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Physics Momentum Problem

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Questions and Answers

What is the x-component of the momentum for a 3 kg particle moving with a velocity of (3i - 4j) m/s?

-12 kg·m/s

3 kg·m/s

-4 kg·m/s

9 kg·m/s (correct)

How do you calculate the magnitude of the total momentum for a particle with momentum components $P_x = 9$ and $P_y = -12$?

$9 - 12$

$\sqrt{(9)^2 + (-12)^2}$ (correct)

$\sqrt{(9) + (-12)}$

$9 + (-12)$

What is the magnitude of the momentum for a block of mass 2 kg moving with a velocity of (2i - j + 3k) m/s?

$\sqrt{13}$ kg·m/s

$2 \sqrt{14}$ kg·m/s (correct)

$\sqrt{44}$ kg·m/s

$2 \sqrt{13}$ kg·m/s

For a block of mass 2 kg moving with a velocity of (2i - j + 3k) m/s, in what direction relative to the x-axis is its momentum?

<p>$\theta = \tan^{-1}(\sqrt{14}/6)$</p> Signup and view all the answers

What is the magnitude of the momentum of a 1500 kg car traveling at a constant speed of 12 m/s?

<p>18000 kg·m/s</p> Signup and view all the answers

Study Notes

Momentum of a Particle

A particle with mass 3 kg has a velocity of (3i - 4j) m/s, resulting in a momentum of 9i - 12j.
The x and y components of momentum are Px = 9 and Py = -12, respectively.
The magnitude of the total momentum is p = √(Px² + Py²) = √(9² + (-12)²) = 15 kg.m/s.

Momentum of a Block

A block with a mass of 2 kg has a velocity of 2i - j + 3k m/s, resulting in a momentum of 2ui - 2j + 6k.
The magnitude of the momentum is p = √(Px² + Py² + Pz²) = √(4 + 4 + 36) = 2√14 kg.m/s.
The direction of the momentum is θ = tan⁻¹(√14/6) with respect to the x-axis.

Momentum of a Car

A car with a mass of 1500 kg is traveling at a constant speed of 12 m/s.

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Description

Solve physics problems involving momentum, velocity, and mass. Find the x and y components of momentum and the magnitude of total momentum.