second

The displacement of a freely falling object in a particular second is equal to the sum of the object's initial velocity and half the acceleration due to gravity multiplied by the time interval. This can be calculated using the equation of motion: displacement = initial velocity * time + 1/2 * g * time^2

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Final Velocity of Dropped Object

The velocity of an object at which it hits the ground after being dropped from a height is determined by the acceleration due to gravity and the height of the drop. The formula for final velocity is: velocity^2 = 2 * g * height, where g = 9.8 m/s²

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Study Notes

Motion in a Straight Line

  • Q1: Iron and wooden balls of same radius, dropped from same height in vacuum, reach the ground in equal time.

  • Q2: A stone dropped from a bridge takes 2 seconds to hit the water. The height of the bridge is 19.6 meters (using g = 9.8 m/s²).

  • Q3: A stone dropped from a tower, after falling 20 meters, has a speed of 20 m/s (using g = 10 m/s²).

  • Q4: The ratio of times taken by two bodies of different masses to fall through different distances depends on the distances (a and b). It's equal to √a/√b.

  • Q5: The time taken to cover the first half of a falling body's height is calculated by √((time to cover the full height)/2).

  • Q6: A body projected upward with a velocity 'u', returning to the starting point after 4 seconds (with g = 10 m/s²) means initial velocity was 20 m/s.

  • Q7: An object dropped takes 5 seconds to reach a certain velocity which is 50 m/s.

  • Q8: The displacement of a dropped object in the 4th second is 28 meters.

  • Q9: If an object is dropped from a height of 80 meters, its time of flight is 4 seconds.

  • Q10: The second drop is 3.75m above the ground while the first drop hits the ground.

  • Q11: A body falling from a tower takes the last 2 seconds to fall 40 meters. The height of the tower is accordingly 80 meters.

  • Q12: A boy drops a stone from a 20-meter tower. The velocity of the stone hitting the ground is 20 m/s (using g =10 m/s²).

  • Q13: A ball is dropped and another thrown. They both drop from the same platform. The time is 6 seconds.

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