Physics Fundamentals: Motion, Energy, and Momentum
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A rock is thrown upwards from the ground with an initial velocity of 20 m/s. If the acceleration due to gravity is 9.8 m/s², how long will it take for the rock to reach its maximum height? Assume the rock starts from rest.

Using the equation of motion v = u + at, we can find the time it takes for the rock to reach its maximum height, where v = 0 m/s. Solving for t, we get t = u / a = 20 m/s / 9.8 m/s² = 2.04 s.

A car travels horizontally at a constant velocity of 30 m/s. If the car travels for 10 seconds, how far will it have traveled?

Using the equation of motion s = vt, we can find the distance traveled by the car. Substituting the values, we get s = vt = 30 m/s × 10 s = 300 m.

A baseball is thrown with an initial velocity of 25 m/s at an angle of 30° to the horizontal. If the acceleration due to gravity is 9.8 m/s², find the range of the baseball. Assume the ball starts from the ground.

Using the equation for range R = (u² sin 2θ) / g, we can find the range of the baseball. Substituting the values, we get R = (25² sin 2(30°)) / 9.8 m/s² = 55.4 m.

A 2 kg block is moving at a velocity of 5 m/s. If it collides with a 3 kg block at rest, what is the resulting velocity of the system if the collision is elastic?

<p>Using the principle of conservation of momentum, we can find the resulting velocity of the system. The total momentum before the collision is p₁ = 2 kg × 5 m/s = 10 kg m/s. After the collision, the total momentum is conserved, and the resulting velocity is v = p₁ / (m₁ + m₂) = 10 kg m/s / (2 kg + 3 kg) = 2 m/s.</p> Signup and view all the answers

A 10 kg block is lifted 2 m vertically upwards. If the gravitational acceleration is 9.8 m/s², what is the increase in potential energy of the block?

<p>Using the equation for potential energy ΔU = mgh, we can find the increase in potential energy of the block. Substituting the values, we get ΔU = 10 kg × 9.8 m/s² × 2 m = 196 J.</p> Signup and view all the answers

A body is projected upwards from the ground with an initial velocity of 15 m/s. If the acceleration due to gravity is 9.8 m/s², what is the velocity of the body when it reaches a height of 10 m?

<p>Using v² = u² + 2as, where v = final velocity, u = initial velocity, a = acceleration, s = displacement. v² = 15² + 2(-9.8)(10) = 0, hence v = 0 m/s.</p> Signup and view all the answers

A projectile is fired at an angle of 45° to the horizontal with an initial velocity of 20 m/s. If the acceleration due to gravity is 9.8 m/s², find the horizontal component of its velocity when it reaches the ground.

<p>Resolve the initial velocity into horizontal and vertical components. The horizontal component is given by ucos(45°) = 20cos(45°) = 14.14 m/s. Since the horizontal component remains constant, the horizontal velocity when it reaches the ground is still 14.14 m/s.</p> Signup and view all the answers

A force of 10 N is applied to a 5 kg block for 2 seconds. If the block is initially at rest, what is its resulting velocity?

<p>Using the impulse-momentum theorem, Δp = FΔt, where Δp = change in momentum, F = force, Δt = time. Δp = 10(2) = 20 kgm/s. Since the block is initially at rest, the resulting momentum is equal to the change in momentum. Hence, mv = 20, where m = 5 kg. Solving for v, we get v = 4 m/s.</p> Signup and view all the answers

A 2 kg block is moving at a velocity of 3 m/s when it collides with a stationary 1 kg block. If the collision is inelastic, what is the resulting velocity of the combined system?

<p>Momentum is conserved in a closed system. Initial momentum = 2(3) = 6 kgm/s. Let the final velocity be v. Then, 6 = (2 + 1)v, v = 6/3 = 2 m/s.</p> Signup and view all the answers

A motor lifts a 50 kg box to a height of 5 m in 10 seconds. If the efficiency of the motor is 80%, what is the power output of the motor?

<p>Work done = mgh = 50(9.8)(5) = 2450 J. Power = work done / time = 2450/10 = 245 W. Since the efficiency is 80%, the power output of the motor = 245/0.8 = 306.25 W.</p> Signup and view all the answers

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