Parallel and Serial Mean Processing Time Quiz
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Questions and Answers

What is the mean processing time for parallel links?

  • It is the mean of the processing time over all parallel links divided by the sum of the parallel probabilities (correct)
  • It is the sum of the processing times over all parallel links
  • It is the sum of the parallel probabilities
  • It is the mean of the processing time over all parallel links multiplied by the sum of the parallel probabilities

    • How is the serial term defined?

  • The sum of the two processing times over all nodes (correct)
  • The mean processing time over all serial links
  • The sum of two random variables
  • The sum of the two processing times over all parallel links

    • What does the loop contribution depend on?

  • The probability of looping and the total number of loops (correct)
  • The number of links in the loop
  • The processing time needed for each loop
  • The total processing time minus the loop time

    • How is the loop contribution calculated when expected to loop N times?

    <p>$N$</p> Signup and view all the answers

    If a routine loops N times, each loop taking TL seconds and then TA seconds are spent outside the loop, what is the total mean time through the process?

    <p>$TA + NTL$</p> Signup and view all the answers

    What is the parallel term in the context of processing time?

    <p>Mean of the processing time over all parallel links</p> Signup and view all the answers

    How is the serial term defined?

    <p>Intuitively obvious as the sum of two processing times</p> Signup and view all the answers

    What does the PL/(1 - PL) term reduce to when substituting N/(N + 1) for the probability of looping?

    <p>N</p> Signup and view all the answers

    How is the loop contribution most simply understood?

    <p>By adding the link processing time and TA seconds</p> Signup and view all the answers

    In what way is the mean processing time for parallel links calculated?

    <p>(PL + 1)/(1 - PL)</p> Signup and view all the answers

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