Organic Chemistry: Carboxylic Amides Reduction
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Questions and Answers

What is the primary function of lithium aluminium hydride (LiAlH4) in organic transformations?

  • To hydrolyze amides into carboxylic acids
  • To perform electrophilic aromatic substitution
  • To oxidize alcohols to aldehydes
  • To reduce carbonyl groups to alcohols (correct)
  • In the reduction of β-aryl-α,β unsaturated carbonyl compounds, what is a key outcome when using LiAlH4?

  • Only the alkene functional group is reduced
  • Only the carbonyl functional group is reduced
  • The carbon-carbon double bond remains intact
  • Both the carbon-carbon double bond and the carbonyl group are reduced (correct)
  • Which type of compound is formed when propargylic alcohols (R–C≡C–CH2OH) are reduced using lithium aluminium hydride?

  • Dienes
  • Saturated alcohols
  • Trans alkenes (correct)
  • Aldehydes
  • How does the mechanism of reduction using lithium aluminium hydride primarily occur?

    <p>By nucleophilic attack of hydride on the carbonyl carbon</p> Signup and view all the answers

    Which of the following is NOT a common application of lithium aluminium hydride in organic chemistry?

    <p>Reduction of alkenes to alkanes</p> Signup and view all the answers

    What is the primary effect of adding AlCl3 to LiAlH4 in a mixed lithium aluminium hydride-aluminium chloride reagent?

    <p>It lowers the reducing power of LiAlH4.</p> Signup and view all the answers

    Which reaction product is formed when LiAlH4 reacts with 3AlCl3?

    <p>LiCl and 4AlHCl2</p> Signup and view all the answers

    What can be inferred about the reducing ability of mixed lithium aluminium hydride-aluminium chloride compared to LiAlH4 alone?

    <p>The mixed hydride exhibits reduced reducing abilities.</p> Signup and view all the answers

    In the context of nucleophilic attack, how does LiAlH4 primarily function?

    <p>As a strong nucleophile capable of attacking electrophiles.</p> Signup and view all the answers

    Which functional group is readily reduced by lithium aluminium hydride?

    <p>Carboxylic acids</p> Signup and view all the answers

    Study Notes

    Carboxylic Amides Reduction

    • Carboxylic amides can be converted into amines or aldehydes through reduction.
    • Lithium aluminium hydride (LiAlH4) is commonly used as the reducing agent, often in tetrahydrofuran (THF) at low temperatures.

    Alkene and Carbonyl Compound Reduction

    • Reducing β-aryl-α,β unsaturated carbonyl compounds using LiAlH4 results in the reduction of both the carbonyl group and carbon-carbon double bond.
    • Various conditions like temperature adjustments (e.g., -10ºC or 35ºC) can influence the reduction process, with alternative reagents like sodium borohydride (NaBH4) or DIBAL-H also applicable.

    Propargylic Alcohol Reduction

    • Propargylic alcohols are reduced with LiAlH4 to yield trans alkenes.
    • A mixed lithium aluminium hydride-aluminium chloride reagent can form, altering the reducing power of LiAlH4.

    Mixed Hydride Reagent Reactions

    • Formations like LiAlH3 and other mixed hydrides occur with AlCl3, affecting the reactivity of reducing agents.
    • For example, the addition of AlCl3 can decrease LiAlH4's ability to reduce functional groups compared to its standalone use.

    Lithium Tri-t-butoxyaluminium Hydride

    • Lithium tri-t-butoxyaluminium hydride ([LiAlH(OtBu)3]) is a milder reducing agent than LiAlH4.
    • This reagent can reduce various functional groups, with specific outcomes:
      • Aldehydes and ketones reduce to alcohols.
      • Carboxylic esters, epoxides react slowly.
      • Halides, nitriles, and nitro groups typically are not reduced.

    Preparation of Lithium Tri-t-butoxyaluminium Hydride

    • [LiAlH(OtBu)3] is synthesized by reacting lithium aluminium hydride with tert-butyl alcohol, employing a stoichiometric relationship.

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    Description

    This quiz focuses on the conversion of carboxylic amides into amines and aldehydes using lithium aluminum hydride (LiAlH4) as a reducing agent. It tests your understanding of the necessary conditions and outcomes of this organic reaction. Ideal for students delving into organic chemistry mechanisms.

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