Mastering Advanced Trigonometry Concepts Quiz

$2 - 2\cos(A-B)$

$-\cot\theta$

$\cot\theta$

$\cos A\cos B - \sin A\sin B$

$-\sin\theta$

$cos(2(A-B)) = cos^2(A-B) - sin^2(A-B)

Using the identity $sin(-\theta) = -sin(\theta)$, we can rewrite it as $sin(-\theta) = -sin(\theta)$. Therefore, $sin(-\theta) = -sin(\theta)

The relationship between $tan(-\theta)$ and $cot(\theta)$ is given by the identity $tan(-\theta) = -cot(\theta)$. Therefore, $tan(-\theta) = -cot(\theta)

Using the identity $cos(A+B) = cos(A)cos(B) - sin(A)sin(B)$, we can rewrite it as $cos(A+B) = cos(A)cos(B) - sin(A)sin(B)$. Therefore, $cos(A+B) = cos(A)cos(B) - sin(A)sin(B)

The value of $d(PQ)$ in terms of $cos(A-B)$ is $d(PQ) = \sqrt{2 - 2cos(A-B)}