Physics: Momentum, Energy, Forces, and Curved Motion
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Questions and Answers

In a perfectly elastic collision between two objects, what is conserved and what equation describes this conservation principle?

In a perfectly elastic collision, momentum is conserved. The conservation of momentum is described by the equation: $m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2$, where $m_1$ and $m_2$ are the masses, $u_1$ and $u_2$ are the initial velocities, and $v_1$ and $v_2$ are the final velocities of the two objects.

A block is released from rest at the top of an inclined plane. If friction is negligible, what is the relationship between the initial potential energy and the final kinetic energy of the block at the bottom of the incline?

If friction is negligible, the initial potential energy of the block at the top of the incline is equal to the final kinetic energy of the block at the bottom of the incline. This is due to the conservation of mechanical energy.

A box is being pushed across a rough horizontal surface with a constant applied force. If the coefficient of kinetic friction remains constant, how does the acceleration of the box change as its speed increases?

If the coefficient of kinetic friction remains constant, the acceleration of the box will remain constant as its speed increases. The acceleration is determined by the net force, which is the applied force minus the constant kinetic friction force.

A satellite is orbiting the Earth in a circular orbit. Derive an expression for the kinetic energy of the satellite in terms of its mass, velocity, and the radius of its orbit.

<p>The kinetic energy of a satellite in a circular orbit is given by $K = \frac{1}{2}mv^2$, where $m$ is the mass of the satellite and $v$ is its orbital speed. Using the expression for centripetal acceleration, $v^2 = \frac{GM}{r}$, where $G$ is the gravitational constant, $M$ is the mass of the Earth, and $r$ is the radius of the orbit, we can substitute for $v$ to get $K = \frac{1}{2}m\left(\frac{GM}{r}\right)$.</p> Signup and view all the answers

A particle is moving in a circular path with a constant speed. Explain how the particle's kinetic energy and centripetal acceleration are related, and why the centripetal force must be constantly changing.

<p>For a particle moving in a circular path with constant speed, the kinetic energy remains constant. However, the direction of the velocity vector is constantly changing, which means that the centripetal acceleration is also constantly changing in direction. The centripetal force, which provides the centripetal acceleration, must also change in direction continuously to keep the particle moving in a circular path.</p> Signup and view all the answers

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